NisforNicky:


Pls help with this.......


I need the workings

Question about the athlete not clear. Pls resend

ivumar:


The question on angle of elevation is, I think incorrect. Or what do you guys think... because I don't get how angle of elevation can be greater than 90 degrees.

thank you.

angles are meant to be in degrees not metres

femi4:
None of the options
Group with 12 teachers is rank 11
Percentile = 100R/N = 1100/12 = 92

how did you rank the group pls?

ivumar:

Question about the athlete not clear. Pls resend

alright

Nairaland's algorithm overcompressed the already faulty pic

Hey Boss. Pls check ur mail

ivumar:
Question about the athlete not clear. Pls resend

mete3:
Hey Boss.
Pls check ur mail

Replied bro

NisforNicky:

More

the percentile placement for the group with 12 teachers is 20%

NisforNicky:

More

the percentile placement for the group with 12 teachers is 20%

SPLENDID25:
the percentile placement for the group with 12 teachers is 20%

no no pls

this is not correct

P = 100 x n/N

= 100 x 11/12


= ~92%

NisforNicky:

no no pls
this is not correct
P = 100 x n/N
= 100 x 11/12 = 92.11%

my bad! misunderstood the question

NisforNicky:

no no pls
this is not correct
P = 100 x n/N
= 100 x 11/12 = 92.11%

my bad! misunderstood the question

SPLENDID25:
my bad! misunderstood the question

pls can you find the interquartile range

cc ivumar femi4

in one month, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107


cc ivumar

NisforNicky:
in one month, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107


cc ivumar

Please check again. What is in the option for (D). Is it really 107?

ivumar:

Please check again. What is in the option for (D). Is it really 107?

looks like 112 or 107
pic not clear at all on dat part

NisforNicky:
in one month, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107



cc ivumar

The answer should be A

Tobilyn77:

The answer should be A

Reasons being?

NisforNicky:


looks like 112 or 107

pic not clear at all on dat part

I got 152, so I was confused.
Had to download the image and zoom... and it actually looked like 152.

ivumar:
I got 152, so I was confused. Had to download the image and zoom... and it actually looked like 152.

you are correct
I enhanced d image and the middle one looked like 5 or 8

pls show workings

Tobilyn77:
The answer should be A

show workings pls

NisforNicky:
in one week, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107


cc ivumar

2:30AM - 4:00AM is 1.5 hrs. The athlete did this particular set of run for 6 days, i.e, In that week, he ran 6 x 1.5 hrs = 9 hrs in the morning.

2:00PM - 4.30pm is 2.5 hrs. The athlete did this particular set of run for 4 days, i.e, In that week, he ran 4 x 2.5 hrs = 10 hrs in the evening

Therefore, the total number of hrs the athlete ran that week is 9 + 10 = 19 hrs.
According to the question, average speed is 8km/hr

Now, the question is asking for the total distance traveled in that week in kilometres. So lets solve
Distance = speed x time
therefore, Distance = 8 x 19 = 152km

[quote author=NisforNicky post=94939564]

Sorry. I mixed it up

Tobilyn77:
the athlete ran for 1 hours 30 minutes for 6 days in the morning.
Total hours ran. (6*1.5hours) = 9 hours .
In the evenings. He ran for (1hour 30mins For 4 days.( 4*1.5) = 6 hours.
(9+6) = 15 hours total.
Speed = distance/time.
8km/hr = x/15
X= 15*8
X= 120km.

im confused walahi

oga how does this translate to A. 200 now



modified: oh, i see where the mistake is

the second one should be 2hrs 30mins not 1hr 30mins

good attempt bro
tobilyn77

ivumar:


2:30AM - 4:00AM is 1.5 hrs. The athlete did this particular set of run for 6 days, i.e, In that week, he ran 6 x 1.5 hrs = 9 hrs in the morning.

2:00PM - 4.30pm is 2.5 hrs. The athlete did this particular set of run for 4 days, i.e, In that week, he ran 4 x 2.5 hrs = 10 hrs in the evening

Therefore, the total number of hrs the athlete ran that week is 9 + 10 = 19 hrs.
According to the question, average speed is 8km/hr

Now, the question is asking for the total distance traveled in that week in kilometres. So lets solve
Distance = speed x time
therefore, Distance = 8 x 19 = 152km

ivumar thanx so much

Pls I still need help with the interpercentile sumtin

Don't know what you do in ur personal lyf but u can comfortably take math tutoring gigs

lolz I dn type ur name too much sotey my keyboard don save am dey suggest am up-and-down

NisforNicky:

pls can you find the interquartile range
cc ivumar femi4

2

SPLENDID25:
2

I got 7
pls show workings

Tobilyn77:

it's cool

pls help solve more

NisforNicky:


no no pls

this is not correct

P = 100 x n/N

= 100 x 11/12


= ~92%

Please, how did u get 11?

ennydammy11:


Please, how did u get 11?

list all the data in order from smallest to largest

then look for where 12 is on the row (11th term in this case)

that is the rank/p0sition (n) of 12.

the big N is the total no. of terms

NisforNicky:


I got 7

pls show workings

i used this to calculate mean, and median.

NisforNicky:


ivumar thanx so much

Pls I still need help with the interpercentile sumtin

Don't know what you do in ur personal lyf but u can comfortably take math tutoring gigs

lolz I dn type ur name too much sotey my keyboard don save am dey suggest am up-and-down

Lolzzz... Thanks bro

As regarding the questions on percentile, median, inter-quartile and their likes,,,,, I think the table given is not representing the right information.
Check up SPLENDID25's last message. I think he put forth a reasonable assumption as regarding the table.
The 2nd row should represent the frequency of the values given in the 1st row.. I'm sure(not 100%) it was a mistake from them.

SPLENDID25:
i used this to calculate mean, and median.

Nice...
You assumed the lower row to be that of frequency, right?