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Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by gpercuxionz(m): 12:03pm On Nov 20, 2017 |
Good day everyone pls I need help to the question 25. Thanks
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Re: Nairaland Mathematics Clinic by Umartins1(m): 3:59pm On Nov 23, 2017 |
gpercuxionz: Let the ogas cross check 1 Like
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Re: Nairaland Mathematics Clinic by Angelan97: 10:40pm On Nov 23, 2017 |
Hi, can someone help me with this one: To cover a distance of 10km, a girl runs some of the way at 15km/h and walks the rest of the way at 5km/h. Her total time of journey is 1hour. A) if the distance walked is x km find a simple expession for the distance run. B) Derive an equation involving x and use it to find the distance walked? |
Re: Nairaland Mathematics Clinic by Umartins1(m): 10:26am On Nov 24, 2017 |
Angelan97: The answer provided is subject to further scrutiny
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Re: Nairaland Mathematics Clinic by Umartins1(m): 10:54am On Nov 24, 2017 |
Check this alternative solution for distance run. I dey argue with one of my guys ontop the one wey correct
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Re: Nairaland Mathematics Clinic by meekmill(m): 12:51pm On Dec 01, 2017 |
Guys help me out
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Re: Nairaland Mathematics Clinic by Umartins1(m): 2:03pm On Dec 01, 2017 |
Here meekmill: 1 Like
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Re: Nairaland Mathematics Clinic by meekmill(m): 4:02pm On Dec 01, 2017 |
Umartins1: Bro thanks very much |
Re: Nairaland Mathematics Clinic by personal59: 12:09pm On Dec 07, 2017 |
please help out guys
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Re: Nairaland Mathematics Clinic by GeniusDavid(m): 10:25am On Dec 23, 2017 |
If 47% of the people in a community voted in a local election and 75% voted in a federal election, what is the least percentage that voted in both? |
Re: Nairaland Mathematics Clinic by Umartins1(m): 11:17am On Dec 23, 2017 |
GeniusDavid: 47-x+75-x+x=100 122-x=100 x = 122-100 x= 22 |
Re: Nairaland Mathematics Clinic by Redder97(m): 8:51am On Dec 24, 2017 |
Re: Nairaland Mathematics Clinic by assavin: 2:38pm On Dec 25, 2017 |
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Re: Nairaland Mathematics Clinic by Crizillion1(m): 8:33am On Dec 26, 2017 |
add me up on whatsapp group 08131667273 |
Re: Nairaland Mathematics Clinic by IFEOLUWAKRIZ: 1:16pm On Dec 26, 2017 |
I register my presence . I'm a PhD holder in mathematics Forward ur questions ASAP And you will score zero * removes slippers *takes to my clean heels 1 Like 2 Shares |
Re: Nairaland Mathematics Clinic by tobillionaire(m): 9:49am On Dec 30, 2017 |
pls I nid help on d working of this find d integral of √tanx |
Re: Nairaland Mathematics Clinic by chrismato(m): 12:24pm On Dec 30, 2017 |
Youngsage: Youngsage: x + y =5 -------- eqn i. x^x + y^y=31 ----- eqn ii. From equatns i & ii, take the log of both sides (xlog^x + ylog^y) = log 31------ eqn iii. log(x+y) = log 5 ------------ eqn iv. xylogxy= log 31 -------- eqn v. log xy = log 5 --------- eqn vi. (Using elimination method); xylog5 = log31 xy = log 31/log 5 =6.2 approx. 6. Recall, from eqn i, x + y = 5. So x = 6/y or y = 6/x. Therefore x=2 when y=3. ans: x=2, and y=3. Youngsage:I,disagree with this solution. bcus log31/logo =2.13approx.an not 6 by approx |
Re: Nairaland Mathematics Clinic by Mechanics96(m): 3:04pm On Dec 30, 2017 |
This solution is wrong sir; u don't take the log of x^x+y^y as xlog^x +ylog^y, and neither do you say xlogx+ ylogy. It should be log(x^x+y^y). These two are not the same. Simple test ; log3+log7 is never equal to log (3+7) Also log31/log5 is not 6.2 but 2.13... Let's get something clear on this question. It is only an IQ test, no maths rule supports the solution, yet the solution is crystal clear. There are many of such questions, the tricks for hacking the solution is thought in numerology. For example; if the sum of two numbers that have themselves as powers is a prime number then the numbers must be prime or one prime one even. x^x+y^y=31, x and y are both prime, one of them is even. Not classroom mathematics... |
Re: Nairaland Mathematics Clinic by Mechanics96(m): 3:37pm On Dec 31, 2017 |
tobillionaire:
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Re: Nairaland Mathematics Clinic by Mechanics96(m): 3:45pm On Dec 31, 2017 |
