Nairaland Mathematics Clinic - Education (162) - Nairaland
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| Re: Nairaland Mathematics Clinic by neighy(m): 6:50am On Jan 25, 2015 |
bolkay47:Thanks Boss... Buh I think Number 5 is limitation... |
| Re: Nairaland Mathematics Clinic by neighy(m): 7:06am On Jan 25, 2015 |
bolkay47... {1}---note: ¥ means root) 12¥e=x¥7::12*¥12=x*¥7 Divide both sides by ¥7 X=12¥12/¥7 using surd You will arrive at x=24¥21/7.. My Bad but its actually 12 base e=X base 7... Where e=12 ... Find X {2}. Y=4x-x^2 at x=1 and x=2 (Note $ means integral) $4x-x^2dx $4x^2/2-x^3/3 Therefore$4x-x^2= 2x^2-x^3/3+C [2(2^2)-2^3/3]-[2-1/3] (8-8/3)-(2-1/3) 16/3-5/3=11/3 Ans=3.7square units. Well my book here says the answer is 2/3 only that the Solution wasn't given... |
| Re: Nairaland Mathematics Clinic by bolkay47(m): 7:14am On Jan 25, 2015 |
neighy:re-write that no 5 question its not clear....but number 3 is weird. For number (2). Maybe I made a mistake or its a typographical error in your textbook. |
| Re: Nairaland Mathematics Clinic by neighy(m): 7:21am On Jan 25, 2015 |
Bolkay47 and Others... More (NB..¥ is Root) 1)Find the root of the equation 2 ¥x =x-3.... 2)If F and G are two different functions such that F(x)=x+1 and -1/x=g(x) find gof 3)A train starts from rest and its acceleration t seconds after start is 1/4 (20-t) m/s what is its speed after 20sec... 4)A curve passes through the point (4, -3). Its gradient is 2-x find the equation of the curve... 5) Find the area enclosed between the curves Y=4-x^2 and Y=x^2-2x To all the maths Gurus here Do the needFul... |
| Re: Nairaland Mathematics Clinic by bolkay47(m): 7:32am On Jan 25, 2015 |
neighy:find what in no2? |
| Re: Nairaland Mathematics Clinic by neighy(m): 7:33am On Jan 25, 2015 |
bolkay47:maybe this will help
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| Re: Nairaland Mathematics Clinic by neighy(m): 7:35am On Jan 25, 2015 |
bolkay47:the root of the equation... |
| Re: Nairaland Mathematics Clinic by bolkay47(m): 7:37am On Jan 25, 2015 |
neighy:maybe the answer is just none. Not that sure tho. (No) got -1/2 as the limit. |
| Re: Nairaland Mathematics Clinic by Nobody: 12:29pm On Jan 25, 2015 |
apart from using this long method,you can also do it like this.x+y=5...1 and x^x+y^y=31...2,we break eqn 2 like this x^x+y^y=2^2+3^3 i.e we break down 31.therefore by equating we have x^x=2^2 and y^y=3^3,so x=2 ans and y=3 ans. |
| Re: Nairaland Mathematics Clinic by Nobody: 12:36pm On Jan 25, 2015 |
the solution to the eqn;x+y=5...1 and x^x+y^y=31...2,we can break eqn 2 as this,x^x+y^y=2^2+3^3.so by equating we have x^x=2^2 and y^y=3^3,therefore x=2 ans and y=3 ans. |
| Re: Nairaland Mathematics Clinic by Nobody: 12:41pm On Jan 25, 2015 |
bolkay you are wrong,for the solution of if x=sin@,simplify x/(1-x^2)^1/2 |
| Re: Nairaland Mathematics Clinic by bolkay47(m): 12:55pm On Jan 25, 2015 |
jgenius:lols I know that now.. But pls post the solution. |
| Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 2:54pm On Jan 25, 2015 |
| Re: Nairaland Mathematics Clinic by efficiencie(m): 6:19pm On Jan 26, 2015 |
jgenius: is tan@ not d answer? |
| Re: Nairaland Mathematics Clinic by agentofchange1(m): 11:31am On Jan 27, 2015 |
| Re: Nairaland Mathematics Clinic by tohero(m): 1:51pm On Jan 27, 2015 |
Hi everyone! I think we should make this suggestion to seun. We all write mathematical equations and expressions using our phone's symbols list. Apart from the fact that it is not appropriate, it reduces the readability and the zeal to post and attend to mathematical questions. There is a solution! But that depends on seun. There is a mathematical typesetting program called LaTeX which is specifically for typesetting mathematical documents. Not just only available for desktops alone but also available for the web! This is what is being used by forums like math.stackexchange.com/questions/96151/do-imaginary-and-complex-angles-exist And the likes of wikipedia when writing anything mathematical. How do we use it here? Depending on the platform to which this forum is built, there is a plugin will allows us to write such equations. If the plugin can be integrated to this forum, then we are good to go! THEN, We need to learn how to use the language LaTeX. Since we are mathematics student, I believe few if not all of us knew about the use. Unfortunately, since it is not included in our courses at school majority may fail to know about this. SOLUTION I can sacrifice my time to teach us all on how to use this beautiful language. NB: LaTeX is what is being used to write our textbooks, project, thesis and the rest! 4 Likes 3 Shares |
