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Nairaland Forum / Nairaland / General / Education / Nairaland Mathematics Clinic (495603 Views)
Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by hardedeji1(m): 10:36am On Oct 23, 2014 |
Re: Nairaland Mathematics Clinic by hardedeji1(m): 10:36am On Oct 23, 2014 |
and here is another!
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Re: Nairaland Mathematics Clinic by Temieasy(m): 12:55pm On Oct 23, 2014 |
[quote author=rhydex247 post=27370292][/quote] Thanks boss |
Re: Nairaland Mathematics Clinic by Temieasy(m): 12:56pm On Oct 23, 2014 |
rhydex247:Thanks |
Re: Nairaland Mathematics Clinic by ValentineMary(m): 12:24pm On Oct 25, 2014 |
benbuks:guy u are good. |
Re: Nairaland Mathematics Clinic by factorial1(m): 3:52pm On Oct 25, 2014 |
If the position vectors A and B are (i + 2j + 4k) and (2i + 3j + 5k), find the position vector of point C that divide AB in the ratio 2:3. Find also the midpoint of AB. P.S... now on break, guess I should be more frequent here now. |
Re: Nairaland Mathematics Clinic by Nobody: 1:47pm On Oct 26, 2014 |
ValentineMary: God is good. |
Re: Nairaland Mathematics Clinic by Nobody: 1:50pm On Oct 26, 2014 |
hmmm...see questions abeg. hmm greet thee all . #shalom. |
Re: Nairaland Mathematics Clinic by happyday: 8:43pm On Oct 26, 2014 |
Kovic08: % error = error/true value x 100% where error = measured value - true value. E.g. A stick of lenght 1.75m was measured by a student as 1.8m. Error = 1.8 - 1.75m = 0.05m. % error = 0.05/1.75 x 100% = ... |
Re: Nairaland Mathematics Clinic by tuwayz(m): 2:40pm On Oct 30, 2014 |
Find the equation of the straight line through (-2,3) and perpendicular to 4x + 3y - 5=0 |
Re: Nairaland Mathematics Clinic by Nastydroid(m): 4:15pm On Oct 30, 2014 |
tuwayz:y-4x-11=0 |
Re: Nairaland Mathematics Clinic by factorial1(m): 5:25pm On Oct 30, 2014 |
Nastydroid:The ans. is 4y - 3x = 18 |
Re: Nairaland Mathematics Clinic by Nastydroid(m): 5:27pm On Oct 30, 2014 |
factorial1:thanks bro,i will try it again |
Re: Nairaland Mathematics Clinic by factorial1(m): 5:29pm On Oct 30, 2014 |
factorial1: |
Re: Nairaland Mathematics Clinic by Nastydroid(m): 5:55pm On Oct 30, 2014 |
factorial1:i made a mistake with d gradient..am on track now |
Re: Nairaland Mathematics Clinic by factorial1(m): 6:15pm On Oct 30, 2014 |
Nastydroid:thought as much. |
Re: Nairaland Mathematics Clinic by Nzecorneboy: 8:27pm On Oct 30, 2014 |
gurus oya solve for A,B,C,D 2A+C=0 3A+2B+D=3 A+3B+C=2 B+D=-1 |
Re: Nairaland Mathematics Clinic by tuwayz(m): 11:07am On Oct 31, 2014 |
factorial1:you are correct but you have to show your working |
Re: Nairaland Mathematics Clinic by tuwayz(m): 11:16am On Oct 31, 2014 |
Nzecorneboy: The solution is kind of long for typing but my finals answers are A =4/13, B=2/13, C=-8/13 , D=-15/13 |
Re: Nairaland Mathematics Clinic by SirChides(m): 7:43am On Nov 02, 2014 |
factorial1:[3(I+2j+4k)+2(2i+3j+5k)]/(2+3). =[3i+6j+12k+4i+6j+10k]/5. =[7i+12j+22k]/5. guess u can do d latter quest |
Re: Nairaland Mathematics Clinic by jackpot(f): 1:10pm On Nov 02, 2014 |
factorial1:just take the average of those two guys. The midpoint then becomes 1.5i+2.5j+4.5k. |
Re: Nairaland Mathematics Clinic by jackpot(f): 5:07pm On Nov 02, 2014 |
ooh, my benbuks. Where art thou? |
Re: Nairaland Mathematics Clinic by rhydex247(m): 3:58pm On Nov 04, 2014 |
Solve. A rigid body whose principal moment of inertia are A,A,3A is in motion with no forces acting. At the instant t=0, the angular velocity (w) of the body referred to the principal axes as coordinates axes are (2n,3n,n). Find angular velocity (w) at any subsequent time. |
Re: Nairaland Mathematics Clinic by emmyeuler1: 10:47pm On Nov 04, 2014 |
please maths generals help me out......benbuks,jackpot,rhydex,calculus fx,efficiency,laplacian........
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Re: Nairaland Mathematics Clinic by Laplacian(m): 7:28am On Nov 05, 2014 |
emmyeuler1:
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Re: Nairaland Mathematics Clinic by Laplacian(m): 7:42am On Nov 05, 2014 |
Here's question 1.)
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Re: Nairaland Mathematics Clinic by Laplacian(m): 7:46am On Nov 05, 2014 |
Contd.
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Re: Nairaland Mathematics Clinic by 2mNaira: 6:31pm On Nov 06, 2014 |
Please can anyone help me with the solution to this simultaneous equation? d1 squared = (x - x1)squared + (y - y1)squared .....equation1 d2 squared = (x - x2)squared + (y - y2)squared .....equation2 where d1,d2,x1,x2,y1 and y2 are all constants The solution should be given in terms of d1,d2,x1,x2,1,y2. Thanks a lot. P.S. I was directed to this thread form the the thread : https://www.nairaland.com/1984138/someone-me-solving-simultaneous-equation#27778957 |
Re: Nairaland Mathematics Clinic by Laplacian(m): 8:21pm On Nov 06, 2014 |
mnairaland:this can be solved either geometrically or algebraically. By geometry, it is easier since u are required to find the coordinate of intersection of two circles. Here's an algebraic proof; d12=(x-x1)2+(y-y1)2.......eqn1 d12=(x-x1+x2-x2)2+(y-y1+y2-y2)2 d12=(x-x2+(x2-x1))2+(y-y2+(y2-y1))2 or d12=(x-x2)2+2(x-x2)(x2-x1)+(x2-x1)2+(y-y2)2+2(y-y2)(y2-y1)+(y2-y1)2 substitute equation (2) in this last eqn and call it eqn (3), equation (3) will involve (x-x2) and (y-y2). From equation (3), substitute for (y-y2) in eqn (2) and solve the resulting quadratic in (x-x2) bros, the alphabet involved is too much, so dont expect the final solution here |
Re: Nairaland Mathematics Clinic by Calculusfx: 11:17pm On Nov 08, 2014 |
rhydex247:...smile,master rhydex,i wish i had ur time,so busy these days,all the way...my greetings to all the generals on the thread,JACKPOT,LAPLACIAN,BENBUKS,RHYDEX,FACTORIAL and others. |
Re: Nairaland Mathematics Clinic by Skykid1208(m): 8:13am On Nov 09, 2014 |
Richiez: Thanks |
Re: Nairaland Mathematics Clinic by Skykid1208(m): 8:16am On Nov 09, 2014 |
Richiez: |
(1) (2) (3) ... (151) (152) (153) (154) (155) (156) (157) ... (284) (Reply)
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