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Physics Problem by profftrojahn: 7:34pm On Apr 07, 2016 |
A ball is dropped from rest vertically from a distance of 1.0m and rebounds to a distance of 0.67m.calculate its velocity before it rebounds and its velocity jxt after it rebounds. ![]() |
Re: Physics Problem by Nobody: 8:35pm On Apr 07, 2016 |
Before it rebounds. . . Using the formula: V^2=U^2+2gS U=O g=10m/s^2 S=1.0m v=? V^2 = u^2+2gS =2×10×1 =20 Therefore, V=√20 I just did it online... No rough work, so If I'm wrong, kindly correct me. |
Re: Physics Problem by profftrojahn: 8:49pm On Apr 07, 2016 |
ERUDITEE:its correct bt wat of d other velocity |
Re: Physics Problem by Nobody: 10:18pm On Apr 07, 2016 |
profftrojahn:here's other part- After Rebound... V^2=U^2 + 2gh since the ball rebounds dat means it goes up,thus making it to have accelaration due to gravity (g) to be negative. g= -10 h=0.67 V=0 (because the ball is going up) substitute values in d formular... 0=U^2 - 2*10*0.67 U^2=13.4 so U= square root of 13.4 So U=3.66. Sorry fr any mistake I made in ma language n if am wrong pls tell...cos I knw dis is correct |
Re: Physics Problem by profftrojahn: 12:45pm On Apr 09, 2016 |
Grammyz:its correct |
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