Welcome, Guest: Register On Nairaland / LOGIN! / Trending / Recent / NewStats: 3,193,688 members, 7,951,858 topics. Date: Wednesday, 18 September 2024 at 05:25 AM |
Nairaland Forum / Nairaland / General / Education / Nairaland Mathematics Clinic (494715 Views)
Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
(1) (2) (3) ... (209) (210) (211) (212) (213) (214) (215) ... (284) (Reply) (Go Down)
Re: Nairaland Mathematics Clinic by agentofchange1(m): 8:47pm On Nov 22, 2015 |
uwc buddy , keep practicing,,,happy solving dprinz99: |
Re: Nairaland Mathematics Clinic by Madmathecian(m): 9:02pm On Nov 22, 2015 |
The height h in feet of a model rocket above the ground t seconds after lift-off is given by h(t) = −5t2 + 100t, if 0 ≤ t ≤ 20 And 0, if t > 20 1. Find and interpret h(10) and h(60). 2. Solve h(t) = 375 and interpret your answers. |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 10:44pm On Nov 22, 2015 |
Madmathecian:1) h(10)=-5(10)2+100(10) =-5(100)+1000 =500 implies that at t=10(tenth seconds), the rocket is 500feet in the air. h(60)=0 because wen we insert dat into d equation we get a negative result. and its not posible for a height to neative. dat implies dat at t=60 the rocket is already back to the ground and its at rest hence height is zero(0) 2)h(t)=375 implies 375=-5(t)2+100(t) dividing tru by 5 givs 75=-t2+20t making t2 positive by taking all values from the RHS to the LHS, we have t2-20t+75=0 by factorization we av t2-5t-15t+75=0 t(t-5)-15(t-5)=0 (t-5)(t-15)=0 thus t=5 or t=15 implies that at the 5th seconds(t=5) the rocket was taking off(moving upward) while at the 15th seconds(t=15) the rocket was already on its way back to the ground. (not good at physics(always d C candidate) so pardon my poor interpretation) |
Re: Nairaland Mathematics Clinic by Madmathecian(m): 11:20pm On Nov 22, 2015 |
ladokuntlad: It's not really physics, but Exponential Modelling in Mathematics. Good job though. |
Re: Nairaland Mathematics Clinic by Madmathecian(m): 11:23pm On Nov 22, 2015 |
Find and simplify the diference quotients for the following functions 1. f(x) = x2 − x − 2 2. g(x) = 3/( 2x + 1) |
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 11:30pm On Nov 22, 2015 |
ladokuntlad:Good job though but I don't totally agree with the h (60) interpretation because at t =60 the height is negative doesn't necessarily means the rocket is back to ground level it might as well means the time function is not valid for state or height of rocket at t=60 |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 11:31pm On Nov 22, 2015 |
stlaibrowne: am 10000000000000000% sure the rocket is back to d ground dats y h=0 at that point |
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 11:37pm On Nov 22, 2015 |
ladokuntlad: I am 100000000000000% sure you need to read the question again. Because actually at t=60 h is not zero but h=-12000 and that's not zero. Get my point ? |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 11:42pm On Nov 22, 2015 |
stlaibrowne:well in pure mathematics and some other mathematical methods question we have something called boundary value problems(BVP) wich involves aving some constraints/conditions on a question. Well i wont go further dan dat. let the referees in the house come and second ur opinion or mine |
Re: Nairaland Mathematics Clinic by naturalwaves: 11:43pm On Nov 22, 2015 |
@ Ladokuntlad, it is possible for height to be negative in physics particularly when an object is going up or down. If you get a negative height, it means the object is going against gavity( I.e moving up). |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 11:50pm On Nov 22, 2015 |
