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Re: Nairaland Mathematics Clinic by personal59: 9:55pm On Aug 21, 2017 |
joshuakdboy:
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Re: Nairaland Mathematics Clinic by personal59: 5:31pm On Aug 22, 2017 |
Festy4u: naturalwaves: masperano:Please help me out its urgent tobillionaire:Please help me out its urgent
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Re: Nairaland Mathematics Clinic by personal59: 11:01pm On Aug 22, 2017 |
agentofchange1: |
Re: Nairaland Mathematics Clinic by Nobody: 11:24pm On Aug 22, 2017 |
personal59: my whatsapp number was there, I don't always put out my number on social media but I wanted to help you. I check Nairaland mostly at nights. if it were really urgent, you'd have forwarded it to my whatsapp. nonetheless I'd provide the solution here for you now. I hope it isn't late. |
Re: Nairaland Mathematics Clinic by Nobody: 11:35pm On Aug 22, 2017 |
[quote author=personal59 post=59701212][/quote] On Question 1, I changed x to a. it looks more reasonable that way. just follow up and ask any questions you have. more solutions are coming. I post anyone I finish 1 Like
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Re: Nairaland Mathematics Clinic by Nobody: 11:55pm On Aug 22, 2017 |
Number 4, 5 and 6 @personal59
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Re: Nairaland Mathematics Clinic by Nobody: 12:09am On Aug 23, 2017 |
It's time for my night meditation. I will continue at dawn. 1 Like |
Re: Nairaland Mathematics Clinic by personal59: 9:14am On Aug 23, 2017 |
joshuakdboy:thank u bro |
Re: Nairaland Mathematics Clinic by personal59: 9:20am On Aug 23, 2017 |
joshuakdboy: am submitting it tomorrow. morning on d whatsapp am having issue with my what'sapp application that's y I post it here |
Re: Nairaland Mathematics Clinic by naturalwaves: 10:31am On Aug 23, 2017 |
personal59:Which ones are yet to be unsolved? Let me know. Everyone seems busy nowadays. Sorry I am just seeing this. Hope it is not too late? |
Re: Nairaland Mathematics Clinic by personal59: 10:22pm On Aug 23, 2017 |
naturalwaves: 12345 av been done |
Re: Nairaland Mathematics Clinic by naturalwaves: 2:19pm On Aug 24, 2017 |
personal59:Okay. Here is number 10.
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Re: Nairaland Mathematics Clinic by naturalwaves: 2:34pm On Aug 24, 2017 |
No 10 continued
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Re: Nairaland Mathematics Clinic by coliboyswag: 2:35pm On Aug 24, 2017 |
please I need a quick answer On this inequalities
1/3x+1/4<3x/8 |
Re: Nairaland Mathematics Clinic by naturalwaves: 3:03pm On Aug 24, 2017 |
Number 7 If 3 dice are thrown together, The only combinations that can give a total of 10 are; 6,3,1 5,4,1 4,4,2 3,3,4 2,2,6 5,3,2 Note that, for each of these combinations, the dice can come in any form. Therefore, the number of ways they can appear for each group listed above is 3!= 6 per group. There are 6 groups. So, the total number of 10s that can appear is 6*6= 36. The overall possible number of outcomes is 36*3= 108. This is because when a die is standing against 2 other groups, the sample size will be 36 and there are 3 dice in this case. Hence, probability of getting a sum of ten = 36/108 = 1/3 Cc: personal59. Modified solution. Cc: personal59 |
Re: Nairaland Mathematics Clinic by naturalwaves: 3:20pm On Aug 24, 2017 |
coliboyswag:Here you go:
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Re: Nairaland Mathematics Clinic by coliboyswag: 3:24pm On Aug 24, 2017 |
please help me with this inequality
1/3x+1/4<3x/8 |
Re: Nairaland Mathematics Clinic by naturalwaves: 3:25pm On Aug 24, 2017 |
coliboyswag:I just did now. Look up. |
Re: Nairaland Mathematics Clinic by Nobody: 3:30pm On Aug 24, 2017 |
