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UI 2018/2019 Admission Thread - Education (85) - Nairaland

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Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)

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Re: UI 2018/2019 Admission Thread by Eben331: 5:40pm On Jul 12, 2018
DrBESTJC:



Volume of the hydrometer when floating in water,V1 = Volume of the weighted bulb + Volume of the cylindrical stem.....
Volume of the wighted bulb = 30cm^3.
Volume of the cylindrical stem = §(pie) * r^2(radius squared) * L1.
.: V1 = 30cm^3 + §r^2h1.
But Cross-sectional area of the cylinder = §r^2 = 1cm^2 (given in the question).
Length of the stem immersed when the hydrometer is floating in water,L1 = 3cm.
.: volume of the hydrometer when floating in water,V1 = 30cm^3 + (1cm^2 * 3cm) = 30cm^3 + 3cm^3 = 33cm^3.

Secondly,

Volume of the hydrometer when floating in the Liquid,V2 = Volume of the weighted bulb + volume of the cylindrical stem....
Volume of the weighted bulb = 30cm^3 ........... and
Volume of the cylindrical stem = §(pie) * r^2(r squared) * L2
.: V2 = 30cm^3 + §r^2L2.
But, cross-sectional area of the cylinder = §r^2 = 1cm^2....
Thanks a lot sir...it's very explicit.
Re: UI 2018/2019 Admission Thread by Eben331: 5:51pm On Jul 12, 2018
DrBESTJC:
HOT CHEMISTRY.

Hydrogen Sulphide is prepared at one end of a laboratory. It takes 5 seconds for a student at the other end to smell it. How long will it take to smell sulphur dioxide from the same position?
(A) 5 seconds also.
(B) 2.5 seconds.
(C) 3.6 seconds.
(D) 9.4 seconds.
(E) 2.7 seconds.

Please SHOW FULL WORKINGS!
C
Re: UI 2018/2019 Admission Thread by Eben331: 5:59pm On Jul 12, 2018
Eben331:
(1) A swimmer is capable of swimming at 1.4m/s in still water. (a) how far downstream will be land if he swims directly across a 180m wide river? (b) how long will it take him to reach the other side? (2) A man can row at 6km/hr in still water and wants to cross a river to a position exactly opposite his starting point. If the river is 5km wide and is flowing at 4km/hr eastwards, find the direction in which he must set off in order to accomplish his objective. How long will it take to cross the river?
Pls someone should solve this question for me.
Re: UI 2018/2019 Admission Thread by Ummuaisha(f): 6:23pm On Jul 12, 2018
Please house,I need unibadan post utme past questions..... Physics chemistry biology and English
I would be grateful if I can lay my hands on them......thank you
Email: hamdalatarogundade@gmail.com
Please also add me on any available group esp the Reading group 08123221363
Re: UI 2018/2019 Admission Thread by OyedejiIfedayo: 7:01pm On Jul 12, 2018
Pls my brother aspiring for MBBS had a very high score in UTME and wrote this years WAEC. But on checking his waec result it displayed no result for this candidate.
I was unhappy when he told me he hasn't seen his result till the present moment even though he has made complaint.
Pls can anyone advise on what can still be done.
Re: UI 2018/2019 Admission Thread by Strawberry001(f): 7:04pm On Jul 12, 2018
Is this thread only for science students?
Re: UI 2018/2019 Admission Thread by TimiElvis001(m): 7:08pm On Jul 12, 2018
Hi am Timi, aspiring for Geology and helpful tips I should know... Thanks 07062480545 pls add to whatsapp Group...
Re: UI 2018/2019 Admission Thread by Strawberry001(f): 7:30pm On Jul 12, 2018
centitan:

Sent,Check your mail.
help, please, I need ui past questions. I applied for psychology
Re: UI 2018/2019 Admission Thread by Strawberry001(f): 7:32pm On Jul 12, 2018
whatsapp group
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 10:21pm On Jul 12, 2018
Aceed:
What is the tension in the cable holding
a mine of mass 600kg and volume 0.8m^3 to
the sea bed, so that it is totally submerged.


Density of seawater = 1030Kgm^-3.

Weight of mine in air = mg = 600g * 10m/s2 = 6000N.
Upthrust of mine in seawater = density * volume * acceleration due to gravity = 1030 * 0.8 * 10 = 8240N.
Tension in the cable = Upthrust - Weight of mine in air = 8240N - 6000N = 2240N.
Re: UI 2018/2019 Admission Thread by kenine45: 1:57am On Jul 13, 2018
IMPORTANT ANNOUNCEMENT


TBOSE TUTORS PRESENTS HER 5th STANDARD PERIODIC MOCK TEST OF OPERATION CRUSH UI PUTME 2018.

As it is now OBVIOUS that UI PUTME is in a few weeks time, it is good that one prepares and sets a target for the exam.

This is why TBOSE TUTORS has prepared a nice avenue to weigh yourself under same standard temperature and pressure as the exam.

