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Nairaland Forum / Nairaland / General / Education / UI 2018/2019 Admission Thread (333584 Views)
Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)
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Re: UI 2018/2019 Admission Thread by Nltaliban(m): 5:27pm On Jul 10, 2018 |
Eben331: Yes.. Late September or early October if all goes well |
Re: UI 2018/2019 Admission Thread by simplebb: 5:35pm On Jul 10, 2018 |
Nltaliban: Have done that. He will be allowed to sit for the PosT UTME and later tender his NECO result for admission the moment the result is released. Finally one can breathe a sigh of relief. Thanks for the selfless inputs. |
Re: UI 2018/2019 Admission Thread by simplebb: 5:37pm On Jul 10, 2018 |
Nltaliban:Same thing I was told and before then NECO will be out. So it is just perfect for him. Thanks for your important updates. |
Re: UI 2018/2019 Admission Thread by Nltaliban(m): 6:24pm On Jul 10, 2018 |
simplebb: You're welcome |
Re: UI 2018/2019 Admission Thread by Obakenny01(m): 7:15pm On Jul 10, 2018 |
Damitism: Does UI still offer Pharmacy? |
Re: UI 2018/2019 Admission Thread by Eben331: 7:39pm On Jul 10, 2018 |
Nltaliban:Thank you very much. You have been helpful always. |
Re: UI 2018/2019 Admission Thread by Eben331: 7:40pm On Jul 10, 2018 |
Obakenny01:Yes. |
Re: UI 2018/2019 Admission Thread by Eben331: 9:11pm On Jul 10, 2018 |
Eben331:Pls I need solution to this question. Someone should help out. |
Re: UI 2018/2019 Admission Thread by scromatan(m): 10:40pm On Jul 10, 2018 |
............. |
Re: UI 2018/2019 Admission Thread by TeflonBlixx: 11:26pm On Jul 10, 2018 |
Eben331: Density is inversely proportional to height. . Density of water x height in water = Density of liquid x height in liquid.. Where density of water is 1gcm^3 Height in water is 3cm Density of liquid is 0.89gcm^3 Height in liquid is unknown 3 x 1 = 0.89 x h 3 = 0.89h 3/0.89 = h h =3.37cm 1 Like |
Re: UI 2018/2019 Admission Thread by Obakenny01(m): 11:42pm On Jul 10, 2018 |
Eben331:And are they taking new students for 2018/2019? |
Re: UI 2018/2019 Admission Thread by ola3310: 1:11am On Jul 11, 2018 |
I am applying as a lecturer. It is wonderful to see students come up with a creative thread as this |
Re: UI 2018/2019 Admission Thread by ola3310: 1:14am On Jul 11, 2018 |
Is there any available whatsapp group I can join. It will be fun getting to know you all better. We can be friends |
Re: UI 2018/2019 Admission Thread by Damitism: 4:49am On Jul 11, 2018 |
Obakenny01: Yes. Pharmacy has been accredited. Send me a pm if you are an aspirant for the coming session. |
Re: UI 2018/2019 Admission Thread by Eben331: 7:34am On Jul 11, 2018 |
TeflonBlixx:Thanks. This was what I got also but the answer the textbook got was 7.1cm. |
Re: UI 2018/2019 Admission Thread by Eben331: 7:38am On Jul 11, 2018 |
Obakenny01:Yes, they've regained accreditation for Pharmacy. You can check the eligibility of the course for 2018/2019 through IBASS to be sure. |
Re: UI 2018/2019 Admission Thread by Nobody: 10:16am On Jul 11, 2018 |
Nltaliban:yes sah. Thanks for your explanations. 1 Like |
Re: UI 2018/2019 Admission Thread by Nobody: 10:19am On Jul 11, 2018 |
Obakenny01:I wanted to go for mbbs but I think my jamb score isn't enough (253) so I think UI might gimme pharmacy instead. I love both courses. I'll also be fifteen this year. Can I gain admission? |
Re: UI 2018/2019 Admission Thread by Nobody: 10:20am On Jul 11, 2018 |
Eben331:is 253 enough to qualify me? |
Re: UI 2018/2019 Admission Thread by scromatan(m): 10:27am On Jul 11, 2018 |
15 yrs ![]() ![]() ![]() UI don't admit students below 16 yrs of age you will have to defer your admission@LukeSkywalker |
Re: UI 2018/2019 Admission Thread by Obakenny01(m): 12:33pm On Jul 11, 2018 |
