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Nairaland Forum / Nairaland / General / Education / UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 (2572433 Views)
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Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 1:23pm On Apr 09, 2015 |
RobinHez:Maracana stadia, Rio De Janeiro. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 1:29pm On Apr 09, 2015 |
RobinHez:Herbert Marculey. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 1:35pm On Apr 09, 2015 |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 1:39pm On Apr 09, 2015 |
RobinHez: oh boy, so they are definitely gonna ask ds kinda questions.... Aaaah,#idd ![]() ![]() |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 1:50pm On Apr 09, 2015 |
dharay99:With Uniben, anything is possible...at least nor be geography questions na |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 1:51pm On Apr 09, 2015 |
P varies directly with R and inversely with the square of Q. p=12 when R=18 and Q =2. Find the constant, K of the variation. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 1:53pm On Apr 09, 2015 |
If (x+3) varies as y and x=3 when y=12. What is the value of x when y=8? |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 1:53pm On Apr 09, 2015 |
RobinHez:geography better jor, where i go cum get current affairs textbook now. Mo ti Ku o0 ![]() |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 2:05pm On Apr 09, 2015 |
Princecalm: (X+3)varies Y=>>x+3=(k)y••••equat1 (dat k na constant) X=3 when Y=12. That's, 3+3=(k)12=>>6=12k Ohk den 12/6=k So k na 2,k=2 So u come say what's d value of x when y=8 So carry equat1 come down, x+3=(k)y Ohk let's substitute, x+3=(2)8 x+3=16 x=16-3=>>x=13 So e com b like say X=13. #scratches head. ![]() |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 2:10pm On Apr 09, 2015 |
dharay99:To me o, no current affairs book will give u what u want just be conversant with newspapers, radio, and the internet and u'll have it all. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 2:16pm On Apr 09, 2015 |
dharay99:your answer is wrong. How did K become 2, were you not suppose to divide through by 12 but instead you divided by 6. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 2:23pm On Apr 09, 2015 |
RobinHez: ohk sha... |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 2:24pm On Apr 09, 2015 |
Princecalm:ionne get yhu, can u plz explain wid ur workings. I myt b wrong. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 2:28pm On Apr 09, 2015 |
oh yea, I dun see where I do mistake o, k should b 1/2. X go come b 3 abi.? |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by eghos12(m): 2:29pm On Apr 09, 2015 |
RobinHez: yes but as u added 1k to these(paid off ur debt because u have initially given them 1k each...so 49+1=50) u suceded in get papa full money i.e full 50k borrowed but mama still has 49k. So the question will be how can mama money become 50k again because total money paid must be equal to 100k i.e intial money borrowed @ the start i solved these using 10 pices of broom i discovered that after giving papa 5 pices mama had 4 excluding my saved one so i had to give mama my saved one to make hers five cause @ the beging of the game i had no pice of broom but man nor fit get 100k change for inside house tay solve maths na. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 2:34pm On Apr 09, 2015 |
X+3 varies directly as Y. => (x+3)=k(y) On subtituting: 3+3=k(12) =>6=12k divide through by 12. 6/12=k. K=1/2. On finding the value of x when y=8 and k = 1/2, u subtitute into the original equation. => x+3= 1/2( ![]() x+3=4 x=4-3 x=1. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 2:36pm On Apr 09, 2015 |
eghos12:Lol...u fit go borrow frm bank na |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Nobody: 2:46pm On Apr 09, 2015 |
Make a dream you have killed a man; the curious world will love your story especially when they learn that you betrayed your lover. I accepted hell the day I fell in love with you, and hell is where I reside. God has lost me. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 2:46pm On Apr 09, 2015 |
Rationalize 3/9-sqroot80. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by eghos12(m): 2:47pm On Apr 09, 2015 |
RobinHez: u get collateral make we go use |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 2:50pm On Apr 09, 2015 |
Princecalm: na for road I stop untop ds one, plz answer am urself, I wanna know. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 2:51pm On Apr 09, 2015 |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 2:58pm On Apr 09, 2015 |
If sin¤(titre)=15/17, where ¤ is acute, find tan¤. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 3:05pm On Apr 09, 2015 |
dharay99: p varies as R and inversely as Q^2 =>p=k(R)/Q^2 On subtituting. 12=18k/2^2 12=18k/4 => 12*4=18k 48=18k => k=48/18 k=8/3 |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Princecalm(m): 3:08pm On Apr 09, 2015 |
dharay99:all right, RobinHez don't you do maths. |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by dharay99: 3:17pm On Apr 09, 2015 |
Princecalm:wait o, 48=18k, Shouldn't u divide both sides wid 18.? ![]() Sumtin like k=48/18 |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 3:22pm On Apr 09, 2015 |
Princecalm:Yeah I do? Any question? |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 3:24pm On Apr 09, 2015 |
eghos12:Na...we go just tell them say 'its for educational purpose, we'll refund it back' |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 4:06pm On Apr 09, 2015 |
Princecalm:27 + 12rt5 all over 62 ? |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Onye4live(m): 4:09pm On Apr 09, 2015 |
Princecalm:K=8/3 |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by Onye4live(m): 4:13pm On Apr 09, 2015 |
Princecalm:X=-9/4 |
Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by RobinHez(m): 4:13pm On Apr 09, 2015 |
Princecalm:Tan• =sin•/cos• Sin•=15/17, cos•=8/17 Therefore, tan•=15/8 |
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