I have been trying to get this correctly but giving me tough time. All I want to do is to get correct repetition of 10clubs with 3options permutations. The options are (Home win, Draw, and Away win) .

Example

These are the 10clubs

Chelsea vs man united
Arsenal vs man city
West ham vs stock
Juventus vs inter
Miland vs roma
Liverpool vs Everton
Basel v sion
Levente vs real betis
Chita vs vienner
Aik vs lazio

Option to be inputted is

Home win
Draw
Away win

So if I am going to do the permutations of 10clubs with 3options, how many places will the 10clubs split into with 3options. I have been searching the Internet to get one or two things related to it but no answer to what I needed.

Please if anyone can help with easy formula to use for the calculation or give any useful site to read more it will be appreciated.

Nevertheless if full detailed solutions to the above question can be solved without any omission i will be glad to work with such person.

Total no of clubs= 10
Total differences=3

Formula for combination
n!/(n-r)!r!
10!/(10-3)!3!

10x9x8x7x6x5x4x3x2x1 /7!3!
10x9x8x7x6x5x4x3x2x1/ 7x6x5x4x3x2x1. 3x2x1

10x9x8x7! /7!. 3x2x1=
10x9x8/ 3x2x1. Note 7!/7!= 1

So 10x9x8=720 and 3x2x1= 6
So, we have 720/6 = 120.

So you will have to play it in 120 ways of which only 1 ticked will come out successful.

damikay87:
I have been trying to get this correctly but giving me tough time. All I want to do is to get correct repetition of 10clubs with 3options permutations. The options are (Home win, Draw, and Away win) .

Example

These are the 10clubs

Chelsea vs man united
Arsenal vs man city
West ham vs stock
Juventus vs inter
Miland vs roma
Liverpool vs Everton
Basel v sion
Levente vs real betis
Chita vs vienner
Aik vs lazio

Option to be inputted is

Home win
Draw
Away win

So if I am going to do the permutations of 10clubs with 3options, how many places will the 10clubs split into with 3options. I have been searching the Internet to get one or two things related to it but no answer to what I needed.

Please if anyone can help with easy formula to use for the calculation or give any useful site to read more it will be appreciated.

Nevertheless if full detailed solutions to the above question can be solved without any omission i will be glad to work with such person.

Solved. 120 ways of which only one will come out successful

Kylekent59:


Solved. 120 ways of which only one will come out successful

OK but u did not show workings. Let chat on whatsapp my no is 07086497433