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Re: Nairaland Mathematics Clinic by afobam(m): 11:55am On Dec 31, 2015
maths guru..... solve 3^x + 4^x =5^x.
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 12:55pm On Dec 31, 2015
afobam:
maths guru..... solve 3^x + 4^x =5^x.
Use graphical method. Mere looking gives the value of x to be 2.
Re: Nairaland Mathematics Clinic by afobam(m): 1:11pm On Dec 31, 2015
yh ure right but pls can u snap and upload that
thankyouJesus:
Use graphical method. Mere looking gives the value of x to be 2.
Re: Nairaland Mathematics Clinic by afobam(m): 1:12pm On Dec 31, 2015
is there any method apart from using graph
thankyouJesus:
Use graphical method. Mere looking gives the value of x to be 2.
Re: Nairaland Mathematics Clinic by GreatYinkus(m): 2:40pm On Dec 31, 2015
afobam:
is there any method apart from using graph
Then you can use Binomial Expansion or better still Newton's Iterative method
Re: Nairaland Mathematics Clinic by agentofchange1(m): 3:30pm On Dec 31, 2015
Re: Nairaland Mathematics Clinic by agentofchange1(m): 3:42pm On Dec 31, 2015
Q2
DatechMan:


Kindly write the questions on a paper and snap. The trig question is not clear
Re: Nairaland Mathematics Clinic by Meel: 3:53pm On Dec 31, 2015
I don come again, integrate $(sin2x)^6 and integrate sin inverse.
Re: Nairaland Mathematics Clinic by agentofchange1(m): 4:01pm On Dec 31, 2015
Sin inverse of what what ? make your question clear,better still upload a photo of it.
Meel:
I don come again, integrate $(sin2x)^6 and integrate sin inverse.
Re: Nairaland Mathematics Clinic by agentofchange1(m): 8:24pm On Dec 31, 2015
Q1
Sirneij:
No one to address these?
c DatechMan
cc Richiez

Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:10pm On Dec 31, 2015
Q3

Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:16pm On Dec 31, 2015
.

Re: Nairaland Mathematics Clinic by DatechMan(m): 7:47am On Jan 01, 2016
afobam:
is there any method apart from using graph

This is a classical example of limitations of analytical methods.
Note: Not all problems are solvable analytically or say easily solvable.

Bro, you need to solve that question using either Graphical method or Numerical methods.

The solution is quite trivial, graphically.

f(x) = 5x - 4x - 3x

Here is an online plotter. http://rechneronline.de/function-graphs/


HAPPY NEW YEAR

#GodBlessNigeria
Re: Nairaland Mathematics Clinic by DatechMan(m): 7:59am On Jan 01, 2016
Sirneij:
1. Use the principle of mathematical induction to show that the arithmetic mean is always greater than or equal to the geometric mean.
2. Prove that (3 + square root5)n + (3 - square root5)n is an even integer for all natural numbers n using the principle of mathematical Induction.
3. Use the principle of Mathematical Induction to Prove that 2002n +2 + 20032n + 1 is divisible by 4005.
4. Prove by Mathematical Induction that 1/2 + cosx + . . . + cos(n - 1)x = sinx/2(2n - 1)/2sinx/2

I must mention that some of this your questions, especially 1 - 3 need not be proved using Mathematical inductions because they are self sufficient.
Meanwhile check out agentofchange1 solutions. Ask questions if you are not clear


Q1
Agent of Change has tried to adapt the proof to Mathematical Induction.


Full proofs here. Check it out

http://www.artofproblemsolving.com/wiki/index.php?title=Proofs_of_AM-GM


Q2
agentofchange1 can you tell us why you think it is you have sufficiently proved the expression when the terms in the bracket cannot be said to be integers or Rational number to say the least.
Kindly expatiate. Because 2y is always even if only y is a non-zero integer.

Thanks
Re: Nairaland Mathematics Clinic by agentofchange1(m): 9:03am On Jan 01, 2016
yes sir , off-course 2k is always even for all non-zero k

i will post an alternative proof Asap
DatechMan:


I must mention that some of this your questions, especially 1 - 3 need not be proved using Mathematical inductions because they are self sufficient.
Meanwhile check out agentofchange1 solutions. Ask questions if you are not clear


Q1
Agent of Change has tried to adapt the proof to Mathematical Induction.


Full proofs here. Check it out

http://www.artofproblemsolving.com/wiki/index.php?title=Proofs_of_AM-GM


Q2
agentofchange1 can you tell us why you think it is you have sufficiently proved the expression when the terms in the bracket cannot be said to be integers or Rational number to say the least.
Kindly expatiate. Because 2y is always even if only y is a non-zero integer.

