UI 2018/2019 Admission Thread - Education (100) - Nairaland
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Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)
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| Re: UI 2018/2019 Admission Thread by kenine45: 10:29pm On Aug 05, 2018 |
join us this Saturday
come WEIGH yourself make sure it is TBOSE TUTORS signed TBOSE TUTORS
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| Re: UI 2018/2019 Admission Thread by Rotemycetes: 9:14am On Aug 06, 2018 |
Good day nairalanders, a friend of mine applied for the 2018 UI post utme, he erroneously applied for the masters admission instead of the undergraduate admission. now he is having issues with continuing registration. please what should be done? Thank you |
| Re: UI 2018/2019 Admission Thread by Rotemycetes: 9:18am On Aug 06, 2018 |
Rotemycetes: |
| Re: UI 2018/2019 Admission Thread by onlyme07(m): 9:21am On Aug 06, 2018 |
Rotemycetes: Masters is 16k and 21k respectively and Masters does not require Jamb number. Your story get k-leg. Anyway,the site for undergrad is admissions.ui.edu.ng. Only Jamb number and Surname is required to generate invoice and continue registration 2 Likes |
| Re: UI 2018/2019 Admission Thread by callyik(m): 10:00am On Aug 06, 2018 |
Nnamdi Azikiwe University has announced the commencement of sale of her Post Utme form for the 2018/2019 academic session which is to end on the 22nd of August 2018. Documents needed for a successful registration: 1.Jamb reg. Number 2. Gmail account 3. LGA & state 4. Date of birth 5. Resident address 6. Name of sponsor & his phone no. 7. Waec/ Nabteb result. Are you interested in picking up the form and registering quickly and without hassle? Is your current location far from Awka? Do you have a tight schedule? Let us handle it for you. For further enquiries, Call or WhatsApp: 07012289926, 07031641773. 24 hour quality delivery. Money back guarantee |
| Re: UI 2018/2019 Admission Thread by Major0303(m): 11:21am On Aug 06, 2018 |
Please help m, which bank are they paying? When I got to first bank ado, I was told that they are not doing it in the bank. Very urgent. |
| Re: UI 2018/2019 Admission Thread by Bibbyiana16: 1:55pm On Aug 06, 2018 |
Please am registering for University of Ibadan putme for my sis, I can't seem to move from the photo and signature page. Please what do I do? |
| Re: UI 2018/2019 Admission Thread by Teekzel(m): 6:40pm On Aug 06, 2018 |
A small metal ball is thrown vertically upwards from the top of tower with an initial velocity of 20ms-1. If the ball took a total of 6s to reach ground level, determine the height of the tower. ( g = 10ms-2) |
| Re: UI 2018/2019 Admission Thread by overcomer90: 6:53pm On Aug 06, 2018 |
Bibbyiana16:Use laptop not ur phone |
| Re: UI 2018/2019 Admission Thread by dmwears(m): 6:58pm On Aug 06, 2018 |
Contact me for the online registration of any post-UTME. I can handle the registration while you print out your slip from your location. Call/WhatsApp: 08066642832 |
| Re: UI 2018/2019 Admission Thread by overcomer90: 7:47pm On Aug 06, 2018 |
Distance between top of tower and maximum ht. is given by V²= U² + 2as U = initial velocity = 20m/s At maximum ht. V = 0 a = -10m/s since it is initially moving upwards We have that 0= 20² + 2*-10*s 20²= -20s => s = 20m (This is the distance between top of tower and maximum ht.)The time taken for this initial motion is given by s = ut + 1/2at² Where s is now = 20m u = 20m/s t =? a=-10m/s² Solving for t u have that t = 2 secs (time taken to reach maximum ht.) The next step u find the distance from the maximum ht to d ground given by s = ut + 1/2at² The time here is the total time - the time taken to reach maximum ht. = 6-2 t= 4secs U = 0 when it is falling down a= 10m/s² Solving for s u have that s = 80m ( distance from the maximum ht to d ground) Last step Height of tower =(distance from the maximum ht to d ground - distance from top of tower to the maximum ht) Teekzel:H = 80m - 20m H = 60m |
| Re: UI 2018/2019 Admission Thread by IFEOLUWAKRIZ: 8:14pm On Aug 06, 2018 |
Bibbyiana16: Have you tried reducing the photo's size? |
| Re: UI 2018/2019 Admission Thread by Seamione(m): 8:16pm On Aug 06, 2018 |
Any mathematics aspirant here yet? |
| Re: UI 2018/2019 Admission Thread by kenine45: 10:39pm On Aug 06, 2018 |
Join us@TBOSE TUTORS
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| Re: UI 2018/2019 Admission Thread by Memunah(f): 10:57pm On Aug 06, 2018 |
