please this mathematics has been given me tough time and headache, please I would be very greatful to any kind hearted individual who can assist me with the solution

image

please if you have any idea on any one please kindly, show it here I will be very greatful,,,,,

Brb
Meanwhile, question 15 (b), that is an equilateral triangle, so all sides are same length, i.e 63cm and all angles are same i.e 60 degrees.

Brb for 15 (a) but question 16 is not clear.

sorry I would have helped but but am not in the field ,,,,

nextprince:
Brb

thank you sir,, am very greatful,,,

bestguycheat:
thank you sir,, am very greatful,,,

15 (b) solved, check.

5minutes, expect 15 (a) but 16 is not clear.

nextprince:

15 (b) solved, check.

5minutes, expect 15 (a) but 16 is not clear.

bestguycheat:
thank you sir,, am very greatful,,,

wow thanks sir,,,, please number 16 is not among ,

bestguycheat:
wow thanks sir,,,, please number 16 is not among ,

Stated dimensions in 15 (a) are not correct.
Size of angles and lengths of opposite sides are not proportionate.

vii, on the second image.

15x + 10 = 8x + 14 +20x - 5

13x = 1

x = 1/13

nextprince:

Stated dimensions in 15 (a) are not correct.
Size of angles and lengths of opposite sides are not proportionate.

vii, on the second image.

15x + 10 = 8x + 14 +20x - 5

13x = 1

x = 1/13

well noted sir,,,,,, I wonder what this lecturer set to gain by giving me what is not correct ,,,,,, ,,,,,,, thank you sir,,,,,...

bestguycheat:
please this mathematics has been given me tough time and headache, please I would be very greatful to any kind hearted individual who can assist me with the solution

15) is called a similar triangles and to resolve this, do the following
6/3=63/x
2=63/x.. When you cross multiple, you will have?
X=63/2=31.5
Therefore,
X=31.5....

To get y do same as follows
6/7=63/y
When you do cross multiplication you will get the following
Y=(63*7)/6
Y=441/6
Y=73.5
QED


The next question is resolved as follows...
Recall that Ext angle is equal to sum of opposite angles,
Thus,
15x+10=(20x-5)+(8x+14)
15x+10=20x-5+8x+14 by opening the brackets
15x+10=20x+8x+14-5 by collecting the like terms
15x+10=28x+9 collect like terms again
15x-28x=9-10
-13x=-1.
Duvide both side by - 13.
Thus,
X=1/13
QED

Types of lines
1)Vertical lines
2)horizontal lines
3)parallel lines
4)perpendicular lines

Diligentpays:
15) is called a similar triangles and to resolve this, do the following 6/3=63/x 2=63/x.. When you cross multiple, you will have? X=63/2=31.5 Therefore, X=31.5....
To get y do same as follows 6/7=63/y When you do cross multiplication you will get the following Y=(63*7)/6 Y=441/6 Y=73.5 QED

wow am so very greatful indeed sir for your assistance,