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Re: Nairaland Mathematics Clinic by personal59: 9:55pm On Aug 21, 2017
joshuakdboy:


The picture isn't clear. forward it to my whatsapp on 09056880123 let me help you with it.

Re: Nairaland Mathematics Clinic by personal59: 5:31pm On Aug 22, 2017
Festy4u:

Let y=Log(2x-1) to base 10
Therefore, 10^y = 2x-1
Take the natural log of both sides
Ln 10^y = Ln (2x-1)
Y Ln10 = Ln (2x-1)
Take the derivative of both sides wrt x
(dy/dx) Ln10 + 0 = (1/2x-1)x 2
Therefore, dy/dx =( 2/2x-1)(1/Ln10)
naturalwaves:

4 workers get paid 160,000 for 5 days
1 worker will get paid 40,000 for 5 days
1 worker will get paid 8000 for 1 day
5 workers will get paid 8000*5 for 1 day
Therefore,
5 workers will get paid 40,000 for 1 day
masperano:


-1/(x^2-3x+2)^0.5
Please help me out its urgent
tobillionaire:
use maclaurims series to expand ln(√x+1/√x-1) to the term x^7
use D'alemberts ratio test to fiind if
(-1)^n-1.n÷n²+1 diverges or converges pls help bosses
Please help me out its urgent

Re: Nairaland Mathematics Clinic by personal59: 11:01pm On Aug 22, 2017
Re: Nairaland Mathematics Clinic by Nobody: 11:24pm On Aug 22, 2017
personal59:
Please help me out its urgent Please help me out its urgent

my whatsapp number was there, I don't always put out my number on social media but I wanted to help you. I check Nairaland mostly at nights. if it were really urgent, you'd have forwarded it to my whatsapp.

nonetheless I'd provide the solution here for you now. I hope it isn't late.
Re: Nairaland Mathematics Clinic by Nobody: 11:35pm On Aug 22, 2017
[quote author=personal59 post=59701212][/quote]

On Question 1, I changed x to a. it looks more reasonable that way. just follow up and ask any questions you have.

more solutions are coming.

I post anyone I finish

1 Like

Re: Nairaland Mathematics Clinic by Nobody: 11:55pm On Aug 22, 2017
Number 4, 5 and 6 @personal59

Re: Nairaland Mathematics Clinic by Nobody: 12:09am On Aug 23, 2017
It's time for my night meditation. I will continue at dawn.

1 Like

Re: Nairaland Mathematics Clinic by personal59: 9:14am On Aug 23, 2017
joshuakdboy:
It's time for my night meditation. I will continue at dawn.
thank u bro
Re: Nairaland Mathematics Clinic by personal59: 9:20am On Aug 23, 2017
joshuakdboy:
It's time for my night meditation. I will continue at dawn.


am submitting it tomorrow. morning on d whatsapp am having issue with my what'sapp application that's y I post it here
Re: Nairaland Mathematics Clinic by naturalwaves: 10:31am On Aug 23, 2017
personal59:



am submitting it tomorrow. morning on d whatsapp am having issue with my what'sapp application that's y I post it here
Which ones are yet to be unsolved? Let me know. Everyone seems busy nowadays. Sorry I am just seeing this. Hope it is not too late?
Re: Nairaland Mathematics Clinic by personal59: 10:22pm On Aug 23, 2017
naturalwaves:

Which one uses yet to be unsolved? Let me know. Everyone seems busy nowadays. Sorry I am just seeing this. Hope it is not too late?


12345 av been done
Re: Nairaland Mathematics Clinic by naturalwaves: 2:19pm On Aug 24, 2017
personal59:



12345 av been done
Okay. Here is number 10.

Re: Nairaland Mathematics Clinic by naturalwaves: 2:34pm On Aug 24, 2017
No 10 continued

Re: Nairaland Mathematics Clinic by coliboyswag: 2:35pm On Aug 24, 2017
please I need a quick answer On this inequalities 1/3x+1/4<3x/8
Re: Nairaland Mathematics Clinic by naturalwaves: 3:03pm On Aug 24, 2017
Number 7
If 3 dice are thrown together,
The only combinations that can give a total of 10 are;

6,3,1

5,4,1

4,4,2

3,3,4

2,2,6

5,3,2



Note that, for each of these combinations, the dice can come in any form. Therefore, the number of ways they can appear for each group listed above is 3!= 6 per group.


There are 6 groups. So, the total number of 10s that can appear is 6*6= 36.


The overall possible number of outcomes is 36*3= 108.
This is because when a die is standing against 2 other groups, the sample size will be 36 and there are 3 dice in this case.


Hence, probability of getting a sum of ten = 36/108 = 1/3

Cc: personal59. Modified solution. Cc: personal59
Re: Nairaland Mathematics Clinic by naturalwaves: 3:20pm On Aug 24, 2017
coliboyswag:
please I need a quick answer On this inequalities
1/3x+1/4<3x/8
Here you go:

Re: Nairaland Mathematics Clinic by coliboyswag: 3:24pm On Aug 24, 2017
please help me with this inequality 1/3x+1/4<3x/8
Re: Nairaland Mathematics Clinic by naturalwaves: 3:25pm On Aug 24, 2017
coliboyswag:
please help me with this inequality
1/3x+1/4<3x/8
I just did now. Look up.
Re: Nairaland Mathematics Clinic by Nobody: 3:30pm On Aug 24, 2017
naturalwaves:

Here you go:

Hi Natural waves how u dey ?I think u made an error . It should be x less than -2/3 nd x greater than 4/3
Re: Nairaland Mathematics Clinic by coliboyswag: 3:38pm On Aug 24, 2017
naturalwaves:
I just did now. Look up.
The answer am seeing on the text book is x>6
Re: Nairaland Mathematics Clinic by naturalwaves: 3:55pm On Aug 24, 2017
Number 8

a) 12.238m approximately
b) 9.37m approximately
Solution attached below
Cc: personal59

Re: Nairaland Mathematics Clinic by naturalwaves: 3:56pm On Aug 24, 2017
masperano:


Hi Natural waves how u dey ?I think u made an error . It should be x less than -2/3 nd x greater than 4/3
Hi bro. I dey o. Let me check through. Thanks.

