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Snepco Past Questions And Answers. / Nnpc/snepco Past Questions / Nnpc/snepco Past Questions (2) (3) (4)
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Re: Snepco Past Questions by SPLENDID25(m): 9:06pm On Oct 14, 2020 |
ivumar:yes Sir 1 Like |
Re: Snepco Past Questions by femi4: 9:31pm On Oct 14, 2020 |
NisforNicky:That table has issue. Not showing frequency row 1 Like |
Re: Snepco Past Questions by NisforNicky: 12:16am On Oct 15, 2020 |
Verbal Cc jpawjpaw thankGod001
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Re: Snepco Past Questions by NisforNicky: 12:19am On Oct 15, 2020 |
Morree
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Re: Snepco Past Questions by jpawjpaw(m): 12:19am On Oct 15, 2020 |
NisforNicky:a man and a woman can do a work for 4 days. x + y = 4 (man = x and woman = y) while the woman alone can do the work for 6 days. y = 6. how long will it take the man to do the work? if x+y = 4 when y = 6 x + 6 = 4 x = 4-6 x = -2 by ignoring the sign, x = 2// so it will take the man 2days to do the work. abeg I stand to be corrected. the question carry weight 1 Like |
Re: Snepco Past Questions by NisforNicky: 12:21am On Oct 15, 2020 |
good night people all the rest are not clear at all good luck everyone
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Re: Snepco Past Questions by NisforNicky: 12:22am On Oct 15, 2020 |
jpawjpaw: hmmmm........ this is what I did too ivumar femi4 pls confirm |
Re: Snepco Past Questions by NisforNicky: 12:25am On Oct 15, 2020 |
jpawjpaw: I think no need to ignore the sign - shows the man will finish the job 2 days less than the 4 days when they did it together |
Re: Snepco Past Questions by Xandre: 1:29am On Oct 15, 2020 |
jpawjpaw:Both of them can do it for 4Days, how then can only the man do it for 2Days? It's 12Days Sha...but not in the options 1 Like |
Re: Snepco Past Questions by femi4: 5:12am On Oct 15, 2020 |
NisforNicky:Can't you see that laugh emoji at the end of his solutions. As you can see, some of the question were either incorrect or answer missing from the options Besides, you can't finish a job working alone in lesser days than the no of days both of them will use to complete same job. 2 Likes |
Re: Snepco Past Questions by ThankGod001(m): 6:06am On Oct 15, 2020 |
nice NisforNicky: |
Re: Snepco Past Questions by ThankGod001(m): 6:08am On Oct 15, 2020 |
SPDC when was that? NisforNicky: |
Re: Snepco Past Questions by Nobody: 6:46am On Oct 15, 2020 |
femi4: Can't you see that laugh emoji at the end of his solutions. Lolll 1 Like |
Re: Snepco Past Questions by Nobody: 6:48am On Oct 15, 2020 |
SPLENDID25:Alright Boss |
Re: Snepco Past Questions by Nobody: 6:49am On Oct 15, 2020 |
NisforNicky: Wrong Sir |
Re: Snepco Past Questions by NisforNicky: 7:56am On Oct 15, 2020 |
ivumar: alright pls A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work? A. 40 days B. 23 days C. 37 ½ days D. 37 days cc femi4 |
Re: Snepco Past Questions by NisforNicky: 7:59am On Oct 15, 2020 |
femi4: A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in A.18 days B.6 days C. 4 days D. 8 days cc ivumar I got 8 |
Re: Snepco Past Questions by femi4: 8:50am On Oct 15, 2020 |
NisforNicky:A does 80% of job in 20 Days. Hence, 100% of job in (100/80) x 20 = 25 Days A alone can complete the job in one day (1/25) portion A and B do 20% of job in 3 Days. Hence, 100% of job in (100/20) x 3 = 15 Days A and B can complete the job in one day (1/15) portion B alone can complete the job in one day [(1/15) - (1/25)] = [(5- 3 )/75] = [2/75] portion B alone can complete the job = (75/2) = 37.5 Days 5 Likes |
Re: Snepco Past Questions by femi4: 9:02am On Oct 15, 2020 |
NisforNicky:4days 2A = B Hence, A = 12/2 = 6days Working together 1/6 + 1/12 = 1/4 of the job/day Hence, the job will be completed in 4days by A and B working together 3 Likes |
Re: Snepco Past Questions by Nobody: 9:34am On Oct 15, 2020 |
femi has given solutions. Hope you understood? 2 Likes |
Re: Snepco Past Questions by NisforNicky: 10:04am On Oct 15, 2020 |
femi4: thanks femi I gt confused by the 80% |
Re: Snepco Past Questions by NisforNicky: 10:05am On Oct 15, 2020 |
femi4: ohhhhh my mistake was doing A=2B thanks again femi4 and ivumar |
Re: Snepco Past Questions by NisforNicky: 10:36am On Oct 15, 2020 |
femi4: 1. A alone can do a piece of work in 10 days and B alone can do it in 15 days. In how many days will A and B together do the same work? (a) 5 (b) 6 (c) 8 (d) 9 2. It takes 6 men 10 days to paint 2 rooms. How long will it take 4 men to paint 6 rooms? A. 42 B. 45 C. 62 D. None of the options cc ivumar femi4 |
Re: Snepco Past Questions by Xandre: 11:22am On Oct 15, 2020 |
NisforNicky:BB Yes to your question on Jim Ovia 1 Like |
Re: Snepco Past Questions by femi4: 12:02pm On Oct 15, 2020 |
NisforNicky:1. 1/15 + 1/10 = 25/150 = 1/6 of the job/day Hence, working together will take them 6days to complete the job 2. 4men will paint 2 rooms in 6*10/4 = 15days Hence, painting of 6 rooms by 4 men = 15*3 =45days 2 Likes |
Re: Snepco Past Questions by NisforNicky: 1:58pm On Oct 15, 2020 |
femi4: thanks a lot |
Re: Snepco Past Questions by NisforNicky: 1:59pm On Oct 15, 2020 |
Xandre:wow since when? |
Re: Snepco Past Questions by NisforNicky: 2:17pm On Oct 15, 2020 |
femi4: 7. Smith and Thomas can do a piece of work in 72 days; Thomas and Clark can do it in 120 days; Smith and Clark can do it in 90 days. In what time can Smith, Thomas and Clark do it, working together? (a) 60 days (b) 66 days (c) 75 days (d) 80 days I got A. 60 |
Re: Snepco Past Questions by NisforNicky: 2:32pm On Oct 15, 2020 |
ThankGod001:last month, I think |
Re: Snepco Past Questions by NisforNicky: 3:11pm On Oct 15, 2020 |
no calculators allowed i jxt confirmed dis from the SNEPCO lady |
Re: Snepco Past Questions by Iamcyborg(f): 4:16pm On Oct 15, 2020 |
NisforNicky: |
Re: Snepco Past Questions by Tobilyn77: 4:17pm On Oct 15, 2020 |
NisforNicky:workings please |
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