I figured programmers are good with maths and numbers I might someone who could solve this here, I posted in the education section no one has figured it yet?

Do it by yourself


Crack your brain small, it's very simple or


Come up with an excuse and dump it on your wife

phatriqk:
I figured programmers are good with maths and numbers I might someone who could solve this here, I posted in the education section no one has figured it yet?

We feel honored that those in education section couldn't solve this 😂

Here's the format:

There are four numbers arranged horizontally. According to their position from left to right, we'll classify them as N1, N2, N3 and N4.

Let's focus on N2, The logic is this:
N1 + N4 ÷ N3 = N2 (don't use BODMAS, a calculator may use BODMAS so calculate with pen and paper.)
(N1 + N4) ÷ N3 = N2 (for calculator)

Please if I've confused you, I'm terribly sorry

It seems that there are three operations addition , subtraction and division . However, there doesn't appear to be a consistent pattern or logic of the left and right boxes
N1=N2N3-N4
N2=(N1+N4)/N3
N3=(N1+N4)/N2
N4=N2N3-N1

11) N2=(N1+N4)/N1

N2=(7+1)/4= 2


13)N3=(N1+N4)/N2

N3=(8+7)/5=3


13)N1=N2N3-N4

N1=(5×1)-4 =5-4=1

14)N4=N2N3-N1

N4=(5×2)-4 =10-4=6

15) N3=(N1+N4)/N2

N3=(5+5)/2 =10/2 =5

Alphabyte2:
It seems that there are two operations addition and subtraction. However, there doesn't appear to be a consistent pattern or logic of the left and right box
11) 7-4=3
12)8-7=1
13) 5-4=1
14)5-2=3

Recheck boss

AnAbnormalHuman:


Recheck boss

Typo

Alphabyte2:


Typo

Nope, I think your methods aren't completely correct.

AnAbnormalHuman:


Nope, I think your methods aren't completely correct.

What about your solution the example is just additional and subtraction of left and right boxes it is not consistent

Alphabyte2:



What about your solution the example is just additional and subtraction of left and right boxes it is not consistent

It's quite consistent, maybe this will help

AnAbnormalHuman:


There are four numbers arranged horizontally. According to their position from left to right, we'll classify them as N1, N2, N3 and N4.

Let's focus on N2, The logic is this:
N1 + N4 ÷ N3 = N2 (don't use BODMAS, a calculator may use BODMAS so calculate with pen and paper.)
(N1 + N4) ÷ N3 = N2 (for calculator)

Please if I've confused you, I'm terribly sorry

AnAbnormalHuman:


It's quite consistent, maybe this will help

I now understand the logic now thanks

Alphabyte2:


I now understand the logic now thanks

You're welcome boss.

AnAbnormalHuman:


You're welcome boss.

What your programming stack?

Alphabyte2:


What your programming stack?

I'm not a programmer
I'm a fanatic tho.

AnAbnormalHuman:


I'm not a programmer
I'm a fanatic tho.

Alright but programming won't be hard for you because your level of critical thinking is high.

Alphabyte2:



Alright but programming won't be hard for you because your level of critical thinking is high.

Maybe you're overrating me but I appreciate the compliment

Actually I was trying to learn some coding... A little Python, a little web development stuff.

I'm quite lazy so I'm taking a 2-3 month break... But hopefully, I may cope if I keep up.

AnAbnormalHuman:


We feel honored that those in education section couldn't solve this 😂

Here's the format:

There are four numbers arranged horizontally. According to their position from left to right, we'll classify them as N1, N2, N3 and N4.

Let's focus on N2, The logic is this:
N1 + N4 ÷ N3 = N2 (don't use BODMAS, a calculator may use BODMAS so calculate with pen and paper.)
(N1 + N4) ÷ N3 = N2 (for calculator)

Please if I've confused you, I'm terribly sorry

Thanks sir

phatriqk:
Thanks sir

You're welcome sir.

PaganTerrorist:
Do it by yourself


Crack your brain small, it's very simple or


Come up with an excuse and dump it on your wife

(N1 + N4 )/N3 = N2

This is the correct mathematical statement. I stand to be corrected . Thanks