Unilag 2015/2016 Admission - Education (54) - Nairaland
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University Of Lagos UNILAG 2015/2016 Masters Degree Forms 08060777331 / Unilag 2015/2016 Pg/master Degree.prospective Applicants / Unilag 2015/2016 Jambites (2) (3) (4)
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| Re: Unilag 2015/2016 Admission by Hemmanity: 12:09am On Apr 18, 2015 |
Umartins1:I bow boss |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 12:11am On Apr 18, 2015 |
Hemmanity: Kaiii,,,, nna, see whyne things!!! Na who be boss? Btw, have you any Maths question with you? |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 1:38am On Apr 18, 2015 |
14. if the sum of the first two terms of a G.P is 3 and the sum of the second and the third terms is -6, find the sum of the first term and the common ratio. a. -5. B. 5. C. -2. D. -3 ______________________________________ a + ar = 3 ------------ (1) ar + ar2 = -6....... (2) a (1+r) = 3....... (3) ar (1+r) = -6.......(4) Eqn (4) / (3) r= -2 Sub. For r in a+ar=3 a + a(-2) = 3 a-2a=3 -a=3 a=-3 a + r = -2 + (-3) -2-3 -5 ........... Option A ________________________________________ 15. The binary operation ¤ is defined by x¤y=x +2y, find 2¤(3¤4). A. 14. B. 26. C. 24. D. 16 ________________________________________ x¤y = x+2y 3¤4 = 3 + 2(4) 3+8 =11 2¤11 2 + 2(11) 2+22 =24................... Option C _______________________________________ 16. A chord of a circle subtends an angle 120 degrees at the centre of circle of diameter 4root3cm. Calculate the area of the major sector. A. 32pi. B. 4pi. C. 8pi. D. 16pi _________________________________________ the angle of the major sector = 360-120= 240 Note: what was given is diameter. It has to be divided by 2 to get the radius. Area= titre/360 * pi r2 = 240 / 360 * pi * 2root 32 2/3 * pi * 12 24pi/3 =8pi...... Option C __________________________________________ 17. If the mid point of the line PQ is (2,3) and the point P is (-2, 1), find the coordinate of the point Q. A. (8,6) b. (5,6). C. (0,4). D. (6,5) ____________________________________________ midpoint= x1 + x2/2 , y1 + y 2/ 2 -2+x/2 = 2, 1+y/2 = 3 -2+x=4, 1+y=6 X=4+2, y=6-1 X=6, y=5 The coordinate of Q is (6, 5)... Option D _______________________________________ 18. Integrate (1+x)/x^3. dx. A. 2x^2-1/x. B. -1/2x^2 - 1/x. C. -x^2/2-1/x. D. X^2-1/x ______________________________________ 1/x3 + x/x3 = x-3 + x1-3 = x-3 + x-2 = x-3+1 / -2 + x-2+1 / -1 = -x-2 / 2 - x-1 = -1/x2/2 - 1/x =-1/x2 * 1/2 - 1/x = -1/2x2 - 1/x + K.... Option B ____________________________________________ 19. Evaluate the integral of sinx with pi/2 as the upper value and 0 as the lower value. a. -2. B. 2. C. 1. D. -1 ___________________________________________ the integration of sinx gives -cosx Pi is 180 Therefore pi/2= 90 -cos90 - (-cos0) 0- (-1). Note: cos 90=0, cos 0=1 = 1...... Option C ____________________________________ 20. The radius of a circle is increasing at the rate of 0.02 cm/s. Find the rate at which the area is increasing when the radius of the circle is 7cm. A. 0.35 cm^2/s. B. 0.88. C. 0.75. D. 0.55 ________________________________________ A= pi r2 dA/dr= 2pi r dt/dr= 0.02 dA/dt = dA/dr * dr/dt = 2 pi r * 0.02 = 2 * 22/7 * 7 * 0.02 = 44 * 0.02 = 44 * 2/100. (Because, calculator is disallowed) = 88/100 = 0.88cm2s-1.... Option B |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 2:22am On Apr 18, 2015 |