naturalwaves:i strongly disagree as pertaining to this particular question above. Why? since some certain condition as been given so its already under a constraint, which cant make us say its going against gravity (-g) even at -g(going against gravity) we don't get our distance to b negative. I stand to b corrected though. Bt for dis particular question above. d reason i gave is still very legit until someone comes here and give His/Her own clear reason |
Re: Nairaland Mathematics Clinic by naturalwaves: 11:55pm On Nov 22, 2015 |
ladokuntlad:Well, I am yet to check out the question itself, just saw where you wrote it can't be negative. Will check out the question tomorrow. |
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 11:55pm On Nov 22, 2015 |
ladokuntlad: I understand boundary value as also we do set up elementary volume for some mathematical method. But in the case rocket is going up against gravity. And the operation is defined with a time function. Definitely it is possible the time function fail to work |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 12:02am On Nov 23, 2015 |
Madmathecian: Difference quotients is given by f(x)=(f(x+h)-f(x))/h 1)f(x)= x2 − x − 2 let us solve in bits for simplification f(x+h)= (x+h)2 − (x+h) − 2 = (x2+2xh+h2)-x-h-2 Now lets put all dis into the difference quotients calling it a function k(x) thus k(x)=((x2+2xh+h2)-x-h-2-(x2 − x − 2))/h =(2xh+h2-h)/h =2x+h-1 2) g(x) = 3/( 2x + 1) K(x)=(3(2(x+h)+1)-1-3(2x+1)-1)/h =(3/(2(x+h)+1)-3/(2x+1))/h =((3(2x+1)-3(2(x+h)+1))/(2(x+h)+1)(2x+1)h) =((6x+3-6x-6h-3)/(2(x+h)+1)(2x+1)h) =-6h/(2(x+h)+1)(2x+1)h =-6/(2(x+1)+1)(2x+1) |
Re: Nairaland Mathematics Clinic by Madmathecian(m): 12:55am On Nov 23, 2015 |
stlaibrowne: Not that I don't understand you but you should read what ladokuntlad wrote above succinctly, they ar constraints in exponential modelling. H(60) is zero because of the strict inequality in the problem above. |
Re: Nairaland Mathematics Clinic by Nobody: 3:03am On Nov 23, 2015 |
stlaibrowne: I think you should be the one to read the question. Ladokuntlad is very correct. The height function is a parabola. It was also stated in the question that h(t)=0 when t>20. my question to you is, is 60 greater than 20? if yes please apologize to Ladokuntlad (lol). It is worth adding that at t=0 and 20 the height is zero.(this implies it goes up reaches its maximum at t=10 before coming down) the function is also symmetric. Pls try to read questions and understand the interpretation before solving. Cheers
|
Re: Nairaland Mathematics Clinic by stlaibrowne(m): 7:44am On Nov 23, 2015 |
masperano: Yeah sure I just read the question again at t>20 h will always be zero. |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 11:22am On Nov 23, 2015 |
Madmathecian: masperano:Tank u my brodas oo. Even if i no sabi physics or word problem. I really tried in dis case |
Re: Nairaland Mathematics Clinic by Laplacian(m): 5:45am On Nov 25, 2015 |
ladokuntlad:actually h(60)=0 ONLY because of the stated boundary condition, not for ANY of the reasons u stated...have a nice day&kudos |
Re: Nairaland Mathematics Clinic by Laplacian(m): 5:53am On Nov 25, 2015 |
stlaibrowne:ur interpretation is right sir...nice criticism!!! |
Re: Nairaland Mathematics Clinic by jackpot(f): 3:02pm On Nov 25, 2015 |
Setting the record straight. Weldone Laplacian for the mopping up. |
Re: Nairaland Mathematics Clinic by Nobody: 4:41pm On Nov 25, 2015 |
it might as well means the time function is not valid for state or height of rocket at t=60 Laplacian: I vehemently disagree with this, the interpretation is wrong. Even if we assume there is no boundary condition (i.e h(t)#0 when t>20). h(60) being negative can be interpreted. (It simply means you are on the cliff when you shoot the rocket, and by time 20 units the rocket reaches the height of the cliff before descending (i.e it is 12000 units below the cliff at time 60 units). |
Re: Nairaland Mathematics Clinic by Nobody: 5:09pm On Nov 25, 2015 |