Good day house, Please I need your help. My sis paid at zenith bank through remita The instructions on the site says one should click on synchronise bank payment,did that and its keep showing 'None of your transactions was successful'..tried it countless times. Please what am I doing wrong? Help me out please |
| Re: UI 2018/2019 Admission Thread by Nobody: 12:42am On Aug 07, 2018 |
My brother couldn't find his year of examination where he was asked to chose examib6year. He did his First O'level in 2016. The examination year on the webpage ends 2014. Please, any solution (s) to this problem. |
| Re: UI 2018/2019 Admission Thread by freshsteph: 12:45am On Aug 07, 2018 |
yah i'm back..... eben repost your question...... |
| Re: UI 2018/2019 Admission Thread by nurex01(m): 12:45am On Aug 07, 2018 |
My brother couldn't find his year of examination where he was asked to chose examination year. He did his First O'level in 2016. The examination year on the webpage ends 2014. Please, any solution (s) to this problem. Cc; pes13 |
| Re: UI 2018/2019 Admission Thread by Rotemycetes: 11:01am On Aug 07, 2018 |
onlyme07: I thought as much too, cos they operate two different platforms for undergraduate and masters t hank you |
| Re: UI 2018/2019 Admission Thread by Memunah(f): 11:26am On Aug 07, 2018 |
Please I need help on this.. Please Memunah: |
| Re: UI 2018/2019 Admission Thread by Sofia01: 11:39am On Aug 07, 2018 |
please where can I get likely current affairs practice questions for ui post utme. |
| Re: UI 2018/2019 Admission Thread by Pes13: 11:41am On Aug 07, 2018 |
nurex01: Nltaliban IFEOLUWAKRIZ Ajet001 Sirgalahad26 WHAT are your takes on this |
| Re: UI 2018/2019 Admission Thread by Nltaliban(m): 11:56am On Aug 07, 2018 |
Doctuur: Please be more explicit.. But if it's what I'm thinking, the examination year can never end 2014 because Ui welcomes even fresh graduates (who must have taken this year's waec) Maybe you should try another browser |
| Re: UI 2018/2019 Admission Thread by Nltaliban(m): 11:57am On Aug 07, 2018 |
Sofia01: Ui will never ask current affairs |
| Re: UI 2018/2019 Admission Thread by Nltaliban(m): 11:57am On Aug 07, 2018 |
Memunah: Is it up to 24 hours? It takes time for bank payment to reflect |
| Re: UI 2018/2019 Admission Thread by Nobody: 11:58am On Aug 07, 2018 |
Memunah:First, I hope u got a remita printout showing the successful payment from the zenith bank. If so, the payment was successful. Since it's not yet showing on UI portal, contact the helpdesk using the phone number displayed on the portal |
| Re: UI 2018/2019 Admission Thread by Sofia01: 12:42pm On Aug 07, 2018 |
Nltaliban:Thank you 1 Like |
| Re: UI 2018/2019 Admission Thread by IFEOLUWAKRIZ: 1:53pm On Aug 07, 2018 |
nurex01: log out then try logging back with another browser Chrome or Firefox |
| Re: UI 2018/2019 Admission Thread by IFEOLUWAKRIZ: 1:58pm On Aug 07, 2018 |
Sofia01:  ?Current affairs?? Ui Don't think so but sha try and be following ECOWAS meetings.. If UNO own will take place before the post utme, then follow it too. Our president was elected ECOWA's chairman last week..Take note of this in government |
| Re: UI 2018/2019 Admission Thread by Rotemycetes: 2:55pm On Aug 07, 2018 |
[quote author=Rotemycetes post=70059034] I thought as much too, cos they operate two different platforms for undergraduate and masters t hank yo please what is the minimum utme score that qualifies one to register for post utme? |
| Re: UI 2018/2019 Admission Thread by Teekzel(m): 4:38pm On Aug 07, 2018 |
[quote author=overcomer90 post=70043778]Distance between top of tower and maximum ht. is given by V²= U² + 2as U = initial velocity = 20m/s At maximum ht. V = 0 a = -10m/s since it is initially moving upwards We have that 0= 20² + 2*-10*s 20²= -20s => s = 20m (This is the distance between top of tower and maximum ht.)The time taken for this initial motion is given by s = ut + 1/2at² Where s is now = 20m u = 20m/s t =? a=-10m/s² Solving for t u have that t = 2 secs (time taken to reach maximum ht.) The next step u find the distance from the maximum ht to d ground given by s = ut + 1/2at² The time here is the total time - the time taken to reach maximum ht. = 6-2 t= 4secs U = 0 when it is falling down a= 10m/s² Solving for s u have that s = 80m ( distance from the maximum ht to d ground) Last step Height of tower =(distance from the maximum ht to d ground - distance from top of tower to the maximum ht) H = 80m - 20m H = 60m [/quote/] correct |
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