tolulopevoice:
Still waiting for solutions please

Ojayyonline:


please I think your question should be checked properly and then pls comment after u are sure of the question.

MathsEconomics:
Good day everyone.

MathsEconomics:
Good day everyone.

toroabasietim94:
Pls who can solve this

Martinez39:
ZERO.

toroabasietim94:
Pls who can solve this

Darivie04:

MathsEconomics:


1. You cannot treat an infinite product as a series unless you take the logarithm and study it.

2. Also, in using D'Alembert ratio test, you cannot make any conclusion if the ratio is one in this case it's better to use Cauchy Condensation Test or Bertrand's test.

Miracle112:
please I want solve this problem and I need guidance please.. someone should help/Guide me...

here is the problem..

1. obtain the angle between the lines 2y-4x+6=0 and y-2x-5=0



2.determine the distance between the line 4x-6y=6 and 3-3y+2x=0


3. Find the locus of a variable point P, if the distance of P from the X-axis is always three times its distance from the point (3, -3)



please mathematicians/physicians in the house should help abeg

Miracle112:
please I want solve this problem and I need guidance please.. someone should help/Guide me...

here is the problem..

1. obtain the angle between the lines 2y-4x+6=0 and y-2x-5=0



2.determine the distance between the line 4x-6y=6 and 3-3y+2x=0


3. Find the locus of a variable point P, if the distance of P from the X-axis is always three times its distance from the point (3, -3)



please mathematicians/physicians in the house should help abeg

MathsEconomics:
Difficult but solvable.

naturalwaves:

You mean Physicists
Physicians are related to medicine and similar stuffs.

Miracle112:


Okay
Thanks Man for the correction.
Can you helpe solve the problem?

Miracle112:
please I want solve this problem and I need guidance please.. someone should help/Guide me...

1. obtain the angle between the lines 2y-4x+6=0 and y-2x-5=0

2.determine the distance between the line 4x-6y=6 and 3-3y+2x=0

the distance, D between two parallel lines y = mx + a and y = mx + b is
D = |b - a|/√(1 + m²)

3. Find the locus of a variable point P, if the distance of P from the X-axis is always three times its distance from the point (3, -3)

please mathematicians/physicians in the house should help abeg

Martinez19:


here is the problem..

Both lines are parallel since their slopes are equal hence the angle between them is zero.



4x - 6y = 6 is equivalent to y = ⅔x - 1 . Also 3 - 3y + 2x = 0 is equivalent to y = ⅔x + 1 . Note that

In your question, a = -1 , b = 1 , and m=⅔ Substituting and solving, we have that
D = 6/√13


|y| = 3√[(x - 3)² + (y + 3)²]
y²= 9[(x - 3)² + (y + 3)²]
y² = 9( x² + y² - 6x + 6y + 18)
9x² + 8y² - 54x + 54y + 162 = 0
Completing the square and solving, you have
(8/9)(x - 3)² + (64/81)(y + (27/8 ) )² = 1
This is an ellipse.

I have done that. It's physicists not physicians.

MathsEconomics:
For everyone.

Darivie04:

After solving this problem I have arrived at the conclusion that there are no solutions.

MathsEconomics:


Can you continue from here?

Darivie03:

No like I actually solved the problem. My solutions included complex numbers meaning one where x,y,z are real numbers doesn't exist.

I solved it by factorizing equation 2 and 3 to obtain the values of x+y+z(given in the question to be 0), xyz(=6) and xy+yz+xz(=7). Then used the cubic equation idea you mentioned.

MathsEconomics:


There are actually two choices for t. t=±7
Here's a recurrence relation to use to confirm this.

dejt4u:
which app do you use to type maths please?

MathsEconomics:


MathMagic Lite.