LukeSkywalker78: Yes but be sure to change to pharmacy (if it is available) |
Re: UI 2018/2019 Admission Thread by Obakenny01(m): 1:01pm On Jul 11, 2018 |
Eben331:U knw any aspirant that has picked Pharmacy? |
Re: UI 2018/2019 Admission Thread by Dkfpaul(m): 7:56pm On Jul 11, 2018 |
The time we all waited for has come. It is no longer a news that POST UTME registration will begin on Monday July 16 and ends on August 10. Buh before then I will like to inform you about important things to take note when registering for Post -Utme: 1. Your Name Must Be Spelt Correctly- This is the number one and most common mistake made by aspirants when registering for post UTME. Spelling your name wrongly might be a very big problem on the day of your exam. Post UTME is not like JAMB where you can correct your mistake after you have successfully registered. So you have to be very careful when registering online. 2. Use the same name you used in your birth cert. , WAEC , JAMB - I have seen occasions where an aspirant use , for example, "Popoola Tosin Michael " in the WAEC registration and later use , for example, " Popoola Oluwatosin Adekusibe " in the JAMB registration . This will be a very big problem to you either during your post UTME registration or during registration after being admitted. Also, you should arrange the name in the same way it was arranged in your birth cert. and other vital documents. 3. Input Your Correct O'level Result - This shouldn't be a new thing to aspirants , although it might be intentional or a mistake, either both sides, it is a big offence. Alot of UNILORIN newly admitted students who were caught in the act were sent home after being admitted. I know you don't want to be in that same situation, then do the right thing. 4. Online payment during registration of post UTME- This is sometimes, a big problem to the aspirants who are registering for the post UTME online because you will be asked to pay some fee for the registration. I will advise you to do this in a cybercafe where you know is safe, don't take the risk of paying online with your smartphone. I have received complains from aspirants in the past about not receiving RRR pin after the money have been deducted from your bank account, allowing to pay twice. I know you don't want that. 5. Read the instructions before registering online- I will advise you to read the guidelines before registering so as to avoid any form of mistakes that can cost you your chance of being admitted this year. Be careful. In conclusion, never allow anyone to register for you in your absence, make sure you are there to access any error before the registration is being submitted. 6.Fill form with CAPITAL LETTERS ensure that all the information you are going to submit is filled with CAPITAL LETTERS as instructed by U. I 7. White background passport Make use of white background passport when registering to avoid inconveniences. Excellent result is assured by God's Grace. You have any question to ask? Then comment below and I will reply you as soon as possible. #PAULISM |
Re: UI 2018/2019 Admission Thread by Adebaba1(m): 8:26pm On Jul 11, 2018 |
Pls add this number to the WhatsApp group 08023656406 |
Re: UI 2018/2019 Admission Thread by Aceed: 12:19am On Jul 12, 2018 |