naturalwaves: Hi Natural waves how u dey ?I think u made an error . It should be x less than -2/3 nd x greater than 4/3 |
Re: Nairaland Mathematics Clinic by coliboyswag: 3:38pm On Aug 24, 2017 |
naturalwaves:The answer am seeing on the text book is x>6 |
Re: Nairaland Mathematics Clinic by naturalwaves: 3:55pm On Aug 24, 2017 |
Number 8 a) 12.238m approximately b) 9.37m approximately Solution attached below Cc: personal59
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Re: Nairaland Mathematics Clinic by naturalwaves: 3:56pm On Aug 24, 2017 |
masperano:Hi bro. I dey o. Let me check through. Thanks. Modified : I did not divide with a negative number. So, the signs cannot flip. It can only flip if I divide with a negative number. Let us carry out a small test. From........3X greater than -2 I said....... X greater than -2/3 This means... X greater than say -0.7 approximately If you try in all the numbers that are greater than -0.7, they will all satisfy the equation 3X greater than -2. For example... -0.6,-0.5,-0.4 etc. If you substitute all these values into 3X greater than -2. The answers you get will all be greater than -2 but if you pick a number that is less than -0.7 say -0.8, you will get something like -2.4 which is less than -2 thus not satisfying 3X greater than -2. If you keep on trying all the numbers that are lesser than -0.7 like -0.8,-0.9-1,-2.2 etc etc, none of them will satisfy the relation 3X greater than -2. So, the signs won't flip. You can even try out all these values into the preceeding relation 3x + 2 greater than 0 and they will all turn out same way. Thanks. Cc: masperano |
Re: Nairaland Mathematics Clinic by Nobody: 4:07pm On Aug 24, 2017 |
personal59:
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Re: Nairaland Mathematics Clinic by naturalwaves: 4:27pm On Aug 24, 2017 |
masperano:Thanks for the rescue. I have actually lost touch with longitude and latitude. @Personal59. Solutions have been provided for the remaining questions 6,7,8,9,10. Good luck! |
Re: Nairaland Mathematics Clinic by naturalwaves: 4:29pm On Aug 24, 2017 |
coliboyswag:Maybe you are looking at the wrong answers. What textbook is that? |
Re: Nairaland Mathematics Clinic by Nobody: 4:36pm On Aug 24, 2017 |
naturalwaves: Lolzz. Yea I think he wrote the question wrongly, he wanted to write x/3 rather than 1/(3x) that is the only way you can get x greater than 6 |
Re: Nairaland Mathematics Clinic by naturalwaves: 4:40pm On Aug 24, 2017 |
masperano: Lol. I see. Please, help him solve that out. Running late. |
Re: Nairaland Mathematics Clinic by Nobody: 4:52pm On Aug 24, 2017 |
naturalwaves: erm i don't really think so i think if you try out the solution you got it wont satisfy your quadratic inequality you solved(i am assuming the quadratic is correct) . for example according to your solution , zero is a solution since it is greater than -2/3, plug it into your quadratic inequality and see if it satisfies? |
Re: Nairaland Mathematics Clinic by Nobody: 4:54pm On Aug 24, 2017 |
naturalwaves: No worries mate |
Re: Nairaland Mathematics Clinic by Nobody: 4:58pm On Aug 24, 2017 |
coliboyswag:
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Re: Nairaland Mathematics Clinic by agentofchange1(m): 5:14pm On Aug 24, 2017 |
greetings great geniuses here ... its been a while. |
Re: Nairaland Mathematics Clinic by naturalwaves: 5:14pm On Aug 24, 2017 |
masperano:It does not satisfy. Will solve again and see where it went wrong when I am settled. Thanks. Modified: X is undefined at 0. Hence x is not equal to 0 and cannot be substituted either. Try out other sets of values and you will see that the answer is absolutely correct. The reason why X is undefined at 0 is because one of the given terms in the question has X as its base. Therefore, X cannot be subtututed at 0. CC: masperano |
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