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Re: Nairaland Mathematics Clinic by tuwayz(m): 10:34pm On Dec 06, 2014 |
Miscellaneous:. Thanks bro, I didn't understand the second solution though |
Re: Nairaland Mathematics Clinic by Miscellaneous(m): 10:48pm On Dec 06, 2014 |
tuwayz: I simplified it as much as I could..... just tell me wat u dont understand there ……& I'll explain. |
Re: Nairaland Mathematics Clinic by tuwayz(m): 11:26pm On Dec 06, 2014 |
Miscellaneous:. Right from the start I don't knw hw U got d values, I taught u were making Y subject of formular but I got confused d 1st 3 steps how did u get d values pls |
Re: Nairaland Mathematics Clinic by Miscellaneous(m): 7:06am On Dec 07, 2014 |
tuwayz: 4rm coordinate geometry, the gradient intercept form is: y = mx + c where m=gradient of the line so, the first thing I did was actually making Y the subject of formula. look closesly & u will see that on that line equation u made Y the subject, it's m = -4/3 Then we proceeded forward by using the rule for two lines to be perpendicular……… m1 * m2 = -1 m1 = the gradient of the 1st line m2= gradient of 2nd we don't av m2 . make m2 the subject in -4/3 * m2 = -1 i.e m2 = 3/4 then proceed………… using the formula for one-point form (y-y1)/(x-x1) = m2 |
Re: Nairaland Mathematics Clinic by ameer2: 11:03am On Dec 07, 2014 |
Miscellaneous:wow...nice1...following n loving dissl.bt y is m1×m2=-1? |
Re: Nairaland Mathematics Clinic by jackpot(f): 5:05pm On Dec 07, 2014 |
^^ @Miscellaneous, come and finish what you started. |
Re: Nairaland Mathematics Clinic by Miscellaneous(m): 6:12pm On Dec 07, 2014 |
jackpot: lol.... @ameer2 for two lines to be perpendicular, then the angle must be 90° thus, from elementary mathematics, tan90° = (m2- m1)/(1 + m2m1) which has no finite value. so, 1 + m2m1 = 0 i.e, m2m1 = -1 for two perpendicular lines |
Re: Nairaland Mathematics Clinic by ameer2: 7:14pm On Dec 07, 2014 |
Miscellaneous:wow...seems im grabbing somtin from dis...0=parallel line/perpendicular line? Ryt |
Re: Nairaland Mathematics Clinic by PatEinstEin(m): 7:18pm On Dec 07, 2014 |
I greet everybody 1 Like |
Re: Nairaland Mathematics Clinic by Miscellaneous(m): 7:08am On Dec 08, 2014 |
ameer2: if two line is parallel, the angle between them is 0° thus m2=m1 for parallel lines. 1 Like |
Re: Nairaland Mathematics Clinic by FuckYou: 1:31am On Dec 09, 2014 |
jackpot:abeg na answer i dey find o |
Re: Nairaland Mathematics Clinic by FuckYou: 1:35am On Dec 09, 2014 |
FuckYou:please o |
Re: Nairaland Mathematics Clinic by mesoade(m): 7:33am On Dec 14, 2014 |
The sum of the first n term of a geometric series is 127,the sum of their reciprocals is 127/64 ,the first term is 1 ,find n and the common ratio . . . Cc factorial1 miscellanous |
Re: Nairaland Mathematics Clinic by Drniyi4u(m): 3:42pm On Dec 14, 2014 |
FuckYou: picture below. From ▲TOA, tan 27° = y/x y = x tan 27°.....(i) From ▲TOB, tan 14° = y / (30+x) y = (30+x)tan14°……(ii) Equate (i) nd (ii) x tan 27° = (30+x) tan 14° x = 28.75m therefore, the width of d river is 28.75m 1 Like
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Re: Nairaland Mathematics Clinic by aptitudeexam: 3:53pm On Dec 14, 2014 |
