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Nairaland Forum / Nairaland / General / Education / UI 2018/2019 Admission Thread (343700 Views)
Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)
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Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 11:58pm On Jul 20, 2018 |
The correct answers are marked with * DrBESTJC: |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:12am On Jul 21, 2018 |
Correct answers are marked with * DrBESTJC: |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:16am On Jul 21, 2018 |
Eben331: I hope you can now see the corrections clearly? |
Re: UI 2018/2019 Admission Thread by Nobody: 12:36am On Jul 21, 2018 |
please I tried registering for the p-utme but it was showing incorrect password or username. what could be the problem. |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:59am On Jul 21, 2018 |
Aceed: Note: Specific heat capacity of copper = 0.4 J.g-1K-1 . Solution: Heat lost by copper ball = Heat gained by water + Heat gained by copper calorimeter. M(mass of copper ball) x c(specific heat capacity of copper) x theta(initial temperature of copper) = m(mass of water) x c(specific heat capacity of water) x theta (change in temperature of water after the copper ball has been placed in it) + m(mass of copper calorimeter) x c(specific heat capacity of copper calorimeter) x theta (change in temperature of the calorimeter after the copper ball has been placed in it) .... But we are required to find the final steady temperature...So, Let the final steady temperature be T. Substututing T in the formula above, we have; m x c x theta = m x c x (T- initial temperature of water before the copper ball was placed in it) + m x c x (T- initial temperature of calorimeter before the copper ball was placed in it) Now,substituting the numerical values,we have: 20 x 0.4 x 200 = 50 x 4.2 x (T-30) + 60 x 0.4 x (T-30) 1600 = 210T - 6300 + 24T - 720 1600 = 234T - 7020 1600 + 7020 = 234T 8620 = 234T .: T = 8620/234 = 38.84K (approximately) |
Re: UI 2018/2019 Admission Thread by esivue007(m): 6:50am On Jul 21, 2018 |
Eben331:i think d news dat was posted here by sulegee has did it all couple wit d info dat i got frm ui |
Re: UI 2018/2019 Admission Thread by esivue007(m): 6:58am On Jul 21, 2018 |
@drbest jc,i think it will be right if u post d glycolysis question in d medical thread |
Re: UI 2018/2019 Admission Thread by Eben331: 7:11am On Jul 21, 2018 |
DrBESTJC:Yeah...Thanks. |
Re: UI 2018/2019 Admission Thread by Eben331: 7:12am On Jul 21, 2018 |
esivue007:Ok bro. |
Re: UI 2018/2019 Admission Thread by Eben331: 7:15am On Jul 21, 2018 |
DrBESTJC, pls help me solve that tension question. |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 8:39am On Jul 21, 2018 |
esivue007: There is no need.'BiafranDel' is very correct........doctors are here in this thread also Back to the question... Aceed: When I was reading my biology textbook(IDODO UME COLLEGE BIOLOGY) , I did not pay much attention to this....infact I skipped it!.....because it was not clear to me....and I did not understand it,but now I do....atleast to the extent of answering it in the exam if I see it! Please all boses in the house, let us work collaboratively to become more successful in this forthcoming PostUTME. Nobody knows it all.The ones you know,please be kind enough to teach us by posting here and answering questions.... If you have the aforementioned textbook,you can turn to page 178 of chapter 8 and read it explained. It reads in part : Chemical processes of cellular respiration. Cellular respiration occures in two main stages involving a series of chemical reactions and respiratory enzymes. First Stage: Glycolysis ( sugar-breaking process) in the cytoplasm (Anaerobic) The glucose molecule is phosphorylated by an addition of phosphate group to the glucose to become glucose phosphate. Through series of oxidative enzymes , the glucose phosphate is converted to two molecules of triose sugar (a 3-carbon sugar). The triose sugar is converted to pyruvic acid by the removal of four atoms of hydrogen by a co-enzyme called NAD(Nicotinamide adenine dinucleotide) with the formation of 2ATP. Second Stage: [b] Anaerobic respiration