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Strictly 4 Mathematicians by Siloko26(m): 10:45pm On Jul 27, 2012 |
Please mathematician in the house help me out with this question. T = 2pie*square root of h^2 + k^2/ gh....make h subject of the formula thanks |
Re: Strictly 4 Mathematicians by Default01: 10:34am On Jul 28, 2012 |
h=2pie k/gt-2pie |
Re: Strictly 4 Mathematicians by mrkels(m): 10:38am On Jul 28, 2012 |
H= (2pie + 2piek)/Tg This ans is based on the equation T=(2pie*squareroot h^2 + k^2)/gh |
Re: Strictly 4 Mathematicians by Siloko26(m): 11:28am On Jul 28, 2012 |
Default01: h=2pie k/gt-2pieu forgot the square root its T = 2pie *(times) the square root of h^2 + k^2 / (over) gh. Expecting more answers and if possible show working Default01: h=2pie k/gt-2pie |
Re: Strictly 4 Mathematicians by Siloko26(m): 11:35am On Jul 28, 2012 |
mrkels: H= (2pie + 2piek)/Tgbros i think u should revise ur ans, try and find T weda u wud get back to the original question, u seems to b ignoring the square roots |
Re: Strictly 4 Mathematicians by travelxpat(m): 6:57pm On Jul 28, 2012 |
A̶̲̥̅♏ not a mathematician but an engineer .going by your equations as long as the squareroot covers the entity and all entity aя̩̥̊ε̲̣̣̣̥ divide by gh. Then d answer I̶̲̥̅̊s̶̲̥̅̊ simply h=± gt^2 square root [g^2•t^4-64pie^2•k^2]\8pie simply used the almighty formula to arrive at d answer, since its a simple quadratic equation |
Re: Strictly 4 Mathematicians by Siloko26(m): 7:08pm On Jul 28, 2012 |
travelxpat: A̶̲̥̅♏ not a mathematician but an engineer .going by your equations as long as the squareroot covers the entity and all entity aя̩̥̊ε̲̣̣̣̥ divide by gh. Then d answer I̶̲̥̅̊s̶̲̥̅̊ simply h=± gt^2 square root [g^2•t^4-64pie^2•k^2]\8pie simply used the almighty formula to arrive at d answer, since its a simple quadratic equationboss thank u very much, i would try it out |
Re: Strictly 4 Mathematicians by travelxpat(m): 7:11pm On Jul 28, 2012 |
U̶̲̥̅̊ r welcome my guy,have a blessed day |
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