Pr0ton:
Before going to bed lemme put this down (hoping to see an answer tomorrow)

Complete this:
Under the general properties of carboxylic acids, as the number of carbon atoms in the alkyl group increases, the acidic nature ______

Tag:
Estijaz
Holamarncy
Segunflames
Francistony
DrHost
Fembleez1

GoodNight

e suppose decrease i guess

[i][/i]jamb z still very far... ..1/27 of a yr!! 2 go

Holamarncy:
[i][/i]jamb z still very far... ..1/27 of a yr!! 2 go

still very far?

estijaz:
ppt oo abeg I can't shout,I dread cbt actually,just imagine d computer switching off b4 u can av d chance to click 'final submit'#dat one na really bad market#

hahaha! bad market really. but no one wishes such situation.

cassyrooy:
Everyones reading?
Gonna sue me?

Well he's got no right to tell me of the thread to romance etc. But it doesn't make me more serious than any other UI aspirant.

i think all your comments are jokes,right? and for allegation of telling you the thread to be: did i told u that? i beg recheck my initial post.... i'm also a social science aspirant..... let continue to exhibit our initial civility.

Holamarncy:
e suppose decrease i guess

yes it decreases there is supply of excess electron..... The larger d r d less acidic...... Ur calc use 2 mol of na= 2 mole of naoh 0.1 mol =x o.1 is get by dividing 2.3 with 23 cross multiply that gives 0.1 multiply that naoh mm and u have ur ans 4...... U can also solv with mm directly.... Organic get calcs ooo

FunkySilver:


still very far?

24hrs is even enough to pass depending on some factors

DrHost:
24hrs is even enough to pass depending on some factors

You're starting to sound cocky.

What kind of factors will make you prepare and pass an exam that is only 24 hours away

You all should read for jamb and forget the post ume for now.

Ogas and Madams...I greet una morning o!

Holamarncy:
e suppose decrease i guess

Correct! Good morning bro

Pr0ton:


2Na + 2H ₂ O ---> 2NaOH + H ₂


From the above equation, calculate the mass of sodium hydroxide produced by 2.3g of sodium.

A. 0.40g B. 0.80g C. 4.00g D. 8.00g

[H = 1, O = 16, Na = 23]

4g.

The only elements/compounds to include is Na and NaOH. Since they both have the same mole(2). Cancel out so it'd be 1.

Na : NaOH
1 : 1
23 : 40
2.3 : xg

X= 40 * 2.3/ 23
X= 4g

NaOH= 4g when Na is 2.3g

DrHost:
yes it decreases there is supply of excess electron..... The larger d r d less acidic...... Ur calc use 2 mol of na= 2 mole of naoh 0.1 mol =x o.1 is get by dividing 2.3 with 23 cross multiply that gives 0.1 multiply that naoh mm and u have ur ans 4...... U can also solv with mm directly.... Organic get calcs ooo

Where did you get 0.1 mol from

XavierG:



You're starting to sound cocky.

What kind of factors will make you prepare and pass an exam that is only 24 hours away

You all should read for jamb and forget the post ume for now.

:-D u c doctor for person name u know know say na boss.

DrHost:
yes it decreases there is supply of excess electron..... The larger d r d less acidic...... Ur calc use 2 mol of na= 2 mole of naoh 0.1 mol =x o.1 is get by dividing 2.3 with 23 cross multiply that gives 0.1 multiply that naoh mm and u have ur ans 4...... U can also solv with mm directly.... Organic get calcs ooo

its nt organic calculation its jxt common stoichiometry

MockinJay:


4g.

The only elements/compounds to include is Na and NaOH. Since they both have the same mole(2). Cancel out so it'd be 1.

Na : NaOH
1 : 1
(mole)


23 : 40
(molar mass)


2.3 : xg
(mass)


X= 40 * 2.3/ 23
X= 4g

NaOH= 4g when Na is 2.3g

Please if I may ask:

1. Why not use 2:2 mole ratio instead of 1:1?

2. I noticed you didn't use the mole ratio in the calculation, then why should we be concerned with the mole ratio in the first place?

