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Nairaland Forum / Nairaland / General / Education / UI 2018/2019 Admission Thread (333434 Views)
Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)
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Re: UI 2018/2019 Admission Thread by Damayogenius18: 10:10pm On Apr 20, 2018 |
No 2...i misread the question...am suppose to use debrogile equation... Lamda= h/mv...mistake on my part.... |
Re: UI 2018/2019 Admission Thread by dolapo74: 10:11pm On Apr 20, 2018 |
How can I calculate pH without using calculator |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 10:16pm On Apr 20, 2018 |
Gracy3535:..it is the mixing or blending of orbital to av orbital of the same energy or to av the same degeneracy...p orbital has slightly higher energy than s orbital..but when hybridize,they will both have the same energy...a new orbital is form different from the original s and p orbital..the new name of the orbital is now called sp orbital...we have sp,sp^2( called sp two not sp square) also sp^3.... |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 10:33pm On Apr 20, 2018 |
dolapo74:..u just need smartness..pH of 0.001= 10^-3..since.pH= - log[H^+]..pH =3....but there are some compicacated one...for dat u av to b smart too...like pH of 3.4 x 10-4....u can just treat it as 1.0 x 10^-4....u get 4.....u will now say....4 - log 3.4...I don't knw log 3.4..but I knw is "0.something".. I knw my answer will be BTW 4 and 3...like 3.1 - 3.9...actually the answer is 3.5......so its just smartness |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 4:22am On Apr 21, 2018 |
Eben331:....no 3....fe= 5cm..Ue = 3cm...Ve=?...so lens formula... 1/f=1/u + 1/v....1/5=1/3 + 1/v...1/v= 1/5 - 1/3 ...Ve = -15/2 = -7.5m.... D way I think it is DAT the image of the objective lens form the object distance of the eyepiece ... |
Re: UI 2018/2019 Admission Thread by vicstiqs95: 9:00am On Apr 21, 2018 |
Eben331:Wrong. |
Re: UI 2018/2019 Admission Thread by vicstiqs95: 9:11am On Apr 21, 2018 |
Diethyl ether is produced from ethanol according to the following equation. 2Ch3ch2oh------->CH3cH2OcH2cH3+ H2o calculate the percentage yield of 50.9g of ethanol react to produce 24.0g of ether. thanks for solving. |
Re: UI 2018/2019 Admission Thread by dolapo74: 9:41am On Apr 21, 2018 |
Damayogenius18:I get your point .Thank you so much |
Re: UI 2018/2019 Admission Thread by Eben331: 9:50am On Apr 21, 2018 |
Gracy3535:Hybridization is the mixing of two or more orbitals of the same principal quantum number to give a new set of orbitals that are exactly equivalent. TYPES OF HYBRIDIZATION (1) sp three eg alkane (2) sp two eg alkene (3) sp eg alkyne. |
Re: UI 2018/2019 Admission Thread by Eben331: 9:51am On Apr 21, 2018 |
dolapo74:You have to knw standard form. |
Re: UI 2018/2019 Admission Thread by Eben331: 9:54am On Apr 21, 2018 |
vicstiqs95:correction pls |
Re: UI 2018/2019 Admission Thread by Eben331: 9:58am On Apr 21, 2018 |
Damayogenius18:correction pls |
Re: UI 2018/2019 Admission Thread by Eben331: 10:10am On Apr 21, 2018 |
(1) A man can row a boat at 4km/hr in still water. He rows the boat 2km upstream and 2km back to his starting place in 2 hours. How fast is the stream flowing? (2) A swimmer is capable of swimming at 1.4m/s in still water. (a) How far downstream will he land if he swims directly across a 180m wide river? (b) How long will it take him to reach the other side? 1 Like |
Re: UI 2018/2019 Admission Thread by Eben331: 10:36am On Apr 21, 2018 |
Damayogenius18:correct! |
Re: UI 2018/2019 Admission Thread by Cboyflald(m): 11:39am On Apr 21, 2018 |
To all social scientists: Follow this link to join my WhatsApp group: https:///GoCqyMHpKQz0TPF6lN7OMf |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 11:54am On Apr 21, 2018 |
Gracy3535:..lol..I miss u guys too.. But from Monday..I will always come online at 2am.... |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 12:25pm On Apr 21, 2018 |
vicstiqs95:...conservation of energy.... Mgh = 1/2mv^2....m cancel...so gh=1/2v^2.... v=√2gh...but h= l - l cos teta....h= l (1-cos teta) h=1(1 - 0.866)..h=0.134... v=√2 * 10 *0.134... v=1.637m/s |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 12:35pm On Apr 21, 2018 |
Damayogenius18:tanx cos i really need ur help. Ve gotten new skul phy. Pls take a pix of science phy |
Re: UI 2018/2019 Admission Thread by ikeepitreal(m): 12:42pm On Apr 21, 2018 |
please, do you guys have a whatsapp group? |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 12:49pm On Apr 21, 2018 |
Gracy3535:...send ur number to me trough mail..I will send it to u via WhatsApp...no need
|
Re: UI 2018/2019 Admission Thread by Damayogenius18: 1:41pm On Apr 21, 2018 |
Eben331:..no 2...the question is not complete or perhaps I don't understand it....I think u should give the speed of the river....even If u don't give it,u should give the angle the boat made wit the shore.. |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 1:53pm On Apr 21, 2018 |
Eben331:..no 1..Velocity of boat related to shore= 2km/ 2hrs = 1km/hr...Velocity of boat related water=4km/hr...velocity of water related to shore= 4^2 - 1^2... v^2 = 16 - 1. ..v = √15...=3.87km/hr |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 2:10pm On Apr 21, 2018 |
Eben331:...no 2..a is not complete...b is t = 180/1.4..=129s..so it will b easier to calculate "a" if the rate of flow of the river is given....dx= speed of river/ 129s....dx= how far downstream....I could av also calculated the speed of river using pythagoras if you av given me the angle the boat made with the shore...I stand corrected o...I may be wrong.. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 4:56pm On Apr 21, 2018 |
Damayogenius18:tanx |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 4:57pm On Apr 21, 2018 |
Eben331:tanx |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 4:59pm On Apr 21, 2018 |
Damayogenius18:am nt on whatsapp |
Re: UI 2018/2019 Admission Thread by briX1: 7:27pm On Apr 21, 2018 |
please , will ui take pharmacy this year? |
Re: UI 2018/2019 Admission Thread by Eben331: 8:46pm On Apr 21, 2018 |
Re: UI 2018/2019 Admission Thread by Eben331: 8:49pm On Apr 21, 2018 |
[/color] Damayogenius18:wrong[color=#990000] Damayogenius18:wrong Damayogenius18:wrong |
Re: UI 2018/2019 Admission Thread by Eben331: 8:53pm On Apr 21, 2018 |
Damayogenius18, show us the corrections to your questions, we dont knw them. |
Re: UI 2018/2019 Admission Thread by briX1: 8:55pm On Apr 21, 2018 |
Eben331: thank you |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 8:57pm On Apr 21, 2018 |
Eben331:..I will bro...solve d relative question.... |
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