So I have a joke great mathematicians(told by my pde lecturer(he is Russian)). A team of Engineers from England visited Germany and they saw a black goat. They came back and said "all goats are black in Germany" Next a team of Physicist visited Germany and they saw a black goat.They came back and said "there is one black goat in Germany". Finally a team of Mathematicians visited Germany and saw a black goat. They came back and said. "There exist at least one black goat in Germany which is black". Moral of the story always check the rightness of your statement as a scientist. Cheers my people |
Re: Nairaland Mathematics Clinic by iameugene(m): 5:11pm On Nov 25, 2015 |
K |
Re: Nairaland Mathematics Clinic by MathsChic(f): 7:05pm On Nov 25, 2015 |
masperano:Only a mathematician can tell such joke, cos it's all in favour of mathematicians. Funny, clever joke Today I was thinking something. The ratio of the circumference of a circle to its diameter is a number that doesn't occur in nature any other way, besides as a ratio of circumference to diameter. Isn't that just spectacular? Or am I wrong? Does it have other occurences? |
Re: Nairaland Mathematics Clinic by petengine(m): 11:43pm On Nov 25, 2015 |
Y=10cos(at)exp(-mt) . use newton raphson method to determine the time when the displacement fall to 4.5 m=0.7, a=4.5 initial guess ti=0.1 thanks all |
Re: Nairaland Mathematics Clinic by Nobody: 1:29am On Nov 26, 2015 |
MathsChic: Yea good question, this month i randomly bumped into a paper that stated how some Rochester University physicists by serendipity discovered the number Pi(i had thought it was always associated with geometric figures) in quantum mechanics while calculating the energy state of hydrogen atom. You may want to take a look at this website: http://www.gizmodo.com.au/2015/11/theres-a-hidden-connection-between-pi-and-quantum-mechanics/ or better still download the article from here: http://scitation.aip.org/docserver/fulltext/aip/journal/jmp/56/11/1.4930800.pdf?expires=1448498047&id=id&accname=guest&checksum=F3D4695391CC583C50ECDCDA779B6C74 The size of the article is beyond the allowable size on Nairaland else i would have attached it. |
Re: Nairaland Mathematics Clinic by LordPherule(m): 5:04am On Nov 26, 2015 |
iameugene: |
Re: Nairaland Mathematics Clinic by LordPherule(m): 5:08am On Nov 26, 2015 |
Since I've been studying Mathematics, I just realised there is cramming in Mathematics in my 3rd year. It suck! |
Re: Nairaland Mathematics Clinic by Madmathecian(m): 9:48am On Nov 26, 2015 |
LordPherule: Oh, words are not enough to describe how much I hate cramming. Especially when it comes to definitions. |
Re: Nairaland Mathematics Clinic by saipn: 11:42am On Nov 26, 2015 |
Gurus help me solve dis set question 1)A company employs 100 people,65 of whom are men. 60 people,including all the women,are paid weekly.How many of the men are paid weekly? 2)In a village all the people speak hausa or English or both.97% speak hausa and 64% speak English,what percentage speak both languages? 3)In a survey of villagers,it is found that 20% of the people have visited kano and 25%have visited portharcourt. If 5% have been to both cities,what percentage have visited neither place? |
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 1:15pm On Nov 26, 2015 |
saipn:1. 25. 2. 61%. 3. 60% |
(1) (2) (3) ... (209) (210) (211) (212) (213) (214) (215) ... (284) (Reply)
Mastercard Foundation Scholarship, Enter Here / DIRECT ENTRY Admission. / Jamb Result Checker 2012/2013 – UTME Result Checker
Viewing this topic: 1 guest(s)
(Go Up)
Sections: politics (1) business autos (1) jobs (1) career education (1) romance computers phones travel sports fashion health religion celebs tv-movies music-radio literature webmasters programming techmarket Links: (1) (2) (3) (4) (5) (6) (7) (8) (9) (10) Nairaland - Copyright © 2005 - 2024 Oluwaseun Osewa. All rights reserved. See How To Advertise. 59 |