agentofchange1:


OK dear in a bus now...let's sha .

using separable variables,

=> dx /dx = (4+y^2)(sec^2 x)/(ytanx)

=> dy/dx =(sec^2 x)/(tanx) * (4+y^2)/y

=> ydy/(4+y^2) = (1/cos^2 x)/(tanx)dx


now take integral of both sides

guess you finish up from dia... right .?

yes I can but I want a full solution. pls

agentofchange1:


OK dear in a bus now...let's sha .

using separable variables,

=> dx /dx = (4+y^2)(sec^2 x)/(ytanx)

=> dy/dx =(sec^2 x)/(tanx) * (4+y^2)/y

=> ydy/(4+y^2) = (1/cos^2 x)/(tanx)dx


now take integral of both sides

guess you finish up from dia... right .?

yes I can but I want a full solution. pls

DeeCherry:


yes I can but I want a full solution. pls

using separable variables,
=> dy /dx = (4+y^2)(sec^2 x)/(ytanx)
=> dy/dx =(sec^2 x)/(tanx) * (4+y^2)/y
=> ydy/(4+y^2) = (sec^2 x)/(tanx)dx

integrating both sides we have

=>1/2ln(4+y^2) = ln(tanx) +lnC

= ln√(4+y^2) =ln(Ctanx)

= > √(4+y^2) = Ctanx.

or y^2 = (Ctanx)^2 -4

that's it

hope u get .?

or needs more explanations.?

Gud afternoon to u all.
I need more info on this. i will b glad for a quick respond.
Where can we do an Industrial traning as a mathematics student. and hw can we apply for it?
U can also help with the salary involved in each of d firm.

ok.I will re.send the P.m.

agentofchange1:



oh...sorry....my bad...

its R3 -R2 rather.....don't know what I was thinking when I wrote that..

correct it plz....thanks for drawing my attention.

It is not all about the salary bro;it's about the knowledge you gain.You can do it with Revenue or tax department.

rhydex247:
Gud afternoon to u all.
I need more info on this. i will b glad for a quick respond.
Where can we do an Industrial traning as a mathematics student. and hw can we apply for it?
U can also help with the salary involved in each of d firm.

From one fraction of the four square, which result to the bigger square, note;

6 + x = 4 + y (sides of square)

Taking a sketch of another circle equidistance from d bigger and d smaller circle the radius of the bigger circle will be bisect into three equal partsm

So we have

6 + x = 6 + 3 = 9

But we know;

6 + x = 4 + y

6 + 3 = 4 + y

Y = 9 - 4

Y = 5


But area of a square = L x L = 9 x 9 = 81cm^2

So that area of the bigger square. = 4 x area of single square

= 4 x 81 = 324cm^2

pls help with this,
find d nth term of d sequence : 9,25,47,....

mikkymax20:
From one fraction of the four square, which result to the bigger square, note;

6 + x = 4 + y (sides of square)

Taking a sketch of another circle equidistance from d bigger and d smaller circle the radius of the bigger circle will be bisect into three equal partsm

So we have

6 + x = 6 + 3 = 9

But we know;

6 + x = 4 + y

6 + 3 = 4 + y

Y = 9 - 4

Y = 5


But area of a square = L x L = 9 x 9 = 81cm^2

So that area of the bigger square. = 4 x area of single square

= 4 x 81 = 324cm^2

let me give you a hint,complete the triangle by joining the dip points,then by applying circle theorem you have the upper angle gives you 90 degrees,then you can use congruent shapes to find the radius of the larger circle and then the area of the square

DeeCherry:


yes I can but I want a full solution. pls

your question is incomplete,what are you finding?

rashywire:
pls help with this,
find d nth term of d sequence : 9,25,47,....

re-check the question guess its 9,25 ,49,. . . . it that .?

rashywire:
pls help with this,
find d nth term of d sequence : 9,25,47,....

are you sure the 3rd term of the sequence is not 49

benji93:
are you sure the 3rd term of the sequence is not 49

if its 49 then its (2n+1)^2

(12345678*12345678)-(12345676*12345680)

benji93:
(12345678*12345678)-(12345676*12345680)

what is the simplest way of solving the above

Onase:
ok.I will re.send the P.m.

OK bro.

or you cud.send it via. benbuks10@gmail.com

I I I I LOVE MATHEMATICS!

can u solve this?

http://adigunsherif.com/maths/first-maths-equation

jauntee02:
can u solve this?

http://adigunsherif.com/maths/first-maths-equation

yes.

PeyButtons:
I I I I LOVE MATHEMATICS!

I love its beauty & complexities

agentofchange1:


yes.

oya go try it!

jauntee02:


oya go try it!

why .?

kinda cheep I guess

I bought 6lamps from the market , positioned them at 6corners of a dark hexagonal-building at about 8:30pm all lamps functioning well, using all/any of the lamps . in how many ways can the building be illuminated ?


answer asap..

Type mathematics easily on my website www.adigunsherif.com/maths by typing maths e.g `sqrt(5) + int(8x)` and see it turn into real maths equatn as u submit it. Check it out now now! Maths Is interestng over there. No more take a pics. Just put ur equatn within ` not '. Test it out now.

jauntee02:
Type mathematics easily on my website www.adigunsherif.com/maths by typing maths e.g `sqrt(5) + int(8x)` and see it turn into real maths equatn as u submit it. Check it out now now! Maths Is interestng over there. No more take a pics. Just put ur equatn within ` not '. Test it out now.

wow like seriously ,..? gonna try it asap.

that's what Oga seun ought to have done here...

thanks man.

Who can please explain infinite series using covergence e.t.c.... With example

agentofchange1:
kinda cheep I guess

I bought 6lamps from the market , positioned them at 6corners of a dark hexagonal-building at about 8:30pm all lamps functioning well, using all/any of the lamps . in how many ways can the building be illuminated ?


answer asap..

56ways?

1/x[(x½/2)(1+x)-½ - (x-½/2)(1+x)½]
Pls, simplify.

please who can explain infinite series for me using convergence, divergence e.t.c with examples..

randwise:
1/x[(x½/2)(1+x)-½ - (x-½/2)(1+x)½]
Pls, simplify.

-1/{2x^2+2x^3}^1/2

randwise:
1/x[(x½/2)(1+x)-½ - (x-½/2)(1+x)½]
Pls, simplify.

solving this question for him here makes sense a lot. http://adigunsherif.com/maths/please-help-him-simplify-this I just copied the question above, wrap it in `` and see it turn into mathematics. no stress at all. so please help him solve the question by typing it and wrapping everything in ``. it's easier typing mathematics over there