Cont'd
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Re: Nairaland Mathematics Clinic by inspirational93: 11:47pm On Dec 31, 2017 |
click this link to download free PDF document files and any related courses on any topic http://viwright.com/4as2 |
Re: Nairaland Mathematics Clinic by KlarkDevlin: 4:37pm On Jan 03, 2018 |
Mechanics96:I also got carried away recently by numerology. If someone is interested, then there is a lot of useful information https://numbervoice.com/ It is very interesting. |
Re: Nairaland Mathematics Clinic by jojokings: 6:11pm On Jan 03, 2018 |
Please I need help regarding my junior sisters maths problem, she has written maths in weac 4 times now yet the highest she got was D7. Who can assist for her to obtain her papers in one sittings. Anyhow that is possible. Am ready for her to secure university admission to study accounting. Preferable if your withing Abuja and environment. Call my number let's discuss. 08036568875 |
Re: Nairaland Mathematics Clinic by jerome263: 6:41pm On Jan 06, 2018 |
jojokings: I have a friend who is well gifted in mathematics.... he is currently studying mathematics in Uniben..........quote me if you need his number.... |
Re: Nairaland Mathematics Clinic by jojokings: 7:21am On Jan 08, 2018 |
jerome263: So how could he be if help? |
Re: Nairaland Mathematics Clinic by jerome263: 8:56am On Jan 08, 2018 |
jojokings:contact me on WhatsApp let's reason zero 7 zero, six 8 nine 9 six 2 six zero |
Re: Nairaland Mathematics Clinic by jojokings: 9:00am On Jan 08, 2018 |
Please who knows when NABTEB O LEVEL exam will be holding, or anyone that knows about special reliable centers for making ones o level papers clear.? |
Re: Nairaland Mathematics Clinic by Red2C(m): 11:31am On Jan 08, 2018 |
No. 22 pls
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Re: Nairaland Mathematics Clinic by lordbeans(m): 6:47am On Jan 11, 2018 |
Red2C: Ok let me have a crack on this. We were asked to show that 2y^2-y-1<=0 for all values of x in R (i.e. (-inf, inf)), if y=(2x+3)/(x^2+2x+3) ; Let's first factorize 2y^2-y-1=(2y+1)(y-1);=> (2y+1)(y-1)<=0; for this to be true, it means (2y+1)<=0 and (y-1)>=0 (We will call this scenario 1) OR (2y+1)>=0 and (y-1)<=0 (scenario 2). Assessing scenario 1(a) 2y+1<=0; => y<=-1/2;(that is y can be -1,-2,-3,... etc). BUT this is in contradiction to scenario 1 (b) y-1>=0 (i.e. -1-1=-2 CANNOT be greater than 0). This means there exist values for y such that scenario one is not satisfied (there goes scenario 1 off the window). We are then left with scenario 2. We must now show that substituting y=(2x+3)/(x^2+2x+3) into scenario 2 must satisfy the inequality. Let's substitute it into scenario 2(a), we obtain 2((2x+3)/(x^2+2x+3))+1 ?>=0 (i.e. is this >=0), => 2(2x+3) ?>= -(x^2+2x+3) , simplifying further we have x^2+6x+9 ?>=0; => (x+3)^2 ?>=0. Any number squared is always positive irrespective of whether the number is negative or positive, hence we can now be confident to remove the question mark in front of the inequality and say yes for any value of x, 2y+1>=0, and this implies that y-1<=0 for y=(2x+3)/(x^2+2x+3); hence the proof of 2y^2-y-1<=0 is complete. Second part (finding the maximum and minimum of y) y=(2x+3)/(x^2+2x+3); we look for the stationary or turning points which are usually maximum, minimum or inflexion points. The stationary points are points where there is a sign change of y as increases that is y moves from positive to negative or vice versa; this means y must go through 0. Knowing this characteristic, we would want to seek these points ; one way of achieving this is to find the points where the derivative of y wrt x is 0 (i.e. dy/dx=0). Differentiating dy/dx using quotient rule gives dy/dx=(-2x^2-6x)/(x^2+2x+3)^2=0; -2x^2-6x=0; =>x^2+3x=> x(x+3)=0=> x=0, x=-3; Hence the turning points occur at x=0 an -3; but you were asked about the maximum and minimum values not where in the x space they occur. Substituting the values into the function we get y=1 at x=0 and y=-1/2 at x=-3. all other values of y are bounded between 1 and -1/2, which implies the maximum value of y=1 and the minimum value of y=-1/2. |
Re: Nairaland Mathematics Clinic by Aybalance: 4:37pm On Jan 19, 2018 |
pls i need help on this... ........nP3+nC4=6.find n |
Re: Nairaland Mathematics Clinic by lordbeans(m): 1:40pm On Jan 20, 2018 |
Aybalance: n=3 |
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