21. If Log 18 + Log 3 - Log x = 3, find x [ everything is in base 3] A. 1. B. 2. C. 0. D. 3 ________________________________________ log318 + log33 - log3x =3 Log3 (18*3)/x = 3 Log354/x = 3 33 = 54/x 27= 54/x 27x=54 X= 54/27 X= 2................ Option B ___________________________________________ 22. Factorise completely 9y^2 - 16x^2. A. (3y-2x) (3y+48). B. (3y+4x) (3y+4x). C. (3y+2x) (3y-4x). D. (3y+4x) (3y-4x) _______________________________________ very simple. Use diff of two squares. You will get option D ________________________________ 23. Evaluate 4 2 -1 2 3 -1 -1 1 3 A. 25. B. 45. C. 15. D. 55 _________________________________ 4(9+1) -2(6-1)-1(2+3) 4(10)-2(5)-1(5) 40-10-5 25........ Option A __________________________________ 24. Find the derivative of sinX/cosX A. Sec^2x. B. Tanxcosecx. C. Cosecxsecx. D. Cosec^2x ______________________________________ Since tanX= sinx/cosx, the answer is simply option A. This can be proved though. _____________________________________________ 25. Integrate cos4x A. 3/4 sin4x+k. B. -1/4sin4x+k. C. -3/4sin4x+k. D. 1/4sin4x+k ___________________________________________ |cos 4x Let u=4x du/dx = 4 dx= 4du du= dx/4 |cosu. dx/4 1/4|cosu 1/4sinu 1/4sin4x....... Option D ____________________________________ 26. If three unbiased coins are tossed, find the probability that they are all heads. A. 1/8. B. 1/3. C. 1/6. 1/9 ____________________________________ . H T H. HH HT T. HT TT HH HT. HT. TT H. HHH HHT. HHT HTT T. HHT HTT HTT TTT Possible outcome= 8 Required " = 1 1/8....... Option A _______________________________________ 27. In how many ways can a committee of 2 women and 3 men be chosen from 6 men and 5 women? A. 50. B. 200. C. 100. D. 30 _________________________________ 6C3 * 5C2 6! / 3!3! * 5! / 2!3! 6*5*4 / 3*2 * 5*4/2 20*10 200.......... Option B ___________________________________ 28. Integrate (sinx+2)dx A. Cosx+x^2. B. Cosx+2x. C. -cosx+2x. D. -cosx+x^2 _____________________________________ option C ______________________________________ 29. At what value of x does the function y=-3-2x +x^2 attain a minimum value? A. 1. B. -4. C. -1. D. 4 _________________________________________ dy/dx; -2+2x=0 2x=2 X=1.......... Option A. _________________________________________ 30. Evaluate the integral of x^3 + x^2 with 2 as the upper value and 0 as the lower value. A. 2 5/6. C. 6 2/3. D. 4 5/6. D. 1 5/6 _________________________________________ x3 + x2 X3+1/3+1 + x2+1/2+1 X4/4 + x3/3 24/4 + 23/3 - 04/4 + 03/3 16/4 + 8/3 - 0 4+ 8/3 (12+  /320/3 6 2/3...... Option B 2 Likes |
| Re: Unilag 2015/2016 Admission by Nobody: 6:48am On Apr 18, 2015 |
tundeks:I have to score 40/40 before I can be admitted?  Umartins1, thanks. 1 Like |
| Re: Unilag 2015/2016 Admission by Mrpulse911(m): 8:39am On Apr 18, 2015 |
labodinho:Oh no. I ddnt knw it was out alrdy i ddnt get d info. Yesterday I was in a bus on my way to Oyo State to get my Certificate of State of Origin when I posted last. I got to Oyo by 5pm or thereabout. I jst saw ur reply dis mawin. What do I do now Labodino, wat do u advice #perplexed |
| Re: Unilag 2015/2016 Admission by Mrpulse911(m): 8:54am On Apr 18, 2015 |
sumbody400:The answer is D |
| Re: Unilag 2015/2016 Admission by tundeks: 9:43am On Apr 18, 2015 |
Mrpulse911:it's late already, Don, t know if jamb may still extend it. |
| Re: Unilag 2015/2016 Admission by Nobody: 10:02am On Apr 18, 2015 |
Mrpulse911:correct |
| Re: Unilag 2015/2016 Admission by Nobody: 10:23am On Apr 18, 2015 |
Umartins1: 4x-16x2 is the same thing as 16x2-4x ?? Let the number to be added to the expression be u2 16x2-4x+u2=0 Therefore 162+u2 (16+u)2 (16x+u) (16+u) 256x2+32xu+u2 We now have 16x2-4x+u2=256x2+32xu+u2 Equating the middle term -4x=32xu -4x/32x=u u=-1/8 Since u=-1/8 Then u2=(-1/ 2u2=1/64[no option is correct] I'll post shortcut very soon |
| Re: Unilag 2015/2016 Admission by Nobody: 10:25am On Apr 18, 2015 |
Umartins1: 4x-16x2 is the same thing as 16x2-4x ?? Let the number to be added to the expression be u2 16x2-4x+u2=0 Therefore 162+u2 (16+u)2 (16x+u) (16+u) 256x2+32xu+u2 We now have 16x2-4x+u2=256x2+32xu+u2 Equating the middle term -4x=32xu -4x/32x=u u=-1/8 Since u=-1/8 Then u2=(-1/ 2u2=1/64[no option is correct] I'll post shortcut very soon |
| Re: Unilag 2015/2016 Admission by Nobody: 10:26am On Apr 18, 2015 |