Note :
1. No calculator is allowed
2. 100 questions in 85mins

I beg you not to joke with this opportunity.
Venue : Abadina primary school 1, UI
Date : 21st of July( next week Saturday )
Time : 10:30am (if you are 30 mins late, you won't be allowed in)
Price : #500

There will be prize for the 1st and 2nd
Science and non science inclusive

Get a #50 bike from UI gate and call "Abadina primary school 1." You will see our banner at the gate with some people to direct you. Make sure it is TBOSE TUTORS as many tutorials are around.

If you are far away you can register for it before then and participate at the same time with us here. The questions will be sent to you on WhatsApp.



The correction will be done on Monday and it is free for all participants only.


Your Success, Our Mandate

For more enquiries, contact AJESEN on 08169993852



Signed
TBOSE TUTORS
Re: UI 2018/2019 Admission Thread by simplebb: 6:22am On Jul 13, 2018
OyedejiIfedayo:
Pls my brother aspiring for MBBS had a very high score in UTME and wrote this years WAEC. But on checking his waec result it displayed no result for this candidate.
I was unhappy when he told me he hasn't seen his result till the present moment even though he has made complaint.
Pls can anyone advise on what can still be done.

That's serious.
Did he write NECo exam this year?
BTW the problem, was it a centre issue or only him?
Re: UI 2018/2019 Admission Thread by OyedejiIfedayo: 7:05am On Jul 13, 2018
simplebb:

That's serious. Did he write NECo exam this year? BTW the problem, was it a centre issue or only him?
He didn't write NECO. it was centre problem.
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:09am On Jul 13, 2018
Aceed:


A block of material of volume 20cm^3 and
density 2.5gcm^-3 is suspended from a spring
balance with half the volume of the block
immersed in water. What is the reading of the
spring balance? (density of water = 1.0gcm^-3)



From Density = Mass/volume
.: Mass = Density * volume = 2.5g/cm^3 * 20cm^3 = 50g = (50/1000)Kg = 0.05Kg.
Weight of the block in air = mg = 0.05Kg * 10m/s2 = 0.5N.

Now,

Half of the volume of the block is immersed in water; which implies: 1/2 * 20cm^3 = 10cm^3.
Upthrust = density * volume * g(acceleration due to gravity) = 1g/cm^3 * 10cm^3 * g = 10g * g = (10/1000)Kg * 10m/s^2 = 0.01Kg * 10m/s^2 = 0.1N

Reading of the spring balance = Tension in the spring of balance = Weight of the block in air - Upthrust = 0.5N -0.1N = 0.4N
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:21am On Jul 13, 2018
Aceed:


What volume of alcohol with a density of
8.4 x 10^2 kgm^-3 will have the same mass as
4.2m^3 of petrol whose density is 7.2 x 10^2 kgm^-3?

From Density = Mass/volume
.: Mass = density * volume.

From the question,alchohol and petrol have the same mass.
.: M = d1 * V1 = d2 * V2.
Substituting the values given in the question in the above equation,
(8.4 * 10^2)Kg/m^3 * V1 = (7.2 * 10^2)Kg/m^3 * 4.2m^3
.: V1(which is volume of alchohol) = (720 * 4.2)/840 = 3.6m^3
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:27am On Jul 13, 2018
Aceed:


A force of 300N was used to pull a load of
mass 40kg at a steady speed up an inclined
of length 6.2m and vertical height 3.5m.
Determine the velocity ratio

Velocity Ratio = Effort distance/Load distance.

From the question,
Effort distance = 6.2m ...and
Load distance = 3.5m.

.: Velocity Ratio = 6.2m/3.5m = 1.77
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:44am On Jul 13, 2018
Aceed:


A body of mass 700g hangs from the end of a
long wire fixed to a high tree. A horizontal
string attached to the body pulls it until the
wire is at 30 degrees to the vertical. Find
the tensions in both the string and the wire.

Using the diagramatic reprsentation of the question below, and solving from the resolved triangle of vectors,
Cos(theta) = adj/hyp
Cos30(degrees) = 7N/T1
.: T1(tension in the long wire) = 7N/cos30 = 8.08N.

Also,

Tan(theta) = opp/adj.
Tan30(degrees) = T2/7N.
.: T2(tension in the string) = tan30 * 7N = 4.04N

Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:53am On Jul 13, 2018
Aceed:
DrBESTJC...OGA NA MASTER... grin grin grin...hmmm which course you dey vie for... you don scatter book oooo
Lol....See this one grin ..... You never Jam real science Masters.....when you do, you go know say na serious pickin I be for physics.....We just de try small small....

I'm aspiring for Medicine.

Abeg, post more difficult questions here, let's see how far we have gone.... ...exam is already here
Re: UI 2018/2019 Admission Thread by Aceed: 8:34am On Jul 13, 2018
DrBESTJC:



From Density = Mass/volume
.: Mass = Density * volume = 2.5g/cm^3 * 20cm^3 = 50g = (50/1000)Kg = 0.05Kg.
Weight of the block in air = mg = 0.05Kg * 10m/s2 = 0.5N.

