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Who Can Solve This Simple Maths? / Please Help Me Out With This Simple Maths Assignment / Simple Maths That Brings Much Argument (2) (3) (4)
Solve This Simple Maths by Nobody: 5:42pm On Jan 07, 2016 |
A contractor agreeing to finish a work in 150
days employed 75 men each working 10 hours
daily. After 90 days, only 1/4 of the work was
completed. Increasing the number of men by
…………. each working now for 15 hours daily, the
work can be completed in time. 1 Like |
Re: Solve This Simple Maths by Nobody: 5:44pm On Jan 07, 2016 |
CarlOzeki, Snowland, Tinkybabe, flawlesRebirth, misshoree, seun, Lalasticlala, Mynd44, eroticangel, paranorman, vengeance, kobonaire.... YOUR ATTENTIONS ARE NEEDED |
Re: Solve This Simple Maths by Kenzico(m): 5:55pm On Jan 07, 2016 |
Am not good in maths....But this one looks sweet |
Re: Solve This Simple Maths by chiefolododo(m): 6:16pm On Jan 07, 2016 |
hopelink1:you come dey mention Lalasticlala? |
Re: Solve This Simple Maths by denniece1(m): 6:29pm On Jan 07, 2016 |
150men |
Re: Solve This Simple Maths by paranorman(m): 7:03pm On Jan 07, 2016 |
hopelink1:dude, the trick in solving this kinda question is to quantify the amount of work done or to be done yourself, if you cannot solve it straight. Say total work to be done is 10000kg. For 150 days, twil take (100000/150)kg per day. So, after 90 days, 1/4 of the work was done= 1/4(10000)kg=2500kg work/day = (2500/90)kg work/day/man = (2500/90)/75 work/day/man/hours=((2500/90)/75))/10= quantity of work that can be done per man for an hour. According to contract, (150-90) days left, work is to be completed in 60days. Work left to be done is 10000-2500; after you have found work/day/man/hours, calculate amount of work done by a man for 15 hours. Remember, new men will be added. From this info, you should to able to manipulate and get your answer. |
Re: Solve This Simple Maths by chiefolododo(m): 7:56pm On Jan 07, 2016 |
Kenzico:guy you no sabi |
Re: Solve This Simple Maths by Sibrah: 8:27pm On Jan 07, 2016 |
You increase the No of men by minimum of 18.85 but since men cannot be in fraction and question require the " additional number of men required to complete the job on time" it is 19 at minimum. 19 The question should be modified to request the minimum number of men request cos if any one gives an answer greater than the minimum required it will satisfy the condition that request "the number of men to be added to complete the job on time" |
Re: Solve This Simple Maths by Nobody: 8:32pm On Jan 07, 2016 |
Sibrah:you are wrong |
Re: Solve This Simple Maths by Sibrah: 8:41pm On Jan 07, 2016 |
hopelink1:I did a quick cross-check. It is 19 men to be added to 75 on ground. 19 or 94 depending on how you see it. |
Re: Solve This Simple Maths by Nobody: 9:55pm On Jan 07, 2016 |
chiefolododo:lala no know mathematics? |
Re: Solve This Simple Maths by Nobody: 9:56pm On Jan 07, 2016 |
paranorman:ans only |
Re: Solve This Simple Maths by Damfash(m): 10:45pm On Jan 07, 2016 |
. |
Re: Solve This Simple Maths by Damfash(m): 11:07pm On Jan 07, 2016 |
Definitely 150 men. Let me try and explain this in a simple way. The first set of men spent 900 hours (10 hours each day for 90 days). The second set of men also spent 900 hours(15 hours each day for 60 days). Knowing that they spent the same number of hours, if the first group (comprising 75 men) could do one quarter of a work, how many men would do three quarters (the remainder) of that same work under the same duration? This will be (75*3)=225. So, 225 men finised the work. By now, I hope you agree with me that 150 men were added. 1 Like |
Re: Solve This Simple Maths by Damfash(m): 3:52pm On Jan 08, 2016 |
. |
Re: Solve This Simple Maths by Nobody: 4:41pm On Jan 08, 2016 |
Damfash:yea |
Re: Solve This Simple Maths by Sibrah: 5:58pm On Jan 08, 2016 |
hopelink1:Provide a convincing explanation please. I believe your question isn't clear enough. |
Re: Solve This Simple Maths by octalbell(m): 9:55pm On Jan 08, 2016 |
This is my solution
|
Re: Solve This Simple Maths by Nobody: 10:48pm On Jan 08, 2016 |
octalbell:wrong 1 Like |
Re: Solve This Simple Maths by Nobody: 11:02pm On Jan 08, 2016 |
Sibrah:1/4(x) is equivalent to 90days x 10hours x 75men and 3/4(x) is equivalent to 60days x 15hours x W men. Taking ratio of These equation i. E 1 ---x = 90 x 10 x 75 4 --- - - - - - - - - - - 3 --x = 60*15*W 4 W, the total number of men to complete the job from This equation is 225, Therefor it requires (225--75)=150men to complete 3/4 of the work in the remaining 60 days if They work for 15hours per day |
Re: Solve This Simple Maths by Sibrah: 3:45am On Jan 09, 2016 |
hopelink1:I followed a similar principle with MS Excel but end up having a diff ans. Must have mixed things up somewhere. |
Re: Solve This Simple Maths by misshoree(f): 9:47am On Jan 11, 2016 |
hopelink1:Am not a mathematician, I deal with drugs |
Re: Solve This Simple Maths by Nobody: 8:33pm On Jan 12, 2016 |
misshoree:hard drugs |
Re: Solve This Simple Maths by Nobody: 8:33pm On Jan 12, 2016 |
misshoree:hard drugs? |
Re: Solve This Simple Maths by Tinkybabe(f): 11:34am On Jan 31, 2016 |
CarlOzeki, Snowland, Tinkybabe, flawlesRebirth, misshoree, seun, Lalasticlala, Mynd44, eroticangel, I'm sorry, just seeing the mention. Ans= 150 Let total work to be completed be X It takes 75 men 10 hours to complete X/4 work in 90days 750 hrs x 90 = X/4 X =270,000 arbitrary unit We have only (150- 90)days left to complete the work at 15 hours per person. If total no of people required to complete the remaining job is R Then 15R x 60 =3/4 X Note X =270,00 R = 225 Men to be added to previous is 225- 75 = 150 men |
Re: Solve This Simple Maths by paranorman(m): 11:58am On Jan 31, 2016 |
Tinkybabe:brilliant gurl! |
Re: Solve This Simple Maths by Tinkybabe(f): 12:12pm On Jan 31, 2016 |
Re: Solve This Simple Maths by paranorman(m): 12:16pm On Jan 31, 2016 |
Tinkybabe:honestly, I admire you maths skills. That question you just solved, I hate its likes mehn.. Infact, I gotta do some 'quantifying' before solving such. How have you been? |
Re: Solve This Simple Maths by kobonaire(m): 5:17pm On Jan 31, 2016 |
@Tinkybabe solution is spot-on. I question the legality/ability of people to work 15 hour days for 60 days continually ... |
Re: Solve This Simple Maths by Tinkybabe(f): 2:57pm On Feb 03, 2016 |
Thanks Paranorman. kobonaire: Legality is indeed questionable but ability is not only possible but happening . How are you? |
Re: Solve This Simple Maths by kobonaire(m): 4:04pm On Feb 03, 2016 |
Tinkybabe:I'm fine thank you my dear, keep up your great work of rockin' in Mathematics and sharing your knowledge... |
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