fatdon2:
Op you can also slove mine.

6

3= 6

No possible three additions from the group of odd numbers will give an even number. No equation is obtainable from the available numbers. The op can try dis one


[ ] + [ ] + [ ] = 29


Fill the brackets with any three of the following numbers

2, 4, 6, 8, 10, 12, 14, 16

The answer is 6

fatdon2:
Op you can also slove mine.

fatdon2:
Op you can also slove mine.

8x7, 7x6, 5x4, 3x2=6
6

I don't know if someone has mentioned this already.
It's basic number theory.

Odd+odd=even
Even+odd=odd
Even+even=even

Therefore

Odd+odd+odd=(odd+odd)+odd=(even)+odd=odd
since all the numbers are odd and 30 is even there's no solution

Except you're looking for 15+15+0=30

fatdon2:
Op you can also slove mine.

Answer is 12

@fatdon2 15

that should be 6

fatdon2:
Op you can also slove mine.

fatdon2:
Op you can also slove mine.

The answer is 9..3X3..the second value of the product keeps decreasing from 7,6,5,4 and then 3.

fatdon2:
Op you can also slove mine.

12

fatdon2:
Op you can also slove mine.

8=56
7=42
6=30
5=20
3=6

fatdon2:
Op you can also slove mine.

the answer is 6.

fatdon2:
Op you can also slove mine.

6

Sum of three odd number can't be an even number , is a simple secondary school mathematics . However on specific assumption we can reach to a solution . We all work out numerics in decimal numeral system , here I am taking an assumption of working out this problem in Numeral system with base 9 (radix=9) . So in our base 9 numeral system
1=1
3=3
5=5
7=7
9=9
11=1*9^1 +1*9^0 =10
13=1*9^1 + 3*9^0 =12
15 = 1*9^1 + 5*9^0 = 14
30 = 3*9^1 + 0*9^0 = 27

So our problem becomes :

__ + __ + __ = 27

where __ can be filled by 1,3, 5,7,9,10,12,14,27
which leads us to the solution
1 + 12 + 14 =27 .

Now we transform our solution back to the base 10 notation :
1+13+15 =30 , where 1 ,13,15,30 are taking its numeric value according to base 9 numeral system .

olusolaj:
even Buhari no fil solve am

See your life!

fatdon2:
Op you can also slove mine.

Answer is 6

fatdon2:
Op you can also slove mine.

simple shii. Answer is 14.

lifestyle1:
6+11+13=30 simply turn 9 upside down.

Lmao!

3 odd numbers cannot give u an even number.

I have zero quantitative skills...

fatdon2:
Op you can also slove mine.

6

No point.

The addition of 3 odd numbers can never give you an even number.

gbanikiti:
Sum of three odd number can't be an even number , is a simple secondary school mathematics . However on specific assumption we can reach to a solution . We all work out numerics in decimal numeral system , here I am taking an assumption of working out this problem in Numeral system with base 9 (radix=9) . So in our base 9 numeral system
1=1
3=3
5=5
7=7
9=9
11=1*9^1 +1*9^0 =10
13=1*9^1 + 3*9^0 =12
15 = 1*9^1 + 5*9^0 = 14
30 = 3*9^1 + 0*9^0 = 27

So our problem becomes :

__ + __ + __ = 27

where __ can be filled by 1,3, 5,7,9,10,12,14,27
which leads us to the solution
1 + 12 + 14 =27 .

Now we transform our solution back to the base 10 notation :
1+13+15 =30 , where 1 ,13,15,30 are taking its numeric value according to base 9 numeral system .

Super story

Ok




Answer abeg....the thread is fast going down FP

30 is an even number, given, are all odd numbers to fill 3 slots with, but 3 is an odd number. The sum of an odd number of odd terms will always give an odd term so far the added terms are all positive.

This puzzle has no answer.

15+15+0=30 ans!

ShakurM:
[1+7] + [7+9] + [5+1] = 30!

that's 30 factorial bro..

fatdon2:
Op you can also slove mine.

Answer is 9

3 = 9

fatdon2:
Op you can also slove mine.

fatdon2:
Op you can also slove mine.

The answer is 6........3=6