in Mitochondria If sufficient oxygen is available, each molecule of pyruvic acid(pyruvate) is oxidized to remove one molecule of carbon(IV)oxide(decarboxylation) and two atoms of hydrogen(dehydrogenation) forming one molecule of acetic acid, a 2-carbon acid.Carbon(IV)oxide is released. Krebs' cycle or citric acid cycle The acetic acid enters into a Krebs' cycle where it is joined to a 4-carbon acid(oxaloacetic acid) present in the mitochondrion to form citric acid(a 6-carbon acid) Conclusively, the enzymes of the glycolytic pathway are located in the cytoplasm and the enzymes of the Krebs cycle are located in the mitochondrion. 2 Likes |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 10:08am On Jul 21, 2018 |
Eben331:That question.... No be here o. Whats d final answer? But ve sent d question to dammy |
Re: UI 2018/2019 Admission Thread by Eben331: 10:19am On Jul 21, 2018 |
Gracy3535:Tell Damayogenius18 to come to Nairaland, it is not all of us that have access to WhatsApp. You also should visit Nairaland often. |
Re: UI 2018/2019 Admission Thread by Eben331: 12:58pm On Jul 21, 2018 |
A resonance tube is 40cm long. The tube is three-quarter full. What is the frequency of the turning fork placed near the mouth of the tube? (velocity of sound in air=334m/s) (A) 2511Hz (B) 1670Hz (C) 835Hz (D) 345Hz PLS SHOW YOUR WORKINGS!! |
Re: UI 2018/2019 Admission Thread by BiafranDel: 1:24pm On Jul 21, 2018 |
Eben331: the full length,L of the tube=40cm=0.4m. It is 3 quarter filled with water i.e 0.4*3/4= 0.3m which is the length of water. To find the length of air we say, length of tube - length of water i.e 0.4 - 0.3= 0.1m. for a closed pipe. fundamental frequency F= velocity/wavelength(4l) where vel= 334m/s, wavelength= 4L i.e 4*0.1= 0.4m. Therefore frequency = 334/0.4, frequency= 835hertz. D |
Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 2:01pm On Jul 21, 2018 |
Eben331: Yesooooo.......na here e dey happen. Everybody should come to nairaland abeg. Facebook I know, Nairaland I know,..........Who be Whatsapp |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 2:26pm On Jul 21, 2018 |
DrBESTJC:even me its nt everytime i ve mb to access whatsapp.. U guyz shuld give me ur facebook ID |
Re: UI 2018/2019 Admission Thread by BiafranDel: 2:35pm On Jul 21, 2018 |
Gracy3535:babe holla me. I just feel like to subscribe for you. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 2:40pm On Jul 21, 2018 |
BiafranDel:lol wats ur ID na |
Re: UI 2018/2019 Admission Thread by BiafranDel: 2:51pm On Jul 21, 2018 |
Gracy3535:text me yours. lemme add you up. I can't access my mails. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 2:54pm On Jul 21, 2018 |
BiafranDel:Grace Adeniyi am puttin on red headgear & yellow top (facebook) |
Re: UI 2018/2019 Admission Thread by Eben331: 2:55pm On Jul 21, 2018 |
Gracy3535:I will add you up. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 2:56pm On Jul 21, 2018 |
Eben331:ok add up ve post mine |
Re: UI 2018/2019 Admission Thread by Eben331: 2:59pm On Jul 21, 2018 |
BiafranDel:Bro, the answer that was gotten was 2511Hz. I don't knw how they come abt it. |
Re: UI 2018/2019 Admission Thread by BiafranDel: 3:18pm On Jul 21, 2018 |
Gracy3535:I couldn't find you o. Is that your full i.d or you have any other name added to it? Did you attach your mobile number on your profile. |
Re: UI 2018/2019 Admission Thread by BiafranDel: 3:20pm On Jul 21, 2018 |
Eben331:okay. Post the calculation let me see |
Re: UI 2018/2019 Admission Thread by Eben331: 3:35pm On Jul 21, 2018 |
BiafranDel:Someone send the question to me. |
Re: UI 2018/2019 Admission Thread by BiafranDel: 3:39pm On Jul 21, 2018 |
Eben331:okay. Tell the person to send the workings. |
Re: UI 2018/2019 Admission Thread by Eben331: 3:49pm On Jul 21, 2018 |
BiafranDel:The person couldn't solve it, dat's why he sent it to me. |
Re: UI 2018/2019 Admission Thread by Eben331: 3:51pm On Jul 21, 2018 |
Eben331:Someone should help me with dis. |
Re: UI 2018/2019 Admission Thread by BiafranDel: 4:11pm On Jul 21, 2018 |
Eben331:so how did he get 2511 as the answer if he could not solve it. Didn't you solve it yourself, what did you get? |
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