Umartins1: 4x-16x2 is the same thing as 16x2-4x ?? Let the number to be added to the expression be u2 16x2-4x+u2=0 Therefore 162+u2 (16+u)2 (16x+u) (16+u) 256x2+32xu+u2 We now have 16x2-4x+u2=256x2+32xu+u2 Equating the middle terms -4x=32xu -4x/32x=u u=-1/8 Since u=-1/8 Then u2=(-1/ 2u2=1/64[no option is correct] I'll post shortcut very soon |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 11:45am On Apr 18, 2015 |
I don't understand the mathematical abracadabra you're performing. |
| Re: Unilag 2015/2016 Admission by Hemmanity: 11:45am On Apr 18, 2015 |
I Need to nail High @least 39/40 in pume b4 i can be admitted any help pals? |
| Re: Unilag 2015/2016 Admission by Nobody: 12:27pm On Apr 18, 2015 |
Umartins1:The question is from the nature of quadratic roots,i was asked this kind of question last year |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 12:30pm On Apr 18, 2015 |
sumbody400:Bros, if dem ask you, na the way I don solve am u go solve am. 1 Like |
| Re: Unilag 2015/2016 Admission by tundeks: 12:48pm On Apr 18, 2015 |
Hemmanity:it's very possible as well as not possible. just keep praying and read hard. |
| Re: Unilag 2015/2016 Admission by tundeks: 12:53pm On Apr 18, 2015 |
sumbody400:The answer to that question is 4, follow the method posted by Umartins1 or read those examples I posted earlier. ur abradacada seems confusing cos I wonder how u import 256x 2+32xu+u |
| Re: Unilag 2015/2016 Admission by tundeks: 12:55pm On Apr 18, 2015 |
Umartins1:he, s performing magic, let's keep our fingers crossed and be watching. |
| Re: Unilag 2015/2016 Admission by harbeemx(m): 1:01pm On Apr 18, 2015 |
Pls guy I don't know how to solve this: What is the difference in the local time between two places in latitude 55 degrees North if they are located at longitude 8 degree west and 18 degree east respectively .Pls show the workings |
| Re: Unilag 2015/2016 Admission by Nobody: 1:08pm On Apr 18, 2015 |
tundeks:lols bro ... Nobi magic o .... It seems there are some subtle part of comprehension textbook you are yet to notice .... Open your comprehension textbook [page 63] ... Success is our !!! |
| Re: Unilag 2015/2016 Admission by labodinho: 3:56pm On Apr 18, 2015 |
Mrpulse911:Oh!! So sorry about the mix up.I don't know if they'll still extend the date.Just be vigilant in case they sell the COC again. Hello,seems the COC is still on,try get it on monday or find out if it's possible. |
| Re: Unilag 2015/2016 Admission by labodinho: 3:59pm On Apr 18, 2015 |
Umartins1:I'm impressed with you effort here.Keep it rolling. |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 4:29pm On Apr 18, 2015 |
harbeemx:______________________________________________ since they are on different longitude, you have to add; 8o + 18o = 26o Remember; 1o = 4mins 4 * 26 = 104mins. |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 4:32pm On Apr 18, 2015 |
labodinho:Boss, na your steps I dey follow o. |
| Re: Unilag 2015/2016 Admission by Umartins1(m): 4:41pm On Apr 18, 2015 |
@harbeemx Roll more. |
| Re: Unilag 2015/2016 Admission by Nobody: 4:45pm On Apr 18, 2015 |
Labodinho, during hostel allocation, will all the freshers get a room(?) because i'm hearing that some didn't get last year... |
| Re: Unilag 2015/2016 Admission by labodinho: 5:40pm On Apr 18, 2015 |
FrancisTony:Allocation is based on fastest finger,server and smartness. |
| Re: Unilag 2015/2016 Admission by labodinho: 5:41pm On Apr 18, 2015 |
Umartins1:hmm...so you're into dis business too,whyning?Good work jare our Economist. |
| Re: Unilag 2015/2016 Admission by Nobody: 5:55pm On Apr 18, 2015 |
labodinho:Nice info. How many people in a room, sef?  |
| Re: Unilag 2015/2016 Admission by labodinho: 7:00pm On Apr 18, 2015 |
FrancisTony:It ranges between 4 and 8 depends on the Hall. 1 Like |
| Re: Unilag 2015/2016 Admission by Nobody: 7:29pm On Apr 18, 2015 |
labodinho:List them.  |
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