urchrlex:

1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzFizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzFizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzFizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzFizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
73
74
FizzFizzBuzz
76
77
Fizz
79
Buzz
Fizz
82
83
Fizz
Buzz
86
Fizz
88
89
FizzFizzBuzz
91
92
Fizz
94
Buzz
Fizz
97
98
Fizz
Buzz

Yelp. Basically same solution I have.

However, there's a slight change needed for your program...

When a number is divisible by both 3 and 5, you're to print "fizzbuzz" AND NOT "FizzFizzBuzz".

jelel6:


Yelp. Basically same solution I have.

However, there's a slight change needed for your program...

When a number is divisible by both 3 and 5, you're to print "fizzbuzz" AND NOT "FizzFizzBuzz".

The logic question is incorrct with outcome they want
for(var i=1; i<101; i++){
var tr = "", fi ="", no="", bo="";
if(i % 3 == 0 && i % 5 != 0){
tr = "Fizz";
}
if(i % 5 == 0 && i % 3 != 0){
fi = "Buzz";
}
if(i % 5 == 0 && i % 3 == 0){
bo = "FizzBuzz";
}
if(i % 5 != 0 && i % 3 != 0){
no = i;
}
console.log(no +tr + fi + bo);
}

Bizmagnet:

Similar to a question Microsoft gave me last year at their interview. Omo, I not fit do am until the time expired.
Question: If A=1, B=2, C= 3, ..., Z=26. Write a program (Javascript) that returns every word whose sum equals to 100.
The truth of the matter is writing algorithm in a timed test may not be best to access Programmers because atimes you may need to think and think before you get the problemm solved which time may not permit.

const characode = function(words){
const letters = {"A":"1","B":"2","C":3,
"":4,"E":"5","F":"6","G":"7","H":"8","I":"9","J":"10","K":"11",
"L":"12","M":"13","N":"14","O":"15","P":"16","Q":"17","R":"18","S":"19","T":"20",
"U":"21","V":"22","W":"23","X":"24","Y":"25","Z":"26"};
var mat = letters[words];
return mat;
}
function sumwords(word){
var words = word.toUpperCase();
var sum = 0;
sum += 0;
for(var i = 0; i < words.length; i++) {
var fo = parseFloat(characode(words[i]));
sum += fo;
}

return sum;


}
var mywords ="apple"
console.log(sumwords(mywords));

urchrlex:


const characode = function(words){
const letters = {"A":"1","B":"2","C":3,
"":4,"E":"5","F":"6","G":"7","H":"8","I":"9","J":"10","K":"11",
"L":"12","M":"13","N":"14","O":"15","P":"16","Q":"17","R":"18","S":"19","T":"20",
"U":"21","V":"22","W":"23","X":"24","Y":"25","Z":"26"};
var mat = letters[words];
return mat;
}
function sumwords(word){
var words = word.toUpperCase();
var sum = 0;
sum += 0;
for(var i = 0; i < words.length; i++) {
var fo = parseFloat(characode(words[i]));
sum += fo;
}

return sum;


}
var mywords ="apple"
console.log(sumwords(mywords));

Similar to a question Microsoft gave me last year at their interview. Omo, I not fit do am until the time expired.
Question: If A=1, B=2, C= 3, ..., Z=26. Write a program (Javascript) that returns every word whose sum equals to 100.
The truth of the matter is writing algorithm in a timed test may not be best to access Programmers because atimes you may need to think and think before you get the problemm solved which time may not permit.[/quote]

const characode = function(words){
const letters = {"A":"1","B":"2","C":3,
"":4,"E":"5","F":"6","G":"7","H":"8","I":"9","J":"10","K":"11",
"L":"12","M":"13","N":"14","O":"15","P":"16","Q":"17","R":"18","S":"19","T":"20",
"U":"21","V":"22","W":"23","X":"24","Y":"25","Z":"26"};
var mat = letters[words];
return mat;
}
function sumwords(word){
var words = word.toUpperCase();
var sum = 0;
sum += 0;
for(var i = 0; i < words.length; i++) {
var fo = parseFloat(characode(words[i]));
sum += fo;
}

if(sum == 100){
return word;
}else{
return "The sum of the word is not 100";
}


}
var mywords ="apple"
console.log(sumwords(mywords));

urchrlex:

