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Nairaland Forum / Nairaland / General / Education / *you Are Good In Math? Solve These* (733 Views)
You Said U're Good In Math Abi Oya Try This / Can You Solve These Questions? (pics) / If You Can Solve These Math Problems, You Are One Of The World's Smartest (2) (3) (4)
*you Are Good In Math? Solve These* by amhackdee(m): 8:13am On May 14, 2015 |
Solve. I notice that at the mention of these name, Front page is sure, lemme try it. Cc: Lalasticlala Fynestboi Richiez
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Re: *you Are Good In Math? Solve These* by Jadonaldson(m): 8:15am On May 14, 2015 |
How does d solving affect the price of garri? Jubilating ijebu dance first 2 comment 1 Like |
Re: *you Are Good In Math? Solve These* by Acekidc4(m): 8:15am On May 14, 2015 |
I will try and Solve it Later!! |
Re: *you Are Good In Math? Solve These* by Nobody: 8:37am On May 14, 2015 |
Cheap. |
Re: *you Are Good In Math? Solve These* by CountDracula(m): 8:43am On May 14, 2015 |
Dis is maths? Loool |
Re: *you Are Good In Math? Solve These* by Basildvalour(m): 8:47am On May 14, 2015 |
OP, is that your assignment C'mon don't be lazy, do your homework now!!! |
Re: *you Are Good In Math? Solve These* by amhackdee(m): 2:55pm On May 16, 2015 |
Acekidc4:hmmmmmmm |
Re: *you Are Good In Math? Solve These* by amhackdee(m): 2:56pm On May 16, 2015 |
Re: *you Are Good In Math? Solve These* by amhackdee(m): 2:57pm On May 16, 2015 |
CountDracula:no! It's Chemistry. |
Re: *you Are Good In Math? Solve These* by amhackdee(m): 2:58pm On May 16, 2015 |
Basildvalour:mtcheeeewwwwwwwww, some people shaa |
Re: *you Are Good In Math? Solve These* by CountDracula(m): 3:11pm On May 16, 2015 |
amhackdee:lol, come see maths |
Re: *you Are Good In Math? Solve These* by Seriallinks(m): 6:02pm On May 16, 2015 |
Question 2 2x + 32{2(-x)} - 12 = 0 Rearranging gives :::> 2x + 32(1/2x) - 12 = 0 Put 2x = s Substituting into the equation gives us::: s + 32/s - 12 = 0 s2 + 32 - 12s = 0 :. s2 - 12s + 32 = 0 Factoring gives ::: s2 - 8s - 4s + 32 = 0 s(s - 8 ) - 4(s - 8 ) = 0 :. s - 8 = 0 or s - 4 = 0 s = 8 or s = 4 Recall that s = 2x Putting back gives :::> 2x = 8 or 2x = 4 2x = 23 or 2x = 22 Thus ::::> x = 3 or x = 2 Question 4 {3n - 3(n-1)}/{33× 3n - 27 × 3(n-1)} Let's first apply the law of indices :::: 3^(n - 1) can be rewritten as ::: 3n ÷ 31 = 3n ÷ 3 So that the expression becomes ::: {3n - 3n ÷ 3}/{33× 3n - 27 × 3n ÷ 3} Then let's put 3n = s Substituting 3n = s back into the expression will give us ::: {s - (s ÷ 3)}/{33× s - 27 × s ÷ 3} Factoring s in both the numerator and denominator, gives :::: s{1 - (1/3)}/s{33 - 27/3} with s cancelling out, leaves us with:::: :. {1 - (1/3)}/{27 - 9) = (2/3)÷18 = (2/3)(1/18) = (1/3)(1/9) = 1/27 1 Like |
Re: *you Are Good In Math? Solve These* by Seriallinks(m): 6:06pm On May 16, 2015 |
Questions 1 and 3 are not clear! I will type out the solutions for 5 and 6 later! I hope it helps. |
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