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Nairaland Forum / Nairaland / General / Education / Nairaland Mathematicians, Please Come And Help Me Solve This (1662 Views)
Mathematicians In The House come over Here / Mathematicians, Please Help Me With These Quadratic Equations / Nairaland Mathematicians And Physicists, Come And Try This. (2) (3) (4)
Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN: 4:36pm On Jan 16, 2023 |
Please I really need help with this. I just can't get to the answer and I don't know why 1 Share
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by don4real: 5:15pm On Jan 16, 2023 |
X=4 6 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Chaos14: 6:10pm On Jan 16, 2023 |
don4real:Wrong -4 |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by doggedemmy(m): 6:30pm On Jan 16, 2023 |
sqlPAIN: 2 Likes
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by steeltrust: 7:20pm On Jan 16, 2023 |
To solve this equation, we can start by multiplying both sides of the equation by x(x+2) to eliminate the fractions: 1/x + 1/2 = 3/x x(x+2) = (x+2) Next, we can distribute the x on the left side of the equation: x^2 + 2x = x + 2 Then, we can subtract x from both sides: x^2 + x = 2 Finally, we can subtract 2 from both sides: x^2 + x - 2 = 0 Now, we can factor the left side of the equation: (x-1)(x+2)=0 This gives us two solutions: x = 1 or x = -2 Hence the solutions are x = 1, and x = -2 2 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN: 7:31pm On Jan 16, 2023 |
Chaos14:the Answer is 4 bro 5 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN: 7:32pm On Jan 16, 2023 |
steeltrust:just solving absolute rubbish. only God knows where you dey get "^" from 10 Likes 1 Share |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by shox(m): 7:32pm On Jan 16, 2023 |
steeltrust: Wrong answers. X=4 1/4+ 1/2= 3/4. Making the equation right 3 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN: 7:38pm On Jan 16, 2023 |
[quote author=doggedemmy post=120095361][/quote] Thanks so much bro. Please in this your solution, can you explain why x(2+x) is equal to 2+x and not 2x+x^2 and also why 3(2x) equal to 6 and not 6x 1 Like
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by doggedemmy(m): 7:41pm On Jan 16, 2023 |
sqlPAIN: You can cancel the x from both sides since it’s a common factor. 2 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by ozonelayer79: 7:52pm On Jan 16, 2023 |
If that equation is correct then it means x has no solution because with the equation like that, what you have after solving it is x^2 (that is, x square ) = 4x In summary, x^2=4x X= square root of 4x. |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Googleus(m): 7:57pm On Jan 16, 2023 |
Solving Sl 1/x + 1/2 = 3/x To solve the equation 1/x + 1/2 = 3/x, we can start by multiplying both sides of the equation by the least common multiple of the denominators, which in this case is x. This gives us: x(1/x) + (x)(1/2) = (3)(x)/x Simplifying the left side of the equation by canceling out the x's on the numerator and denominator, we get: 1 + (x/2) = 3 We can then subtract x/2 from both sides of the equation: 1 = 3 - x/2 Multiply both sides by 2 to get rid of the fraction: 2 = 6 - x Finally, adding x to both sides of the equation: x = 6 - 2 x = 4 So the solution is x = 4. 2 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by doggedemmy(m): 8:04pm On Jan 16, 2023 |
ozonelayer79: If x2=4x, you can divide both sides by x and get x as 4. 1 Like |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by FromZeroToHero(m): 8:04pm On Jan 16, 2023 |
Very simple 4 Likes 1 Share
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by ozonelayer79: 8:13pm On Jan 16, 2023 |
doggedemmy:That is, x × x = 4 × x Which means X cancels out X which finally gives x = 4 That's very correct. |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by steeltrust: 8:15pm On Jan 16, 2023 |
