just a simple but powerful function to improve our coding skills


beginners onlys

so the function will do the following

when given a two parameters the first will be a word and second will be a sentence

it should be able to detect that the word is in the sentence example

function find("boy","obi is a boy"
{
code........

return 0 or 1
}

the function will return 0 or 1
0 if word not found in the sentence
1 if word is found in the sentence


contest is closing on 3rd of this month

Note : you are not allowed to use any inbuilt library or functions just from scratch code every thing




some time similar to str.find()

in python


any language is welcomed but c and c ++ Will be more interesting






pros are not welcomed

just New coders




SINCE WE DO NOT HAVE A WINNER

I WILL LIKE TO Honor THIS GREAT PROGRAMMERS

1.justanALIAS (golang)

2.jidez007 (c++)


please drop your numbers for a little appreciation









SOLUTION IN C language

#include <stdio.h>



//FUNCTION THAT CHECKS if a phrase exists in sentence

int found(char* phrase,char *sentence)
{
    //one line function to check lenght
    int len(char*item){int t=0;while(item[t] !='\0')t++;return t;}

     // ckecking length
    int sent_len = len(sentence);
    int word_len = len(phrase);

    //variables for keeping records and also indexing through string array
    int c=0,j=0,chk=0;

    //for loop to loop through sentence
    for(c=0;c<sent_len;c++)
    {


        //check if phrase[0] is equal to sentence[c]
    	if(phrase[j]==sentence[c])
    	{
    	    /*if sentence[c-1] is not  a whitespace ,and also j==0 and c not ==0
    	    that mean that the phrase is just similar word like 'to' and 'toy' to avoid it such scenario this if statement is must
                */

    	    if(sentence[c-1] !=32 & j==0 & c !=0)
    	    {
    	        break;
    	    }

    	    //if above evaculation is false then this one increment this record variables
    	    else
            {
                chk+=1;
                j+=1;
            }


		}

		/*
		while matching word like 'toma' against 'toys' once it match 'm' to 'y'
            it will reset record variable to null and it means not matched

            */
		else
		{
			chk=0;
			j=0;
		}


        //if chk record variable is equal to phrase lenght then break loop because a match found
		if((chk==word_len)&(sentence[c+1]==32))
		{

			break;
		}



    }

    if(chk==len(phrase))
        return 1;
	else
        return 0;

}


int main()
{

    char r[]="boy are goo";
    char t[] = "d boy you boy are goo d";
    printf("%d ",found(r,t));
    return 0;
}

3days for the contest to run

And of course I will be umpire. . .

Clarify please. Custom functions that don't call library function?

I Really Dont Understand D Question Fully, Can U Explain Better Pls

Jaddo19:
I Really Dont Understand D Question Fully, Can U Explain Better Pls

I hope you understand it now

Desyner:
Clarify please. Custom functions that don't call library function?

just a custom function but no library or inbuilt function

#python 3.x
def wordsearch(x, sent):
for x in sent:
return 1
break
else: return 0

x = input('word: ')
sent = input('sentence: ')
wordsearch(x, sent)

Welete:
#python 3.x
def wordsearch(x, sent):
for x in sent:
return 1
break
else: return 0

x = input('word: ')
sent = input('sentence: ')
wordsearch(x, sent)

nairaland is messing with my indentation..

Using Php
.
.
<?Php
If (strpos("is This What You Want","What"){
Echo true;
}else{
Echo (int)false;
}
?>

Jaddo19:
Using Php
.
.
<?Php
If (strpos("is This What You Want","What"){
Echo true;
}else{
Echo (int)false;
}
?>

great but no inbuilt function or library and fancy operator

https://msdn.microsoft.com/en-us/library/2hxce09y(v=vs.90).aspx?_e_pi_=7%2CPAGE_ID10%2C1207831521

Welete:


nairaland is messing with my indentation..

no fancy operator

Welete:
#python 3.x
def wordsearch(x, sent):
for x in sent:
return 1
break
else: return 0

x = input('word: ')
sent = input('sentence: ')
wordsearch(x, sent)

in operator a membership operator only in python I consider it inbuilt function

dhtml18:
And of course I will be umpire. . .

the troll master

package main

import(
"fmt"
"strings"
)
func main(){
if check("justanALIAS", "justan") == 1 {
fmt.Println("success")
}else {
fmt.Println("failure")
}
func check(main string, sub string) int {
if strings.Contains(main, sub){
return 1
}else {
return 0
}
}

justanALIAS:
package main

import(
"fmt"
"strings"
)
func main(){
if check("justanALIAS", "justan" == 1 {
fmt.Println("success"
}else {
fmt.Println("failure"
}
func check(main string, sub string) int {
if strings.Contains(main, sub){
return 1
}else {
return 0
}
}

Golang

golang hard ooo

silento:
golang hard ooo

not true oo

Python 3.5
Check the attached image

python user without the help of in operator rewrite you code

^^^Na wa o!

in Kotlin

//using std library
var haystack = "hello NL geeks"
assertEquals("geek", haystack.contains("geek" ) )

//OR 
assert("NL" in haystack)

^^^Yah!

mustaphagreens:
Please check the attached images. Nairaland clearly does not allow for indentation.