| Re: Nairaland Mathematics Clinic by bolkay47(m): 8:45pm On Jan 28, 2015 |
tohero:whao.!! |
| Re: Nairaland Mathematics Clinic by Cymbal: 11:51pm On Jan 30, 2015 |
Hello fellaz....Kindly help me prove this trigometric question: .. Show that (tan@ + cos@)/(sec@ + sin@) = sec@ - sin@. ...where @= angle tita. |
| Re: Nairaland Mathematics Clinic by Drniyi4u(m): 7:48am On Feb 05, 2015 |
AlphaMaximus:yoų çāŋ ţŗy Engineering Mechanics - Statics, by Meriam, Kraige OR Beer & Johnston: Statics and Dynamics ţђęy'ŗę woŋdęŗƒųl įŋ męçђāŋįçş! |
| Re: Nairaland Mathematics Clinic by yemstok(m): 10:01pm On Feb 05, 2015 |
agentofchange1: Thanks for helping out the other day bro. I need ur assistance once more. Should I bring iit on? |
| Re: Nairaland Mathematics Clinic by fapcrook(m): 12:01am On Feb 06, 2015 |
Please I need help with my real analysis and abstract algebra.. I am a mathematics student. Thanks in advance |
| Re: Nairaland Mathematics Clinic by akpos4uall(m): 9:26am On Feb 06, 2015 |
AlphaMaximus: I'm not 100% sure but I think there is a Schaum's Outline Series textbook on Mechanics of Materials. |
| Re: Nairaland Mathematics Clinic by akpos4uall(m): 9:51am On Feb 06, 2015 |
neighy: bolkay47: gof means we should find g of f = g{f(x)}. That is an expression that is defined by the function g of function f of x. f(x) = x + 1 g(x) = -1/x We can get gof by putting f(x) in place of x in g(x) gof = -1/f(x) gof = -1/(x + 1) In case you don't understand, let me use figures to make it clearer. When x = 1, f(1) = 1 + 1 = 2, g(2) = -1/2 = -0.5 According to our solution, gof = -1/(x + 1) = -1/(1 + 1) = -1/2 = -0.5 As you can see, they are the same When x = 10, f(10) = 1 + 10 = 11, g(11) = -1/11 gof = -1/(x + 1) = -1/(10 + 1) = -1/11 Once again, they are the same |
| Re: Nairaland Mathematics Clinic by agentofchange1(m): 4:45pm On Feb 06, 2015 |
yemstok: OK..let's see if I can ... or others can help out .. |
| Re: Nairaland Mathematics Clinic by efficiencie(m): 10:05pm On Feb 06, 2015 |
Cymbal: Given (tanθ+cosθ)/(secθ+sinθ)= secθ-sinθ Verify by fixing θ=(π/3) (tan(π/3)+cos(π/3))/(sec(π/3)+sin(π/3)) = (√3+1/2)/(2+√3/2) = (2√3+1)/(4+√3) = ((2√3+1)(4-√3))/((4+√3)(4-√3)) = (7√3-2)/13 = (7√3-2)/13 but the LHS is sec(π/3)-sin(π/3) = (2-√3/2) which shows that (tanθ+cosθ)/(secθ+sinθ)≠ secθ-sinθ Since it's the equation doesn't hold for: θ=(π/3) But it can be shown that: (tan^2(θ)+cos^2(θ))/(secθ+sinθ)=secθ-sinθ Startin frm d RHS! secθ-sinθ =(secθ-sinθ)(secθ+sinθ)/(secθ+sinθ) =(sec^2(θ)-sin^2(θ))/(secθ+sinθ) =(1+tan^2(θ)-sin^2(θ))/(secθ+sinθ) =(tan^2(θ)+cos^2(θ))/(secθ+sinθ) Which is the RHS QE  |
| Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 2:23pm On Feb 07, 2015 |
Drniyi4u: akpos4uall:thanks a lot. |
| Re: Nairaland Mathematics Clinic by Cymbal: 5:54pm On Feb 07, 2015 |
efficiencie:thanks a bunch. |
| Re: Nairaland Mathematics Clinic by rhydex247(m): 2:09am On Feb 08, 2015 |
fapcrook:For real analysis u can use this references i. introduction to real analysis. by bartle.G. sherbert ii Real analysis textbuk by Hans sagan nd edward ganghan iii. Real analysis textbuk by Olubumo iv Real analysis textbuk by DR. S.O. OLUYEMI. (LAUTECH WIZARD IN REAL ANALYSIS). ## For abstract algebra u can use this references as well. i. Schaums outlines on Abstract Algebra. ii. Discrete mathematics by shaums outlines. i hope dis will help. #Series cares# |
| Re: Nairaland Mathematics Clinic by Arithmetic(m): 11:37pm On Feb 08, 2015 |
Evaluate ${(1/lnt)}dt. |
| Re: Nairaland Mathematics Clinic by Arithmetic(m): 11:37pm On Feb 08, 2015 |
Evaluate ${(1/t).et}dt. |
| Re: Nairaland Mathematics Clinic by badmus45: 5:18am On Feb 09, 2015 |
heip solve this assignment sirs:given points A(18,-  and B(-7,- are vertices of an isoceles triangle ABC with AB=AC,if the altitude AN has the equation 4x+3y=48,find the coordinate of N and C. (2).the points A(3,1) B(8,2) C(-1,11) are the vertices of a triangle, if N isthe foot of the perpendicular from A to BC find(a)equation of BC (b)equation of AN (c)length of AN. pls oooooo |
| Re: Nairaland Mathematics Clinic by badmus45: 5:19am On Feb 09, 2015 |
badmus45: |
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