sumbody400:
If it takes 2 men 3days to make 3000 heaps in a maize farm.how many days will it take 10 men,working at the same rate to make 25,000 heaps ??

isholad1:
The is ans is 15days

Umartins1:

______________________________________________
since they are on different longitude, you have to add;
8^o + 18^o
= 26^o
Remember; 1^o = 4mins
4 * 26 = 104mins.

FrancisTony:

List them.

Umartins1:

______________________________________________
since they are on different longitude, you have to add;
8^o + 18^o
= 26^o
Remember; 1^o = 4mins
4 * 26 = 104mins.

harbeemx:

Wow..thank u so much,I av a problem with another one
In a class of 30 students, there are 10 who wear spectacles and 16 girls.There are 8 boys who do not wear spectacles. How many girls wear spectacles?

Umartins1:
@harbeemx

Roll more.

Umartins1:

___________________________________________

I'm sorry for coming late. I was watching Madrid game. Here it is.

n(u) = 30
n(girls) = 16
n(boys) = 14
n(boys that wear spec) = 6
n(girls that wear spec) = 4.
Answer is 4.


Roll more questions, bro.

sumbody400:
wrong

isholad1:
Wetin be d ansa o

sumbody400:
5 days

harbeemx:
thanks
Three times the tens digits of a two digit number is greater than the unit digit by two. When the digits are interchanged, the new number is 36 more than the original number, what is the original number

Umartins1:


let the number(not digit) be xy
Therefore, we'll have 10x+y
From the first statement;
3x = 2+y
3x-y=2 ===========> 1

From the second statement;
10y + x = 36 + 10x + y
x-10x+10y-y=36
-9x+9y=36===========> 2.

Combine equations 1 and 2

3x-y=2===========> 1
-9x+9y=36===========> 2

Multiply eqn (1) by 9 and eqn (2) by 1
27x-9y=18===========> 3
-9x+9y=36===========> 4
Add eqns (4) and (3)
18x=54
X=3

Sub for x in eqn (1)
3x-y=2
3(3)-y=2
9-y=2
-y=2-9
-y=-7
Y=7

The number is 37.


Endeavor to roll more questions.

ariyibiyomi:
Umartins, i want u to solve this questions 1. When the food bill of a family increased by 20% the family head reduced the quantity of food bought for the family by 15%, the fractional increase in the food bill is now? 2. To increase the surface area of a sphere by 69%, the percetage increasea in the diameter should be? 3.sin35/cos55 + cos 15/sin75 4. If the side of a square increases by 0.5%, find the approximate percentage increase in the area.

i want u to solve this questions

sumbody400:
More grease to your elbow bro@umartins1

pls consider the fastest way to arrive at the answer cos of the limited time of the exam.

E.g question 12,p-3=0,p=3.

3 can be substituted into the equation to arrive fast at the answer.

ariyibiyomi:
Umartins stop been oversensitive, i personally direct the questions to u cus u are d first to solve any questions posted here, i dont ave anytin against u

Since sin35=cos55
Cos55/cos55 + cos(60-45) / sin (45+30)
1 + cos60cos45 + sin60sin45 / sin45cos30 + cos45sin30

1+ 1/2*root/2 + root3/2*root2/2 / root2/2*root3/2 + root2/2*1/2

1+ (root2 + root6)/4 / (root2+root6)/4

1+1
=2.

let A be the area of the square
A=S²
dA/ds= 2s
€A= dA/ds * €s.............. (€ stands for deta)
€A=2s€s
€A/A = 2s€s/A
€A/A= 2s€s/ S²
€A/A= 2s€s/s²
€A/A= 2€s/s
But €s/s= 0.5/100
= 5/1000
€A/A= 2 * 5/1000
= 10/1000 * 100%
=1%

ariyibiyomi:
Umartins i dont knw hw to solve it, dats why i ask u to solve dem, der are jamb past questions, anyway i will check the back of the jamb pack where only d answers and not the workings are provide to see if u are right

ariyibiyomi:
U are just a genuis, u are right @ umartins

Umartins1:


Ok, then. I'm sorry.

tundeks:
are u a Stallite or an aspirant.