Mrshape:
I am having difficulty posting shape with my other account thus I created this as a supplement fellow friends of shape.
Solve

this one want make we know say him go school. afonja

Na wa oo this guys did not even play playstation that's R=2 na check the back

Funaki:


when I used cosine rule with r=7. I got total angle around 390. that's too much

I think the cosine and sine values are also approximate values. I don't know why the deviation is that much.
Can u please share your preferred solution to the question.
I might be wrong though.

dacool1:

I think the cosine and sine values are also approximate values. I don't know why the deviation is that much.
Can u please share your preferred solution to the question.
I might be wrong though.

I couldn't solve it guy . I'm sorry I'm tackling you.

r=11.5

Funaki:


I couldn't solve it guy . I'm sorry I'm tackling you.

No qualms. I was only eager to learn from you. Keep trying other possible solutions you might find one. Nice conversation by the way.

r = 7

Smile no one has got it,
I will post solution later
Since it is already in frot page lets wait maybe someone will come with a solution

dacool1:

No qualms. I was only eager to learn from you. Keep trying other possible solutions you might find one. Nice conversation by the way.

Alright champ

NothingDoMe:
Solved=7

7 is not correct

Mrshape:

7 is not correct

Na eye I use calculate am

In secondary school when there's no time we just do rough estimates based on observed distance on paper

NothingDoMe:
Na eye I use calculate am

In secondary school when there's no time we just do rough estimates based on observed distance on paper

OK make a solution and update your post people are looking up to u
I Am waiting sir

Gentle20love:
R = 9

Not correct sir
try again sir

chloride6:
Simple



Let's see using the sin rule

R divided by the angle opposite to the prime number chord

This relation holds for all the prime numbers chords...

The sum of the opposite angles equals 360

While the sum of interior angles equals n-2 by 180

Solve for the rest..

Can you through more light on your methodology, I don't see any positive result from your explanation yet, please explain more

kombats:
r = 8.5
Prime = 17

Not correct sir
Try again sir

Adanairaland:
R = 17

Not correct madam.
Try again please

Mrshape:

Not correct madam.
Try again please

You are not nice at all sha

See the way you told me straight to my face that am wrong




.

I'll try next time

Advantaged1:
9

9 is not a prime number .

Mrshape:

Not correct madam.
Try again please

Is it 7.4?

DrayZee:

Is it 7.4?

Approximately 7.4
You are the first person to get it,
Show your workings sir

NothingDoMe:
Na eye I use calculate am

In secondary school when there's no time we just do rough estimates based on observed distance on paper

Na so my brother, but next time make u just take the number before which is 7 and put . Anything eg, 7.3, 7.4, 7.5 Who get time as no time to waste time. If dem like make dem wrong am, e no kuku comot or add one naira to my pocket

Mrshape:

Approximately 7.4
You are the first person to get it,
Show your workings sir

Yo, I did it graphically . Was giving me a hard time.

I'd like to see the solution sha.

R 17 Or 7 no number can divide a prime numbers except itself and 1

Martinez39:
Post them. I have tried to no avail.

Let the anglees subtended at the center of each sector

by the perpendicular line draw from the circle centre

@1,@2,@3,@4,@5,@6

@1+@2+@3+@4+@5+@6=180

Sin^-1(1/R) +sin^-1(1.5/R)+sin^-1(2.5/R)+sin^-1 (3.5/R)

+sin^-1 (5.5/R)+sin^-1 (6.5/R)=180

The substitute values into R to check which is the

closest to 180° note you should start from values grater

than 6.5 because height of the longest chord

h=√(R^-6.5)

Note walfrom aphal can't even compute that and get

numerical values, so only substitution works or graph it

Thus R =7.4233units.
Look forward to my next shape, I remain Mr shape your shape lover,

Mrshape:

Let the anglees subtended at the center of each sector

by the perpendicular line draw from the circle centre

@1,@2,@3,@4,@5,@6

@1+@2+@3+@4+@5+@6=180

Sin^-1(1/R) +sin^-1(1.5/R)+sin^-1(2.5/R)+sin^-1 (3.5/R)

+sin^-1 (5.5/R)+sin^-1 (6.5/R)=180

The substitute values into R to check which is the

closest to 180° note you should start from values grater

than 6.5 because height of the longest chord

h=√(R^-6.5)

Note walfrom aphal can't even compute that and get

numerical values, so only substitution works or graph it

Thus R =7.4233units.
Look forward to my next shape, I remain Mr shape your shape lover,

Make a sketch of the shape for your solution.

When you draw another line from the center of the circle, you'd form a 45 45 90 triangle. So 11=x√2, thereon you can solve for x

,

How

Is there any typographical error there cos u did not include 4.5 in the summation

Mrshape:

Let the anglees subtended at the center of each sector

by the perpendicular line draw from the circle centre

@1,@2,@3,@4,@5,@6

@1+@2+@3+@4+@5+@6=180

Sin^-1(1/R) +sin^-1(1.5/R)+sin^-1(2.5/R)+sin^-1 (3.5/R)

+sin^-1 (5.5/R)+sin^-1 (6.5/R)=180

The substitute values into R to check which is the

closest to 180° note you should start from values grater

than 6.5 because height of the longest chord

h=√(R^-6.5)

Note walfrom aphal can't even compute that and get

numerical values, so only substitution works or graph it

Thus R =7.4233units.
Look forward to my next shape, I remain Mr shape your shape lover,

radius is 9 or your shape is undefined

perpeling22:
Abeg is this further maths or ....,. .

No insult pleaseoooo

There's nothing like "further" math, math is math.

But no this isn't in the f.math curriculum.

Mrshape:


Let the anglees subtended at the center of each sector

by the perpendicular line draw from the circle centre

@1,@2,@3,@4,@5,@6

@1+@2+@3+@4+@5+@6=180

Sin^-1(1/R) +sin^-1(1.5/R)+sin^-1(2.5/R)+sin^-1 (3.5/R)

+sin^-1 (5.5/R)+sin^-1 (6.5/R)=180

The substitute values into R to check which is the

closest to 180° note you should start from values grater

than 6.5 because height of the longest chord

h=√(R^2-6.5^2)

Note walfrom aphal can't even compute that and get

numerical values, so only substitution works or graph it

Thus R =7.4233units.
Look forward to my next shape, I remain Mr shape your shape lover,

Smart method but not cool. I was a bit shocked that you resorted to trial and error and this makes the problem less interesting. This method can work for any polygon with sides of arbitrary length and you made it look like we were supposed to use a property of prime numbers to arrive at the solution.