Thanks
Re: Nairaland Mathematics Clinic by Orthega: 12:20pm On Jan 01, 2016
Show that 3^4n+2 + 2.4^3n+1 is exactly divisible by 17 if n is a positive integer. Pls do not write snap because i'm using small phone but kindly type. Ur solution will highly be appreciated.
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 1:28pm On Jan 01, 2016
Orthega:
Show that 3^4n+2 + 2.4^3n+1 is exactly divisible by 17 if n is a positive integer. Pls do not write snap because i'm using small phone but kindly type. Ur solution will highly be appreciated.
my flex small,
from the question using mathematical induction,
3(4n+2) + 2.4(3n+1).
When n=1,
3(4(1)+2) + 2.4(3(1)+1)=1241.
The answer is divisible by 17.
Show for when n=2.
For nth term,
3(4n+2) + 2.4(3n+1).
For (n+1)th term,
3(4(n+1)+2) + 2.4(3(n+1)+1).
3(4n+4+2) + 2.4(3n+3+1).
3(4n+6) + 2.4(3n+4).
Since (n+1)th term is true for all n which is a positive integers, then,
3(4n+2) + 2.4(3n+1) is divisible by 17.
Re: Nairaland Mathematics Clinic by Timothy3113(m): 2:50pm On Jan 01, 2016
Pls help out

Re: Nairaland Mathematics Clinic by thankyouJesus(m): 4:49pm On Jan 01, 2016
Timothy3113:
Pls help out
$sin-1x dx =
$1 X sin-1x dx.
By integration by part.
let u=sin-1x.
sinu = x------------(1).
u' cosu = 1.
divide both sides by cosu.
u' = 1/cosu.--------(2).
Recall that sin2u + cos2u = 1.
cosu = sqrt 1 - sin2u.
from (1).
cosu = sqrt 1 - x2.
into (2).
u' = 1/sqrt 1 - x2.
Let dv = 1 dx.
v = x.
$udv = uv - $vdu.
You should be able to continue from here, if not, go to number 3 solution.

1 Like

Re: Nairaland Mathematics Clinic by thankyouJesus(m): 5:01pm On Jan 01, 2016
$x/sqrt (1-x2 dx.
Let u = 1 - x2.
Du/dx = 2x.
Dx = du/2x.
Substituting back into the question.
$(x/sqrt u) du/2x.
1/2$1/sqrt u du.
1/2$u-1/2 du.
You should be able to continue from here, sorry about the rough work, my phone is not ........................
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 5:16pm On Jan 01, 2016
$sin62x dx. $(sin22x)3 dx. Recall that. Cos4x = cos (2x + 2x). Cos4x = cos22x - sin22x. Cos4x = 1 - 2sin22x. Sin22x = (1-cos4x)/2. You should be able to continue from here.
Re: Nairaland Mathematics Clinic by GreatYinkus(m): 5:34pm On Jan 01, 2016
@Timothy, thankyouJesus has done primarily all the work, but in case you need answers to cross check:

1. xSin-1x + √(1-x2) + c

2. 1/8[(5/2)x-Sin4x+(3/16)Sin8x+(1/12)Sin34x] + c

3. -√(1-x2) + c
.
I just hope I've not made any mistake undecided
Re: Nairaland Mathematics Clinic by Orthega: 10:22pm On Jan 01, 2016
thankyouJesus:
my flex small,
from the question using mathematical induction,
3(4n+2) + 2.4(3n+1).
When n=1,
3(4(1)+2) + 2.4(3(1)+1)=1241.
The answer is divisible by 17.
Show for when n=2.
For nth term,
3(4n+2) + 2.4(3n+1).
For (n+1)th term,
3(4(n+1)+2) + 2.4(3(n+1)+1).
3(4n+4+2) + 2.4(3n+3+1).
3(4n+6) + 2.4(3n+4).
Since (n+1)th term is true for all n which is a positive integers, then,
3(4n+2) + 2.4(3n+1) is divisible by 17.
Tnx bt d soln is not complete.
Re: Nairaland Mathematics Clinic by Orthega: 10:25pm On Jan 01, 2016
agentofchange1:
Q2
pls, let ur soln to be clear as that of timothy 3113. Ur kindness will highly be appreciated,tnx.
Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:14am On Jan 02, 2016
ok
Orthega:
pls, let ur soln to be clear as that of timothy 3113. Ur kindness will highly be appreciated,tnx.

Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:34am On Jan 02, 2016
gat all solutions here bt the network is too poor over here ,will upload later
Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:39am On Jan 02, 2016
you are correct bro,
GreatYinkus:
@Timothy, thankyouJesus has done primarily all the work, but in case you need answers to cross check:

1. xSin-1x + √(1-x2) + c

2. 1/8[(5/2)x-Sin4x+(3/16)Sin8x+(1/12)Sin34x] + c

3. -√(1-x2) + c
.
I just hope I've not made any mistake undecided
Re: Nairaland Mathematics Clinic by agentofchange1(m): 12:01pm On Jan 02, 2016
here,
Timothy3113:
Pls help out

1 Like

Re: Nairaland Mathematics Clinic by agentofchange1(m): 12:04pm On Jan 02, 2016
Q2










Q3 ( Check (*) ) above

Re: Nairaland Mathematics Clinic by agentofchange1(m): 12:22pm On Jan 02, 2016
here

Re: Nairaland Mathematics Clinic by ladokuntlad(m): 12:32pm On Jan 02, 2016
.
Re: Nairaland Mathematics Clinic by Nobody: 6:17am On Jan 03, 2016
eche45:
Have being following this thread.
But this my 1st time of posting here.
I must say u guy are doing a great job. Watch out for my own questions o. Me too will b trying to solve some issue here.
Thanks.
Yet u criticize mathematician nd compare dem to economists, why dont you use ur dumb engineering brain nd solve all ur math problem. Crystallised creatinous fvcktard

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