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Re: Nairaland Mathematics Clinic by jackpot(f): 9:24pm On Dec 14, 2014 |
mesoade:n=7, r=2 Hint: (1-r^n)/(1-r)=127, (1-r^(-n))/(1-r^(-1))=127/64. Solve simultaneously. |
Re: Nairaland Mathematics Clinic by mesoade(m): 1:03am On Dec 15, 2014 |
jackpot:it's the simultaneous part that gives me prob. . . Pls,kindly finish it for me |
Re: Nairaland Mathematics Clinic by jackpot(f): 6:29am On Dec 15, 2014 |
mesoade:it is simple nah. Multiply the second equation with r^(n-1). You will now get 127=(127/64)r^(n-1), so r^(n-1)=64, so r^n=64r. Now, from 1-r^n=127(1-r), we have 1-64r=127(1-r). The rest is banana |
Re: Nairaland Mathematics Clinic by mesoade(m): 9:26am On Dec 15, 2014 |
jackpot:thanks bro,but how did you come about that@emboldened |
Re: Nairaland Mathematics Clinic by lantessy(m): 1:05pm On Dec 15, 2014 |
Solve the system of equations: xyz = 4 xy + yz + zx = 10 x^2 + y^2 + z^2 = 16. |
Re: Nairaland Mathematics Clinic by jackpot(f): 1:18pm On Dec 15, 2014 |
mesoade:gave you lollipop to lick and you just returned it. Well, lemme savour the sweet taste. Multiplying both sides of (1-r^(-n))/(1-r^(-1))=127/64 with r^(n-1), we have (127/64)r^(n-1)= [(1-r^(-n))/(1-r^(-1))]r^(n-1)= [r^n(1-r^(-n))]/[r(1-r^(-1))]=(r^n-1)/(r-1)=(1-r^n)/(1-r)=127. Therefore, (127/64)r^(n-1)=127 implies r^(n-1)=64. Yummmmmmy. . .sweet |
Re: Nairaland Mathematics Clinic by lantessy(m): 1:40pm On Dec 15, 2014 |
jackpot: 127 (r - 1) = r^n - 1 and r^n = 64r => 127(r - 1) = 64r - 1 63r = 127 - 1 => r = 2 Then if r=2, 2^n = 64 * 2 Therefore, 2^ n = 128= 2^7 Hence, n=7 |
Re: Nairaland Mathematics Clinic by Nobody: 1:48pm On Dec 15, 2014 |
jackpot: Hmmmm! Powerful, See scholar. |
Re: Nairaland Mathematics Clinic by Dacronym(m): 7:48am On Dec 17, 2014 |
.. |
Re: Nairaland Mathematics Clinic by jackpot(f): 3:57pm On Dec 17, 2014 |
Dacronym:A(w)= w(14-w). Domain A= { w: 0<w<14} Range A= (0, 49] |
Re: Nairaland Mathematics Clinic by Dacronym(m): 8:53pm On Dec 17, 2014 |
jackpot:pls do you understand the question? No disrespect but This ans is incorrect. And if its not pls show workings cos i dont understand what u did |
Re: Nairaland Mathematics Clinic by jackpot(f): 2:08am On Dec 18, 2014 |
Dacronym:I bet any other different answer you post is incorrect. Post the answer you think is correct. Only then will I defend my answer. |
Re: Nairaland Mathematics Clinic by dejt4u(m): 8:55am On Dec 18, 2014 |
jackpot: |
Re: Nairaland Mathematics Clinic by Nobody: 9:06am On Dec 18, 2014 |
Re: Nairaland Mathematics Clinic by dejt4u(m): 9:07am On Dec 18, 2014 |
Tpappie:you are right.. I made a sil.ly mistake |
Re: Nairaland Mathematics Clinic by erigwe: 4:14pm On Dec 18, 2014 |
pls help on this problem: prove that: (Log ab base a)(Log ab base b) = (log ab base a) + (log ab base b) |
Re: Nairaland Mathematics Clinic by tohero(m): 5:09pm On Dec 18, 2014 |
Dacronym: jackpot: Dacronym:Perimeter of a rectangle= 2(L+B)=28. L+w=14. So L=14-w. Dacronym: Area (A)=L*B=L*w=(14-w)w=w(14-w) jackpot: |
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