sqlPAIN:that not nice You can correct me in a calm manner I’m not God who knows it all Atlist I made an attempt correct me where I’m wrong not shouting as we are enemies It not nice 9 Likes |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by NaijaphiliaBlog: 8:16pm On Jan 16, 2023 |
EQUATION: 1/X + 1/2 = 3/X SOLUTION: Since the right side of the equation is 3/X, let's multiply everything by X in order to cancel the X on the right side i.e. X(1/X + 1/2) = X(3/X) X/X + X/2 = 3X/X 1 + X/2 = 3 Lets move the 1 to the right side of the equation i.e. X/2 = 3 - 1 X/2 = 2 Let's finally multiply both sides by 2 i.e. 2(X/2) = 2(2) X = 4 QED 1 Like |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Spare124: 8:16pm On Jan 16, 2023 |
Please can you help with this
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Drrnie(m): 8:34pm On Jan 16, 2023 |
sqlPAIN:Bro leave that one... Na only God know where e get -4 from |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Edmaths: 8:51pm On Jan 16, 2023 |
steeltrust: Sorry about that. The equation has two answers: x = 0 or x = 4 1 Like |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Nobody: 8:59pm On Jan 16, 2023 |
Spare124:Example 1 6*5=30 30/2=15 How they got 15 15/5=3 3*2= 6 How they got 6 6*5=30 30/15=2 How they got 2 15*2=30 30/6=5 How they got 5 |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by don4real: 9:06pm On Jan 16, 2023 |
See confidence chai. You are the one that is wrong. Check the solving below Chaos14: |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by MIRACULOUS123(m): 9:22pm On Jan 16, 2023 |
Chaos14: Seems I'm the only one that understand you. I thought the first step before solving anything is to collect the like terms. 1/x +1/2=3/x Collect the like terms. 1/x -3/x=-1/2 Then finding the LCM. -2/x=-1/2 Lastly,cross multiply X=-4 |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sholey4love: 9:33pm On Jan 16, 2023 |
Here is the answer Just copy and paste this on Google 1/x+1/2=3/x
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Alusiizizi(m): 10:03pm On Jan 16, 2023 |
sqlPAIN: M0ron!! |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by jeromestarks: 10:27pm On Jan 16, 2023 |
Una no Sabi anything for this forum. 1/x +1/2 = 3/x Find LCM you have 2+3/2x = 3/x Cross multiply, you have 6x = x(2 + x) Opening the brackets, you have 6x = 2x + x^2 i.e x square Collecting like terms , you have 6x -2x = x^2 4x = x^2 X^2 -4x = 0 Factorise it and I get X (x -4) = 0 Divide both sides by x X (x - 4)/X = 0/x X - 4 = 0 X = 4 |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by TONYE001(m): 10:42pm On Jan 16, 2023 |
x = 4. 1 Like
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Goodlady(f): 10:58pm On Jan 16, 2023 |
sqlPAIN:The answer is 2. It's dark here I d v shown you my wokings. |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Awesome80(m): 11:59pm On Jan 16, 2023 |
Here's my own solution... The LCM of x, 2 and x in the equation: 1/X +1/2 = 3/X is 2X. Multiply through by 2x, i.e 1/X x 2X + 1/2 x 2X = 3/X x 2X Here a couple of things happen... 1. The X in 2X cancels out X in 1/X leaving you with 1 x 2 = 2. 2. The 2 in 2X cancels out 2 in 1/2 leaving you with 1 x X = X. 3. The X in 2X cancels out X in 3/X leaving you with 3 x 2 = 6. So we now have 2 + X = 6. After collecting like terms, we have X = 6 - 2 Therefore, X = 4. |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Bam17(f): 12:23am On Jan 17, 2023 |
4... like everyone got ![]() 1 Like 2 Shares
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Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Bam17(f): 12:26am On Jan 17, 2023 |
Spare124:Here, you multiply the first two, then divide by the 3rd to get the final answer. |
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Bam17(f): 12:28am On Jan 17, 2023 |
Spare124:To understand better. Modified: Then you start applying the steps to the rest of the sums ![]() 1 Share
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