I made the following IQ Quiz. It's not your regular brainteaser. Not even an MIT Graduate would get all.

Each question is worth #20k.
No trial limit. Guess as much as you want. The first to get a correct answer for a question, will be credited instantly....

Lets Go

Question 1

If TWO*FOUR*SIX = 1152.

Then THREE*FIVE*SEVEN = X.

1152 + X = Y.


1,11,21,1211,111221,312211,A.


A + Y = Z

Solve for Z

ANSWER

Some guys tried sha. Like i said it's not your regular brain teaser. Back to the answer.

The first part "TWO THREE FOUR FIVE SIX" are the numbers spelt out. And we know * is multiplication. Now this is where most people are missing it. Think outta the box.

2*4*6=1152

just square each number and multiply then divide by 2

(2^2)*(4^2)*(6^2)=2304 divide by 2 = 1152 (quantitative reasoning)

Following the steps above,

3*5*7=5512.5

X= 5512.5

Y= 1152 + X =6664.5

Next is A, most of you got A which is 13112221.

Z= A + Y =13118885.5

Modified: Time limit is 2hrs per question.

To solve this problem, we need to determine the numerical values of the letters in the equations and then solve for the unknowns.

Firstly, let's assign numerical values to the letters in the equations based on their positions in the alphabet:

A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10, K=11, L=12, M=13, N=14, O=15, P=16, Q=17, R=18, S=19, T=20, U=21, V=22, W=23, X=24, Y=25, Z=26

Using this encoding scheme, we can write the given equations as:

20 15 23 * 6 15 21 * 18 9 14 = 1152
20 18 5 5 14 * 6 9 22 * 19 5 22 5 14 = X

To solve for X, we can multiply the numerical values of the letters in the second equation:

X = 20 * 18 * 5 * 5 * 14 * 6 * 9 * 22 * 19 * 5 * 22 * 5 * 14 = 117964800

Next, we can add X and 1152 to get Y:

Y = X + 1152 = 117965952

Finally, we can decode the value of A as follows:

A = "one A" because it is written as "1"
"one A, one B" because the previous term has "one A"
"two A, one B" because the previous term has "one A, one B"
"one C, two A, two B" because the previous term has "two A, one B"
"three C, one A, two B" because the previous term has "one C, two A, two B"
"one D, three C, two A, one B" because the previous term has "three C, one A, two B"
Therefore, A = "one D, three C, two A, one B" and has a numerical value of 13221112.

Finally, we can add Y and A to get Z:

Z = Y + A = 117965952 + 13221112 = 131187064

Therefore, the value of Z is 131187064.

Westerhoffe:
To solve this problem, we need to determine the numerical values of the letters in the equations and then solve for the unknowns.

Firstly, let's assign numerical values to the letters in the equations based on their positions in the alphabet:

A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10, K=11, L=12, M=13, N=14, O=15, P=16, Q=17, R=18, S=19, T=20, U=21, V=22, W=23, X=24, Y=25, Z=26

Using this encoding scheme, we can write the given equations as:

20 15 23 * 6 15 21 * 18 9 14 = 1152
20 18 5 5 14 * 6 9 22 * 19 5 22 5 14 = X

To solve for X, we can multiply the numerical values of the letters in the second equation:

X = 20 * 18 * 5 * 5 * 14 * 6 * 9 * 22 * 19 * 5 * 22 * 5 * 14 = 117964800

Next, we can add X and 1152 to get Y:

Y = X + 1152 = 117965952

Finally, we can decode the value of A as follows:

A = "one A" because it is written as "1"
"one A, one B" because the previous term has "one A"
"two A, one B" because the previous term has "one A, one B"
"one C, two A, two B" because the previous term has "two A, one B"
"three C, one A, two B" because the previous term has "one C, two A, two B"
"one D, three C, two A, one B" because the previous term has "three C, one A, two B"
Therefore, A = "one D, three C, two A, one B" and has a numerical value of 13221112.

Finally, we can add Y and A to get Z:

Z = Y + A = 117965952 + 13221112 = 131187064

Therefore, the value of Z is 131187064.

This must be a copied answer

Next question please…
And you're currently owing me ₦20,000.00k

Westerhoffe:
Next question please…
And you're currently owing me ₦20,000.00k

Alt account

NOTORIOUS100:

This must be a copied answer

Oga Pay up and dish out the next question

NOTORIOUS100:

Alt account

Abi?

Westerhoffe, You are wrong partially. If we follow your values, that means the first equation will be wrong.

CHECK

If TWO*FOUR*SIX = 1152

Now as you assign values to those letters and multiply, it wont give you 1152 please check again

Please don't come here and be shouting alt account. And oga westeroffe dey slow down, your answer wrong. Check again

WhereMyLoud:
Oga Pay up and dish out the next question

abeg dey calm down...

