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Nairaland Forum / Nairaland / General / Education / Nairaland Mathematics Clinic (493938 Views)
Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by jaryeh(m): 2:52am On Feb 23, 2015 |
Mathematicians in the house, I salute o. Pls, does anyone know where or how I can get a pdf copy of Schaum's outline of vector analysis? 1 Like |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:12am On Feb 23, 2015 |
jaryeh: follow this link..then download any of them www.google.com/m?q=pdf+on+vector+analysis&client=ms-opera-mini-android&channel=new |
Re: Nairaland Mathematics Clinic by Nobody: 9:26am On Feb 23, 2015 |
Can u pls help me to upload your solution.The former is not clear. agentofchange1:I have £=-1 in the solution with me but is just complicated. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 9:29am On Feb 23, 2015 |
Onase: OK that will be later ... am not at home now u mean d ans is -1 & not 5?. |
Re: Nairaland Mathematics Clinic by seribroo56(m): 10:56am On Feb 23, 2015 |
jaryeh:search for ucforum ---->ebook--->education... you may not find that exact book but am sure u will find a book very close to it... good morning |
Re: Nairaland Mathematics Clinic by Nobody: 11:45am On Feb 23, 2015 |
pls which textbook can i see a replicate of this example? agentofchange1:Yes. |
Re: Nairaland Mathematics Clinic by Nobody: 12:00pm On Feb 23, 2015 |
Pls Nairalanders help me to solve this question.Find the value of alpha(i will use pound symbol)£ for which the following equation possesses solutions> x-3y+2z=4 2x+y-z=1 3x-2y+z=£(alpha) A friend solved it and gave me the following answers. z=7,y=2,x=-4,alpha=-1.But is workings are complicated.I have made an attempt but i am hooked at reducing echelon matrix. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 2:09pm On Feb 23, 2015 |
Onase: hmm. no bro..those values don't satisfy the equations Check putting x=-4 , y=2 , z=7 for eqn1 , -4-3(2)+2(7)=-4-6+14= =4 .....(eqn 1 satisfied) for eqn 2, 2(-4)+2-7 =-8+2-7=-13=/=1 (eqn2 not satisfied) for eqn3, 3(-4)-2(2)+7=-12-4+7=-9=/=-1(eqn3 not satisfied) it must satisfy all . here , check my solution , the values are x=1 , y=-1 , z=0 & £=5 Check for eqn1, 1-3(-1)+0=1+3=4 (eqn1 satisfied) for eqn2 2(1)+(-1)+0=2-1 =1 (eqn2 satisfied) for eqn3 , 3(1)-2(-1)+0=3+2=5.(eqn3 satisfied) that's it man . pix below. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 2:22pm On Feb 23, 2015 |
Onase: you can check. Engineering mathematics by H.K Dass. |
Re: Nairaland Mathematics Clinic by randwise(m): 3:10pm On Feb 23, 2015 |
Hello, pls, help solve this algebra.. I'm very confused. if x=(p+q)⅓+(p-q)⅓ and r=(p²-q²)½ prove that x³-3rx=2p |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:40pm On Feb 23, 2015 |
randwise: OK check the 2nd eqn I think it ought to be ^1/3. not ^1/2 ********Solution ************ proof: x=(p+q)1/3 +(p-q)1/3 r=(p2 -p2 )1/3 r=(p+q)1/3 *(p-q)1/3 set a=(p+q)1/3 & b=(p-q)1/3 => x=a+b & r=ab now LHS, x3 -3rx => (a+b)3 -3ab(a+b) => a3 + b3 thus we have , [(p+q)1/3 ]3. +[(p-q)1/3 ]3 =p+q+p-q 2p ...............(as required ) |
Re: Nairaland Mathematics Clinic by Nobody: 8:08pm On Feb 23, 2015 |
Tanx bro...I really appreciate. agentofchange1: |
Re: Nairaland Mathematics Clinic by Dacronym(m): 8:15pm On Feb 23, 2015 |
.. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 8:16pm On Feb 23, 2015 |
Re: Nairaland Mathematics Clinic by Nobody: 8:27pm On Feb 23, 2015 |
Downloading. |
Re: Nairaland Mathematics Clinic by Nobody: 8:53pm On Feb 23, 2015 |
agentofchange1:yes.Pls how did u arrive at O O O in the third row? Cuz R3-3R1 wont give us Zero. |