Modified :
I did not divide with a negative number. So, the signs cannot flip. It can only flip if I divide with a negative number.
Let us carry out a small test.
From........3X greater than -2
I said....... X greater than -2/3
This means... X greater than say -0.7 approximately
If you try in all the numbers that are greater than -0.7, they will all satisfy the equation 3X greater than -2. For example... -0.6,-0.5,-0.4 etc. If you substitute all these values into 3X greater than -2. The answers you get will all be greater than -2 but if you pick a number that is less than -0.7 say -0.8, you will get something like -2.4 which is less than -2 thus not satisfying 3X greater than -2. If you keep on trying all the numbers that are lesser than -0.7 like -0.8,-0.9-1,-2.2 etc etc, none of them will satisfy the relation 3X greater than -2. So, the signs won't flip.
You can even try out all these values into the preceeding relation 3x + 2 greater than 0 and they will all turn out same way. Thanks.
Cc: masperano
Re: Nairaland Mathematics Clinic by Nobody: 4:07pm On Aug 24, 2017
personal59:
Please help me out its urgent Please help me out its urgent

Re: Nairaland Mathematics Clinic by naturalwaves: 4:27pm On Aug 24, 2017
masperano:

Thanks for the rescue. I have actually lost touch with longitude and latitude.
@Personal59. Solutions have been provided for the remaining questions 6,7,8,9,10. Good luck!
Re: Nairaland Mathematics Clinic by naturalwaves: 4:29pm On Aug 24, 2017
coliboyswag:
The answer am seeing on the text book is x>6
Maybe you are looking at the wrong answers. What textbook is that?
Re: Nairaland Mathematics Clinic by Nobody: 4:36pm On Aug 24, 2017
naturalwaves:

Maybe you are looking at the wrong answers. What textbook is that?

Lolzz. Yea I think he wrote the question wrongly, he wanted to write x/3 rather than 1/(3x) that is the only way you can get x greater than 6
Re: Nairaland Mathematics Clinic by naturalwaves: 4:40pm On Aug 24, 2017
masperano:


Lolzz. Yea I think he wrote the question wrongly, he wanted to write x/3 rather than 1/(3x) that is the only way you can get x greater than 6

Lol. I see. Please, help him solve that out. Running late.
Re: Nairaland Mathematics Clinic by Nobody: 4:52pm On Aug 24, 2017
naturalwaves:

Hi bro. I dey o. Let me check through. Thanks.

Modified :
I did not divide with a negative number. So, the signs cannot flip. It can only flip if I divide with a negative number.
Let us carry out a small test.
From........3X greater than -2
I said....... X greater than -2/3
This means... X greater than say -0.7 approximately
If you try in all the numbers that are greater than -0.7, they will all satisfy the equation 3X greater than -2. For example... -0.6,-0.5,-0.4 etc. If you substitute all these values into 3X greater than -2. The answers you get will all be greater than -2 but if you pick a number that is less than -0.7 say -0.8, you will get something like -2.4 which is less than -2 thus not satisfying 3X greater than -2. If you keep on trying all the numbers that are lesser than -0.7 like -0.8,-0.9-1,-2.2 etc etc, none of them will satisfy the relation 3X greater than -2. So, the signs won't flip.
You can even try out all these values into the preceeding relation 3x + 2 greater than 0 and they will all turn out same way. Thanks.
Cc: masperano

erm i don't really think so i think if you try out the solution you got it wont satisfy your quadratic inequality you solved(i am assuming the quadratic is correct) . for example according to your solution , zero is a solution since it is greater than -2/3, plug it into your quadratic inequality and see if it satisfies?
Re: Nairaland Mathematics Clinic by Nobody: 4:54pm On Aug 24, 2017
naturalwaves:

Thanks for the rescue. I have actually lost touch with longitude and latitude.
@Personal59. Solutions have been provided for the remaining questions 6,7,8,9,10. Good luck!

No worries mate
Re: Nairaland Mathematics Clinic by Nobody: 4:58pm On Aug 24, 2017
coliboyswag:
The answer am seeing on the text book is x>6

Re: Nairaland Mathematics Clinic by agentofchange1(m): 5:14pm On Aug 24, 2017
greetings great geniuses here ... its been a while.
Re: Nairaland Mathematics Clinic by naturalwaves: 5:14pm On Aug 24, 2017
masperano:


erm i don't really think so i think if you try out the solution you got it wont satisfy your quadratic inequality you solved(i am assuming the quadratic is correct) . for example according to your solution , zero is a solution since it is greater than -2/3, plug it into your quadratic inequality and see if it satisfies?
It does not satisfy. Will solve again and see where it went wrong when I am settled. Thanks.


Modified:

X is undefined at 0. Hence x is not equal to 0 and cannot be substituted either. Try out other sets of values and you will see that the answer is absolutely correct. The reason why X is undefined at 0 is because one of the given terms in the question has X as its base. Therefore, X cannot be subtututed at 0. CC: masperano

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