H

MaDaRa01:
Please don't come here and be shouting alt account. And oga westeroffe dey slow down, your answer wrong. Check again

The pattern seems to be describing the sequence of numbers obtained by reading out loud the count of consecutive identical digits in each previous term, starting from 1.

The first term is "1", as there is a single 1.
The second term is "11", as there are two 1s in the previous term.
The third term is "21", as there is one 2 followed by one 1 in the previous term.
The fourth term is "1211", as there is one 1 followed by one 2 followed by two 1s in the previous term.
The fifth term is "111221", as there are three 1s followed by two 2s followed by one 1 in the previous term.
The sixth term is "312211", as there are one 3 followed by one 1 followed by two 2s followed by two 1s in the previous term.
To solve the problem:

TWOFOURSIX = 1152, which means that TWO has a value of 3, FOUR has a value of 6, and SIX has a value of 8.

THREEFIVESEVEN = X, which means that THREE has a value of 5, FIVE has a value of 4, and SEVEN has a value of 6. Therefore, X = 546 = 120.

1152 + X = 1272.

The next term in the sequence is "13112221", as there is one 1 followed by three 3s followed by two 1s followed by two 2s followed by one 1 in the previous term.

A + Y = Z, where A = "13112221", and Y = 1272. Therefore, Z = A + Y = "131135493"

MaDaRa01:
abeg dey calm down...

so the new pattern na to ask bulala question ,like say u get any razza , take person past time, una don cast, if u like , call this a stupid reply, na to face front,oya see road, u know say me no dey see joy , make we no burst for street, who dey ask say wetin i dey talk? dey play ,as dem neva set line 4 ground, dey play.

The 20k,, na cash or transfer

Please confirm my answer. What number can i forward my accout no. to sir

NOTORIOUS100:

Alt account

Not ALT account.
It's CTL account.
Or even Windows account.

Westerhoffe:
To solve this problem, we need to determine the numerical values of the letters in the equations and then solve for the unknowns.

Firstly, let's assign numerical values to the letters in the equations based on their positions in the alphabet:

A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10, K=11, L=12, M=13, N=14, O=15, P=16, Q=17, R=18, S=19, T=20, U=21, V=22, W=23, X=24, Y=25, Z=26

Using this encoding scheme, we can write the given equations as:

20 15 23 * 6 15 21 * 18 9 14 = 1152
20 18 5 5 14 * 6 9 22 * 19 5 22 5 14 = X

To solve for X, we can multiply the numerical values of the letters in the second equation:

X = 20 * 18 * 5 * 5 * 14 * 6 * 9 * 22 * 19 * 5 * 22 * 5 * 14 = 117964800

Next, we can add X and 1152 to get Y:

Y = X + 1152 = 117965952

Finally, we can decode the value of A as follows:

A = "one A" because it is written as "1"
"one A, one B" because the previous term has "one A"
"two A, one B" because the previous term has "one A, one B"
"one C, two A, two B" because the previous term has "two A, one B"
"three C, one A, two B" because the previous term has "one C, two A, two B"
"one D, three C, two A, one B" because the previous term has "three C, one A, two B"
Therefore, A = "one D, three C, two A, one B" and has a numerical value of 13221112.

Finally, we can add Y and A to get Z:

Z = Y + A = 117965952 + 13221112 = 131187064

Therefore, the value of Z is 131187064.

this is a look and say sequence so the answer is; 1113213211

MaDaRa01:
I made the following IQ Quiz. It's not your regular brainteaser. Not even an MIT Graduate would get all.

Each question is worth #20k.
No trial limit. Guess as much as you want. The first to get a correct answer for a question, will be credited instantly....

Lets Go

Question 1



Modified: Time limit is 2hrs per question.

this is a look and say sequence na..Bleep all this long talk cause the answer is :1113213211..boss
Because A would be:13112221

OK.

Let's start by breaking down the given multiplication into individual factors:

TWO = 2
FOUR = 4
SIX = 6

So, TWOFOURSIX = 246 = 48

Now, let's find the value of THREEFIVESEVEN:

Similarly, breaking down the given multiplication into individual factors:

THREE = 3
FIVE = 5
SEVEN = 7

So, THREEFIVESEVEN = 357 = 105

Next, we need to find the value of Y by adding X to 1152:

We don't know the value of X yet, but we can see that the given sequence of numbers is following the pattern of saying out the number of consecutive digits in the previous term.

So, 1 is "one 1", 11 is "two 1s", 21 is "one 2, one 1", 1211 is "one 1, one 2, two 1s", and so on.

So, the next term in the sequence should be "one 3, one 1, two 2s, two 1s", which we can write as 13112221.

