Dkfpaul:
good day to you all.
I got 65.375 as my aggregate score, aspiring for education and political science even though last year cut off was 61.5 for the course. Need your advice.


what is my chance on this score?
is their any probability that the Cut off for this year will exceed 65.375?

Bro choi wat an escape...Ur score is equivalent to d cutoff...welcome to ui...we gonna meet next session by God grace

Thanks in anticipation.

Dkfpaul:
pls I need urgent reply to this question.

A graduate of Education and Economics of University of Ibadan Will be given B.sc(Ed) or just ordinary B.Ed ?

PatrickOA:
Whoever attended the end of the year party will testify it was a banger ���... Lectures begin January 7th... Tell your younger siblings, niblings, that your stubborn cousin to attend and join the list of successful candidates...

midehill:



Pls Wich lecture are u talking abt

babablogger:
for psychology English Language and any other 3 subjects from Social Sciences and/or Sciences.
They updated it last month

tundexweb:

Hello bro.
Is this subject combination good for psychology?
Eng,economics, government, literature..�

babablogger:
i'm not sure about literature though, but that's what you wrote in UTME right?

tundexweb:

I am about to register for UTME

samuelizz:


1. KE is converted to PE

½mv² = mgh

v² = 2gh.

h = 5cm = 0.05m

v² = 2(10)0.05

v = √1

v = 1ms-¹


2, the acceleration doubles when the force doubles, since the mass is kept constant.

3. y = vertical component, x = horizontal component

V² = U² + 2gh

30² - 10² = 2gh

h = 40m.

H = ½gt²

40 = ½(10)t²

t = 2√2s. ( time taken for the journey)

Now to the ball thrown horizontally,

Vx = Ux = 10ms-¹

Vy = Uy + gt..

Uy = 0, since the ball was thrown horizontally, the vertical component is zero

Vy = 10(2√2)

Vy = 20√2ms-¹

V = √(Vx² + Vy²)

V = √(10²) + (20√2)²

V = √(100 + 800)

V = √(900)

V = 30ms-¹


4. KE = ½mv² = ½m(20²)

KE = 200m

PE = mgh = m(100)10

PE = 1000m

% = 200m/1000m × 100

m cancels out with annoyance..

% = 0.2 × 100

% = 20%


5. mass of water = 5 - 4.26 = 0.74g

mass of anhydrous salt = 4.26g

Mass of water/mass of anhydrous salt = 18x/molar mass of salt

0.74/4.26 = 18x/208


x ≈ 2( the number of molecules of water)

Hardebaryor:
@bolded how does the final speed equals the initial speed?

simonjassy:
Please, any uite here who Knows when ui will resume their academic calendar?.my friend says it tomorrow, though i have doubts considering the election has been postponed.

shoyemiayodeji:

Tomorrow

rafo200:
*Important Information to All UTME Candidates across the Nation.*

Now that UTME 2019 is here, the management of *Team Tutors, Ibadan* present Jamb marathon revision camp tagged *"Weapon of Jamb Destruction"*�� which holds *a week to Jamb*.

Date : � April 4th to 10th 2019
Time : �7a.m. to �7p.m. daily
Venue : �Lawn tennis court S.U.B, UI

*Featuring:*
_Revision of all important topics;_
_Critical analysis of past questions_
_Final standard mock Exam(CBT)_

```Meet few of our stuffy tutors```
�Lord Morgan
�Dr Mark
�Dr Marco genius
�Dr Black
�Sir Noah
```and many more.```

```Our 2018 records speak```
*_•Adubi Damilola_ 338 _Medicine UI_*
*_•Omayajowo Femi_ 326 _Elect Engineering, UI_*
*_•Makinde Ojo Samuel_ 319 _Medicine UI_*
*_•Oluborode Daniel_ 317 _Medicine ,UI_* *_and many more..._*

ACCOMMODATION is available for distant students.
For more enquiries: 07039412017

_*Even If you have planned to fail, your plan will fail, just come.*_