ok

the second triangle is 9

Scamfender:
. This is very easy but tricky

there are 5 squares in all, the others are rectangles.
on a cautionary note: remember a square is a shape with four straight sides of equal length

Next

missing number is 90

90.

I just noticed two more triangles in the second picture.
All in all, there are 10 triangles.

? = 9 x 10 =90

Waiting for more. These questions are too cheap though. Go harder!

Mrval20:
Waiting for more. These questions are too cheap though. Go harder!

Like if you did this





The hard way of course

How many squares are in dss picture






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The answer is 3
.
.
As 4+2 = 6
10 + 9 = 19
.
.
.
Take a look at it closely.

35 squares!

33 squares

I got 33 squares.

Scamfender:

Like if you did this





The hard way of course

I don't get you.

Ans is 34 squares

40 squares. Anything 4 me?

I gat 27 squares ooh, howcome some people got 34,33?...how,I guess I counted wrongly

3

sugarcoatted:
1st picture has 10triangles, i have no idea about the second 1

I think d 2nd has 4

@Scamfender,
Abeg, post the answers to these questions and put us out of our miseries.

Scamfender:
Replace the question mark with the right number

Will post the answer later
Sscroll down for more

the answer is 3 cos 9 minus 3 will give the answer in the immediate up.

Mrval20:

I don't get you.

. Solve the puzzle.

Scamfender:
Next

10 times 9 is 90

You are given the figure that is attached with the question. What you have to do is move six matchsticks such that the resulting figure has five squares.

Can you do it?

How will you place six X'son a X and O board without forming any three-in-a-row combination?

Scamfender:

10 triangles were stated at the source

The source got it wrong. First is 13 triangles and 11 for the second pic.

CallmeKola:
@Scamfender,
Abeg, post the answers to these questions and put us out of our miseries.

. Will do that tomorrow. I don't post another picture until the current one has been solved

Scamfender:
How many squares are in dss picture






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38

Scamfender:
How will you place six X'son a X and O board without forming any three-in-a-row combination?

You can only have 5 x's and 4 o's cos there are 9 spaces on the board
I.E 1,3,4,5,8.