What is the tension in the cable holding a mine of mass 600kg and volume 0.8m^3 to the sea bed, so that it is totally submerged. What is the upthrust on a body which displaces 0.6m^3 of water, 0.5m^3 of methylated spirit? (density of water = 10^3 kgm^-3, density of methylated spirit = 0.8 x 10^3 kgm^-3 and g = 10ms^-2) A body of mass 700g hangs from the end of a long wire fixed to a high tree. A horizontal string attached to the body pulls it until the wire is at 30 degrees to the vertical. Find the tensions in both the string and the wire. A block of material of volume 20cm^3 and density 2.5gcm^-3 is suspended from a spring balance with half the volume of the block immersed in water. What is the reading of the spring balance? (density of water = 1.0gcm^-3) What volume of alcohol with a density of 8.4 x 10^2 kgm^-3 will have the same mass as 4.2m^3 of petrol whose density is 7.2 x 10^2 kgm^-3? A force of 300N was used to pull a load of mass 40kg at a steady speed up an inclined of length 6.2m and vertical height 3.5m. Determine the velocity ratio WORKINGS PLEASE... cc eben331 damayogenius18 teflonblixx (pics with workings are acceptable) |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 1:52am On Jul 12, 2018 |
TeflonBlixx: Sir,I don't agree with this... I think there is a better way to solve it and arrive at the exact answer...... |
Re: UI 2018/2019 Admission Thread by Aceed: 1:56am On Jul 12, 2018 |
And someone should please explain GAXULIR ![]() |
Re: UI 2018/2019 Admission Thread by ola3310: 2:56am On Jul 12, 2018 |
Good day all. My name is Olaosebikan Ayomide. I am an aspiring lecturer applying for a lecturing job in UI and OAU. I see it is a great idea that this thread was created. It is also nice seeing students coming up and sharing past questions in preparation for the forthcoming post Utme. So in my own little way of socializing, I opened a whatsapp group where we can get to know each other and help out with registration and preparation. Feel free to join us on the group. Here is the link. https:///A9gpxuTH7OIIymy3rOvW7Y https:///A9gpxuTH7OIIymy3rOvW7Y https:///A9gpxuTH7OIIymy3rOvW7Y And in Case the link doesn't work for you, you can also drop your whatsapp contact so that you can be added |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 3:00am On Jul 12, 2018 |
Eben331: Volume of the hydrometer when floating in water,V1 = Volume of the weighted bulb + Volume of the cylindrical stem..... Volume of the wighted bulb = 30cm^3. Volume of the cylindrical stem = §(pie) * r^2(radius squared) * L1. .: V1 = 30cm^3 + §r^2h1. But Cross-sectional area of the cylinder = §r^2 = 1cm^2 (given in the question). Length of the stem immersed when the hydrometer is floating in water,L1 = 3cm. .: volume of the hydrometer when floating in water,V1 = 30cm^3 + (1cm^2 * 3cm) = 30cm^3 + 3cm^3 = 33cm^3. Secondly, Volume of the hydrometer when floating in the Liquid,V2 = Volume of the weighted bulb + volume of the cylindrical stem.... Volume of the weighted bulb = 30cm^3 ........... and Volume of the cylindrical stem = §(pie) * r^2(r squared) * L2 .: V2 = 30cm^3 + §r^2L2. But, cross-sectional area of the cylinder = §r^2 = 1cm^2. Length of the stem immersed when floating in the liquid,L2 = ? .: V2 = 30cm^3 + (1cm^2 * L2 cm) V2 = 30cm^3 + L2 cm^3 Finally, Upthrust = Volume * density * acceleration due to gravity. Which implies that: V1 * d1 * g = V2 * d2 * g Cancell out the acceleration due to gravity,g, we have: V1 * d1 = V2 * d2. From our calculations above,we have that: V1 = 33cm^3 d1(which is density of water) = 1g/cm^3 V2 = (30 + L2) cm^3 d2(which is density of the liquid) = 0.89g/cm^3 Substituting the values in the equation above,we have: 33 * 1 = (30 + L2) * 0.89 33 = 26.7 + 0.89L2 33 - 26.7 = 0.89L2 6.3 = 0.89L2 .: L2 = 6.3/0.89 = 7.1 cm (approximately). Abeg pardon my typos....Na Nokia torch I dey use ![]() 1 Like |
Re: UI 2018/2019 Admission Thread by Aceed: 3:05am On Jul 12, 2018 |
DrBESTJC...OGA NA MASTER... ![]() ![]() ![]() |
Re: UI 2018/2019 Admission Thread by kenine45: 6:56am On Jul 12, 2018 |
Perhaps you need a tutorial that can help you in your preparations for UI PUTME, kindly join TBOSE TUTORS today.
|
Re: UI 2018/2019 Admission Thread by ikeepitreal(m): 7:58am On Jul 12, 2018 |
abeg add me to the whatsapp group
08185942804 |
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