Language: Python
Version: 3.0
Using the in operator
def findString(x,y):
if x in y:
return 1
else:
return 0

#an instance of findString
print(findString("boy","I am a boy" ))



Done!!!
Check out the code below or in the second image
#findString without the in operator

def findString(x,y):
i=0
p=""
while i<=len(y)-1:
if (y[i]!=" " and p!=x):
p+=y[i]
i+=1
elif p==x:
return 1
else:
i+=1
p=""
if p==x:
return 1
else:
return 0

#client program invoking findString
x=input("enter target word:" )
y=input("enter phrase or sentence:" )
print(findString(x,y))

wow that's great nice indentation in your code

But can you rewrite the code so that if Len()

will not be there

the essence of this contest is to make you understand what happen beneath the standard libraries and function

anyway you will do great things in python keep on trying you got the heart of a coded indeed

Sorry just seeing this, I will post mine the goal is no inbuilt function and yet people still using contains and strpos this is why Nigerians fail algorithm test, even the interview we conducted we spelt it out loud and yet still the same thing.

pcguru1:
Sorry just seeing this, I will post mine the goal is no inbuilt function and yet people still using contains and strpos this is why Nigerians fail algorithm test, even the interview we conducted we spelt it out loud and yet still the same thing.

nawa the tire me ooo

package main

import (
"fmt"
)
// i made my own len() method
func length(dstring string) int {
var counter int
for range dstring {
counter++
}
return counter
}
func main() {
mainstr := "i am a bon boi"
substr := "boi"
fmt.Println(check(mainstr, substr))
}
func check(mainstr string, substr string) int {
var status bool = false
for i, _ := range mainstr {
if mainstr[i] == substr[0] {
last := length(substr)
di := i + last
if substr == mainstr[i:di] {
status = true
} else {
continue
}
}
}
if status {
return 1
} else {
return 0
}
}

justanALIAS:
package main

import (
"fmt"
)
// i made my own len() method
func length(dstring string) int {
var counter int
for range dstring {
counter++
}
return counter
}
func main() {
mainstr := "i am a bon boi"
substr := "boi"
fmt.Println(check(mainstr, substr))
}
func check(mainstr string, substr string) int {
var status bool = false
for i, _ := range mainstr {
if mainstr[i] == substr[0] {
last := length(substr)
di := i + last
if substr == mainstr[i:di] {
status = true
} else {
continue
}
}
}
if status {
return 1
} else {
return 0
}
}

range
is inbuilt operator in golang can you scrap it

silento:

range
is inbuilt operator in golang can you scrap it

I dont think so but i will try. By the way, the above code is buggy; see d fixed version:


package main

import (
"fmt"
)
func length(dstring string) int { // i made my own len() method
var counter int
for range dstring {
counter++
}
return counter
}
func main() {
mainstr := "i am a bon boni"
substr := "i am"
fmt.Println(check(mainstr, substr))
}
func check(mainstr string, substr string) int{
var status bool = false
for i, _ := range mainstr {
if mainstr[i] == substr[0] {
if length(mainstr[i:]) >= length(substr) {
last := len(substr)
di := i + last
var rangeof string = mainstr[i:di]
if substr == rangeof{
status = true
} else {
continue
}
} else {
continue
}
}
}
if status {
return 1
} else {
return 0
}
}

justanALIAS:

I dont think so but i will try. By the way, the above code is buggy; see d fixed version:


package main

import (
"fmt"
)
func length(dstring string) int { // i made my own len() method
var counter int
for range dstring {
counter++
}
return counter
}
func main() {
mainstr := "i am a bon boni"
substr := "i am"
fmt.Println(check(mainstr, substr))
}
func check(mainstr string, substr string) int{
var status bool = false
for i, _ := range mainstr {
if mainstr[i] == substr[0] {
if length(mainstr[i:]) >= length(substr) {
last := len(substr)
di := i + last
var rangeof string = mainstr[i:di]
if substr == rangeof{
status = true
} else {
continue
}
} else {
continue
}
}
}
if status {
return 1
} else {
return 0
}
}

ok

I'm more of an amateur than a newbie (sort of) but it took longer than I expected, and more iterations than I anticipated (still have them in Sublime Text), but I finally did it. This is in JavaScript:

function find (word, text)
{
let index = 0;
let lastIndex = 0;
let startIndex = 0;
let placeholder = "";

while (startIndex < text.length && placeholder !== word)
{
lastIndex = startIndex + (word.length - 1);

if (word[index] === text[startIndex] && word[word.length - 1] === text[lastIndex])
{
for (startIndex; startIndex <= lastIndex; startIndex++)
{
if (word[index] === text[startIndex])
{
placeholder += word[index];
index++;
}
else
{
index = 0;
placeholder = "";
startIndex = lastIndex;
}
}
}
else
{
startIndex++;
}
}

return (placeholder === word) ? 1 : 0;
}

You can test it yourself with your browser (Chrome; any browser really but the shortcut is for Chrome) if you're using a PC.

- Press Ctrl + Shift + J in any open tab
- Copy and Paste the above code into the console and hit the Return/Enter key
- Type find("whatever word you want to find", "whatever sentence you want the word to be found in" ) into the console and hit the Return/Enter key.

OK. Here are the shortcuts for all (most) browsers to open the console:

Chrome and Firefox - Ctrl + Shift + J
Edge and IE - F12, then select "Console"