Can someone solve this maths problem

Help

Triangle ABC is similar to triangle ADE. Therefore,
AC ÷ AE = BC ÷ DE,
6 ÷ 4 = 5 ÷ DE,
6 × DE = 5 × 4,
DE = 20/6
DE = 10/3 = 3.33 cm

dejt4u:
Triangle ABC is similar to triangle ADE. Therefore,
AC ÷ AE = BC ÷ DE,
6 ÷ 4 = 5 ÷ DE,
6 × DE = 5 × 4,
DE = 20/6
DE = 10/3 = 3.33 cm

My brother, you sabi book. Thanks so much for the support.

dejt4u:
Triangle ABC is similar to triangle ADE. Therefore,
AC ÷ AE = BC ÷ DE,
6 ÷ 4 = 5 ÷ DE,
6 × DE = 5 × 4,
DE = 20/6
DE = 10/3 = 3.33 cm

I trust you'd be here already

Gaddafi1:


My brother, you sabi book. Thanks so much for the support.

You can say that again. The guy na very intelligent (beyond brilliance) guy

adebayour26:

I trust you'd be here already

lol

My son's home work... JSS2. He can't thank me enough, special apprecitation again.

Another method..... 6/5=4/x.......cross multiply......6x=20.....x=20/6.....x=3.33