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Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 - Education - Nairaland

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Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 by ostechno(m): 2:39pm On Dec 10, 2016
1. x^4+3x^3+8x^2+10x+8=0
Re: Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 by Kowor(f): 3:27pm On Dec 10, 2016
forward it to math section.
Re: Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 by Akious2k2(m): 4:53pm On Dec 10, 2016
ostechno:
1. x^4+3x^3+8x^2+10x+8=0
Mr Oga, use Remainder Rule,
Substitute x=1, -1, 2, -1, etc till u get 0 (Zero);
Oya,
If x=1,
1+27+64+10+8=0
If x=-1
1-27+64-10+8=0
Assuming u got 0 when x=k, den (x-k) is a factor
Assuming u got 0 when x=-k, den (x+k) is a factor
From there, all u need do is to divide that expression by your (x+k) or (x-k)
After dividing, u will b left with a polynomial starting with d power of 3 (Note dat there will b no remainder since (x+k) or (x-K) is a factor)
Repeat d step again from
Substitute x=1, -1, 2, -1, etc till u get 0 (Zero);
Assuming u got 0 when x=k, den (x-k) is a factor
Assuming u got 0 when x=-k, den (x+k) is a factor
From there, all u need do is to divide that expression by your (x+k) or (x-k)
After dividing, u will b left with a polynomial starting with d power of 2 (Note dat there will b no remainder since (x+k) or (x-K) is a factor)
Then u can solve d rest (Quadratic Equation) like we were taught in secondary school...
Cheers

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