The logic question is incorrct with outcome they want
for(var i=1; i<101; i++){
var tr = "", fi ="", no="", bo="";
if(i % 3 == 0 && i % 5 != 0){
tr = "Fizz";
}
if(i % 5 == 0 && i % 3 != 0){
fi = "Buzz";
}
if(i % 5 == 0 && i % 3 == 0){
bo = "FizzBuzz";
}
if(i % 5 != 0 && i % 3 != 0){
no = i;
}
console.log(no +tr + fi + bo);
}

It is correct. You're correct also, just the part where you pass the string "fizzfizzbuzz" instead of "fizzbuzz".

exchangedrive:
I have received applications from a handful but it is rather sad, that nobody is willing to take the online assessment (test).
Some would rather want to drop samples of jobs done in times past; which is not a true reflection of a developer's ability;
since such jobs might have been a collaborative effort.
Thus, we require applicants to take the online assessment in real-time.
Thank you.

Victorukafor@gmail.com

jelel6:


It is correct. You're correct also, just the part where you pass the string "fizzfizzbuzz" instead of "fizzbuzz".

With Python :

num = list(range(1, 101))

for i in num:
if i%3 and i%5 == 0:
print ('FizzBizz')
elif i%3 == 0:
print ('Fizz')
elif i%5 == 0:
print('Bizz')
else:
print(i)

urchrlex:


Similar to a question Microsoft gave me last year at their interview. Omo, I not fit do am until the time expired.
Question: If A=1, B=2, C= 3, ..., Z=26. Write a program (Javascript) that returns every word whose sum equals to 100.
The truth of the matter is writing algorithm in a timed test may not be best to access Programmers because atimes you may need to think and think before you get the problemm solved which time may not permit.

const characode = function(words){
const letters = {"A":"1","B":"2","C":3,
"":4,"E":"5","F":"6","G":"7","H":"8","I":"9","J":"10","K":"11",
"L":"12","M":"13","N":"14","O":"15","P":"16","Q":"17","R":"18","S":"19","T":"20",
"U":"21","V":"22","W":"23","X":"24","Y":"25","Z":"26"};
var mat = letters[words];
return mat;
}
function sumwords(word){
var words = word.toUpperCase();
var sum = 0;
sum += 0;
for(var i = 0; i < words.length; i++) {
var fo = parseFloat(characode(words[i]));
sum += fo;
}

if(sum == 100){
return word;
}else{
return "The sum of the word is not 100";
}


}
var mywords ="apple"
console.log(sumwords(mywords));

You didn't get the question bro. The question is to return all words such that when you add all its letters, it will give 100. What you did is test for words whose letter sum up to 100.

Bizmagnet:

You didn't get the question bro. The question is to return all words such that when you add all its letters, it will give 100. What you did is test for words whose letter sum up to 100.

Post the right answer Bro. If you want it the way you stated then contact me because u will PAY some dollars!

urchrlex:


Post the right answer Bro. If you want it the way you stated then contact me because u will PAY some dollars!

Lolz. Like I stated earlier, I was given the question at an interview which I couldn't solve till the time expired. You're good I must confess but that answer is not accurate. What's your stack? I wouldn't know if you can chat me up to discuss something.

Hi, I am a full stack developer vast in PHP, laravel and software architecture.

You can contact me
Whatsapp: 2347038257962
Email: akinbami.gbenga@gmail.com

Bizmagnet:

Similar to a question Microsoft gave me last year at their interview. Omo, I not fit do am until the time expired.
Question: If A=1, B=2, C= 3, ..., Z=26. Write a program (Javascript) that returns every word whose sum equals to 100.
The truth of the matter is writing algorithm in a timed test may not be best to access Programmers because atimes you may need to think and think before you get the problemm solved which time may not permit.

I came across this thread late last night - yes, I know its been over a year but I got interested in this question above ^^
Anyway, I bookmarked it and came back this morning (I deliberately avoided thinking about it in the night so I could simulate it being a random sudden test). Here's my answer::

//start time: 10:01am

function wordValue(word) {
let chars = ["A","B","C","","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"];
function getWordValue(word) {
let wordUpperC = word.toUpperCase();
let wordValue = 0;
for (let letter of wordUpperC) {
for (let char of chars) {
if (letter == char) {
wordValue += (chars.indexOf(char)+1);
}
}
}
return wordValue;
}
if (getWordValue(word) == 100) console.log(word);
else console.log("The given word does not add up to 100" );
}

//end time 10:35am

I feel kinda proud, finished it all plus troubleshooting/testing in less than 40mins (used a bunch of random words and then "Jttttj" to test).
I did a teeny-tiny small ojoro sha; I couldn't remember the string method for converting to upper case letters, so I googled it. But everything else I wrote by myself from scratch.

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