3. Could you tell me the exact formular you used for the calculation?

Kumpharm.. What's up nw?

Holamarncy:
walahi na only chemistry i dn read...hmmm...guy God go help...

. Please if I may ask,which course are you going for....

Omoyele96:
. Please if I may ask,which course are you going for....

mbbs ..u?

Pr0ton:


Please if I may ask:

1. Why not use 2:2 mole ratio instead of 1:1?

2. I noticed you didn't use the mole ratio in the calculation, then why should we be concerned with the mole ratio in the first place?

3. Could you tell me the exact formular you used for the calculation?

dat z method z tym consuming
since dey av d same mole
23 = 40
2.3 = X
of course its jxt 4

Pr0ton:


Please if I may ask:

1. Why not use 2:2 mole ratio instead of 1:1?

2. I noticed you didn't use the mole ratio in the calculation, then why should we be concerned with the mole ratio in the first place?

3. Could you tell me the exact formular you used for the calculation?

1. For two reasons. First, they are both carrying the same mole. So one could easily cancel them out. But why? Cause it's easier and faster.(reason 2)

2. I made use of it. Since it's 1,it won't show just like HCl is also 1HCl. Now, if I were to use the 2mole instead of the 1mole. The molar masses of Na and NaOH would be 46 and 80g/mol respectively.

3. The "I don't have a calculator but want to be fast" formula

Whether I use the 1:1 mole ratio or 2:2 mole ratio, I would still get the same answer.

2Na : 2NaOH
2* 23 : 2* 40
46 : 80
2.3 : x

X= 80 * 2.3/46
X= 4g

Holamarncy:
dat z method z tym consuming
since dey av d same mole
23 = 40
2.3 = X
of course its jxt 4

Yours is faster but not comprehensive.

Just imagine an equation of this nature having a 3mole of Cl and 3mole of say, NaOH.

Instead of using a calculator or stressing yourself to multiple 3 by 35.5 for Cl. Why not just cancel both mole ratio out?

So it'd be 35.5 of Cl and 40 of NaOH. Faster..ryt?

Holamarncy:
dat z method z tym consuming
since dey av d same mole
23 = 40
2.3 = X
of course its jxt 4

That's the same formula I used but I needed to explain so the guy could easily grab.

MockinJay:


1. For two reasons. First, they are both carrying the same mole. So one could easily cancel them out. But why? Cause it's easier and faster.(reason 2)

2. I made use of it. Since it's 1,it won't show just like HCl is also 1HCl. Now, if I were to use the 2mole instead of the 1mole. The molar masses of Na and NaOH would be 46 and 80g/mol respectively.

3. The "I don't have a calculator but want to be fast" formula

Whether I use the 1:1 mole ratio or 2:2 mole ratio, I would still get the same answer.

2Na : 2NaOH
2* 23 : 2* 40
46 : 80
2.3 : x

X= 80 * 2.3/46
X= 4g

Got it! Thanks

Pr0ton:


Who can name the above

Could you answer that?

Meanwhile, more calculations coming up. @Holamarncy, MockinJay and DrHost.

Pr0ton:
Kumpharm.. What's up nw?

I'm good dear, Good morning

..

Pr0ton:


Could you answer that?

Meanwhile, more calculations coming up. @Holamarncy, MockinJay and DrHost.

Compounds present: Phenol and Toluene(but not attached to benzene)

My guess (Hydroxymethyl)benzene

kumpharm:



I'm good dear, Good morning

Good morning! How about your admission??

Holamarncy:
..lol no b u wan join ehn na ur acceptance fee b dat na..

Lol

Pr0ton:


Good morning! How about your admission??

Been admitted already..

MockinJay:
..

Compounds present are actually Phenyl (C₆H ₅) and Menthanol (CH₃OH)

It's Phenylmenthanol. Are you an aspirant?

kumpharm:


Been admitted already..

Oh..(Never knew) What course?