Thus, X = 13112221.

Adding X to 1152, we get:

Y = 1152 + X = 1152 + 13112221 = 13113373.

Finally, we need to find the value of Z by adding Y to A:

We don't know the value of A, but we can see that it is following the pattern of Conway's "look-and-say sequence".

Starting with "1", each term is formed by saying the digits out loud and counting the consecutive occurrences of each digit. For example, "1" becomes "one 1" or "11", which then becomes "two 1s" or "21", and so on.

So, the next term in the sequence should be "one 3, one 1, two 3s, three 1s, two 2s, one 1", which we can write as 131231132211.

Thus, A = 131231132211.

Adding A to Y, we get:

Z = A + Y = 131231132211 + 13113373 = 131244245584.

Therefore, Z is equal to 131244245584.

WhereMyLoud:
Please confirm my answer. What number can i forward my accout no. to sir

wrong

kals4luv990:
this is a look and say sequence na..Bleep all this long talk cause the answer is :1113213211..boss

wrong

Westerhoffe:
OK.

Let's start by breaking down the given multiplication into individual factors:

TWO = 2
FOUR = 4
SIX = 6

So, TWOFOURSIX = 246 = 48

Now, let's find the value of THREEFIVESEVEN:

Similarly, breaking down the given multiplication into individual factors:

THREE = 3
FIVE = 5
SEVEN = 7

So, THREEFIVESEVEN = 357 = 105

Next, we need to find the value of Y by adding X to 1152:

We don't know the value of X yet, but we can see that the given sequence of numbers is following the pattern of saying out the number of consecutive digits in the previous term.

So, 1 is "one 1", 11 is "two 1s", 21 is "one 2, one 1", 1211 is "one 1, one 2, two 1s", and so on.

So, the next term in the sequence should be "one 3, one 1, two 2s, two 1s", which we can write as 13112221.

Thus, X = 13112221.

Adding X to 1152, we get:

Y = 1152 + X = 1152 + 13112221 = 13113373.

Finally, we need to find the value of Z by adding Y to A:

We don't know the value of A, but we can see that it is following the pattern of Conway's "look-and-say sequence".

Starting with "1", each term is formed by saying the digits out loud and counting the consecutive occurrences of each digit. For example, "1" becomes "one 1" or "11", which then becomes "two 1s" or "21", and so on.

So, the next term in the sequence should be "one 3, one 1, two 3s, three 1s, two 2s, one 1", which we can write as 131231132211.

Thus, A = 131231132211.

Adding A to Y, we get:

Z = A + Y = 131231132211 + 13113373 = 131244245584.

Therefore, Z is equal to 131244245584.

wrong boss

westerhoffe

wrong boss

MaDaRa01:
wrong

see boss my A in d sequence is:13112221
Nd my Z will be:1113213211
Nd yes this question is hard but came across wen a friend doing PhD in the UK introduced me to it
But since yu say m wrong
Please explain it to me..keep your 20k nd teach me this one abeg🥺🙏

HellVictorinho6:
so the new pattern na to ask bulala question ,like say u get any razza , take person past time, una don cast, if u like , call this a stupid reply, na to face front,oya see road, u know say me no dey see joy , make we no burst for street, who dey ask say wetin i dey talk? dey play ,as dem neva set line 4 ground, dey play.

ok sir

kals4luv990:
see boss my A in d sequence is:13112221
Nd my Z will be:1113213211

every one get A But X and Y are wrong, which will make Z wrong

kals4luv990:
see boss my A in d sequence is:13112221
Nd my Z will be:1113213211
Nd yes this question is hard but came across wen a friend doing PhD in the UK introduced me to it
But since yu say m wrong
Please explain it to me..keep your 20k nd teach me

i will post the answer soon...... And don't worry, i will mention you in another thread for something. Check your mention later

MaDaRa01:
ok sir

another scope , but sha no reply me this time, my head dey touch with high tension.

Op to be giving people false hope no dey tire you?

HellVictorinho6:
another scope , but sha no reply me this time, my head dey touch with high tension.

eeyah, situation don deal with this one. Dare me to send you 20k?

Medianna:
Op to be giving people false hope no dey tire you?

werey make i go delete your name sef

MaDaRa01:
every one get A But X and Y are wrong, which will make Z wrong

first of all boss the question pattern is wrong but if yu will accept with me that this is a look and say sequence
Let's put it in "terms" instead of alphabets and assume dey are all terms..so we are looking for the 7th term if m not mistaken so look:
1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.
1211 is read off as "one 1, one 2, then two 1s" or 111221.
111221 is read off as "three 1s, two 2s, then one 1" or 312211.
So A would be: 13112221
Nd Z would be:1113213211