Now,

Half of the volume of the block is immersed in water; which implies: 1/2 * 20cm^3 = 10cm^3.
Upthrust = density * volume * g(acceleration due to gravity) = 1g/cm^3 * 10cm^3 * g = 10g * g = (10/1000)Kg * 10m/s^2 = 0.01Kg * 10m/s^2 = 0.1N

Reading of the spring balance = Tension in the spring of balance = Weight of the block in air - Upthrust = 0.5N -0.1N = 0.4N

answer to this was 40g
Re: UI 2018/2019 Admission Thread by iremide12: 9:25am On Jul 13, 2018
Nltaliban:



If you ask me, you stand a good chance in Ui but it's up to you to take the risk.


Think we'll, it's your decision. There's every probably that the time that will be given to you to accept Oou's admission would have elapsed before Ui will conduct postume.


Think well, if you think you're ready to take the challenge and Prove yourself as a champion.


pls I don't grab your that second paragraph/statement
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 9:30am On Jul 13, 2018
Aceed:


answer to this was 40g

I think it is wrong because tension is a force whose unit is Newton...and spring balance measures weight not mass.


But you can still convert the value in Newton to gramms...thus
F = mg ...where m = F/g = 0.4/10 = 0.04Kg.
Then,multiply by 1000 to convert to gramms = 0.04 * 1000 = 40g
Re: UI 2018/2019 Admission Thread by simplebb: 9:54am On Jul 13, 2018
OyedejiIfedayo:


He didn't write NECO.
it was centre problem.

The best shot is to register for the Post UTME using Awaiting result and to write it then hope WAEC release his result.

Then ensure you keep checking while ensuring the following are correct too, that might be another cause.
1. Centre Number/Card. exam No. 2. Type of examination 3.
Examination year.
Re: UI 2018/2019 Admission Thread by Nltaliban(m): 11:15am On Jul 13, 2018
iremide12:
pls I don't grab your that second paragraph/statement


Are you in whatsapp so I send a voice note?

I really can't type much
Re: UI 2018/2019 Admission Thread by Bolujoe49: 7:23pm On Jul 13, 2018
@Damogenius, Ntaliban, Eben311. Please add me to the UI aspirants group chat. 08105317653. Thanks.
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 8:20pm On Jul 13, 2018
DrBESTJC:


I think it is wrong because tension is a force whose unit is Newton.


But you can still convert the value in Newton to gramms...thus
F = mg ...where m = F/g = 0.4/10 = 0.04Kg.
Then,multiply by 1000 to convert to gramms = 0.04 * 1000 = 40g
ve u being able to get square root of 2, 13...
Re: UI 2018/2019 Admission Thread by IamGoke(m): 10:22pm On Jul 13, 2018
Nltaliban:



Are you in whatsapp so I send a voice note?

I really can't type much
Add me. O8080772177
Re: UI 2018/2019 Admission Thread by psalmhorah(m): 12:05am On Jul 14, 2018
pls bosses add me to the whatsapp group
08024618054
Re: UI 2018/2019 Admission Thread by psalmhorah(m): 12:18am On Jul 14, 2018
Cc; pes13,Nltaliban,damayogenius
Re: UI 2018/2019 Admission Thread by kenine45: 3:46am On Jul 14, 2018
IMPORTANT ANNOUNCEMENT

TBOSE TUTORS PRESENTS HER 5th STANDARD PERIODIC MOCK TEST OF OPERATION CRUSH UI PUTME 2018.

As it is now OBVIOUS that UI PUTME is in a few weeks time, it is good that one prepares and sets a target for the exam.

This is why TBOSE TUTORS has prepared a nice avenue to weigh yourself under same standard temperature and pressure as the exam.

Note :
1. No calculator is allowed
2. 100 questions in 85mins
I beg you not to joke with this opportunity.
Venue : Abadina primary school 1, UI
Date : 21st of July( next week Saturday )
Time : 10:30am (if you are 30 mins late, you won't be allowed in)
Price : #500

There will be prize for the 1st and 2nd
Science and non science inclusive
Get a #50 bike from UI gate and call "Abadina primary school 1." You will see our banner at the gate with some people to direct you. Make sure it is

TBOSE TUTORS as many tutorials are around.
If you are far away you can register for it before then and participate at the same time with us here. The questions will be sent to you on WhatsApp.

The correction will be done on Monday and it is free for all participants only.

Your Success, Our Mandate
For more enquiries, contact AJESEN on 08169993852

Signed
TBOSE TUTORS
Re: UI 2018/2019 Admission Thread by KINGBEN1(m): 7:32am On Jul 14, 2018
Pls What's going on I can't login into the portal for my registration ... anyone with same problem

I placed reg no and surname it's not loging in

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