Re: Nairaland Mathematics Clinic by benji93: 10:03pm On Feb 23, 2015 |
I have question for you all.Two fathers and two sons went to the market to buy bottles of wine,they all had #450 whiles each bottle costs #150,they to share the bottle of wines equally and not in fractions,how is this possible. |
Re: Nairaland Mathematics Clinic by randwise(m): 12:46am On Feb 24, 2015 |
agentofchange1: I'm happy. Thanks brother. You just solved out one my MTS101 problems. Thank you. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 5:58am On Feb 24, 2015 |
Onase: its nothing man, just solving for fun /learning & helping ....return all praise to God, the giver of life & knowledge, nothing was ever done exclusive of his grace . BTW: I CNT view the P.m u sent me earlier , kindly re-send. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:02am On Feb 24, 2015 |
randwise: its OK bro....any day. , try also to give an helping hands /teach also others in need , also make sure you try a particular problem exhaustively before posting here , that's how we learnt / reached the level we are , its fun solving.. #shalim....#1love |
Re: Nairaland Mathematics Clinic by dejt4u(m): 6:48am On Feb 24, 2015 |
benji93:this isnt mathematics but a riddle.. Obviously, there are three guys involved.. The son, the father and the grandfather.. i.e the two fathers are the father and the grandfather. the 2 sons are the father and the son..since the father is stil a son to the grandfather.. Therefore, they will have one bottle each.. Good morning my ogas here |
Re: Nairaland Mathematics Clinic by Drniyi4u(m): 6:50am On Feb 24, 2015 |
benji93:there are 3 people involved, one grandfather, one father nd his 2 sons.... meaning 2 fathers nd 2 sons So, #150 * 3 =#450 |
Re: Nairaland Mathematics Clinic by dejt4u(m): 7:14am On Feb 24, 2015 |
Drniyi4u:nxt tym, m gonna cover my works..lol. Howdy! |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:59am On Feb 24, 2015 |
Onase: oh...sorry....my bad... its R3 -R2 rather.....don't know what I was thinking when I wrote that.. correct it plz....thanks for drawing my attention. |
Re: Nairaland Mathematics Clinic by benji93: 11:24am On Feb 24, 2015 |
Find the area of the Shaded Portion if the side of the Square measures 20 cm. Give the answer in cm^2. (Use the Value of Pi as 3.14 only. Exactly 3.14)
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Re: Nairaland Mathematics Clinic by benji93: 11:27am On Feb 24, 2015 |
What is the area of the large square ?
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Re: Nairaland Mathematics Clinic by furetin20: 7:09pm On Feb 24, 2015 |
FOLLOWING BADLY. I GREET ALL THE BOSSES AND MASTERS IN THE HOUSE I'D BE LEARNING A LOT FROM YOU GUYS HOPEFULLY VERY SOON ASSIGNMENTS WOULD ALWAYS BE UPLOADED HERE |
Re: Nairaland Mathematics Clinic by Nastydroid(m): 8:02pm On Feb 24, 2015 |
furetin20:make sure you include airtime and data |
Re: Nairaland Mathematics Clinic by Geofavor(m): 9:57pm On Feb 24, 2015 |
lol |
Re: Nairaland Mathematics Clinic by benji93: 11:07pm On Feb 24, 2015 |
benji93:men,i tink this will make you sweat |
Re: Nairaland Mathematics Clinic by DeeCherry(f): 11:17am On Feb 25, 2015 |
Pls guys help with this . ytan xdy/dx = (4+y^2) sec^2x |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 12:15pm On Feb 25, 2015 |
DeeCherry: OK dear in a bus now...let's sha . using separable variables, => dy /dx = (4+y^2)(sec^2 x)/(ytanx) => dy/dx =(sec^2 x)/(tanx) * (4+y^2)/y => ydy/(4+y^2) = (1/cos^2 x)/(tanx)dx now take integral of both sides guess you finish up from dia... right .? 1 Like |
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