lebesgue:
You are most welcome.


What text? If you are referring to the proof, I didn't copy it from a text. I wrote it myself!


No, I am not. I am an undergraduate studying Mathematics, and I intend to be an algebraist.

Chuksemi: Abeg... How do I learn maths? I've been trying but the improvement is not as I expected. Any advice? I really want to become a guru.

erigwe:


thanks master, am very greatful!

lebesgue: ^
No sir I am not familiar with it, but I will check it. In the States, we use so many different texts for analysis, and the most popular one is
The Principles of Mathematical Analysis, by Walter Rudin.

lebesgue:

Part 3 of 3.

Arithmetic: You are d boss, no flattering sir.

Oxide65:





Thanks efficiencie. But the hypothesis only says (Yn) is bounded So we do not know if it converges. About the divergence of (Xn) Sorry I dint specify it diverges to positive infinity. Thanks I'm looking forward to seeing your reply.

benbuks:

this may help



www.nairaland.com/1790583/math-genius-calculations-without-calculator

Oxide65:

So Sorry if I'm bugging you Please. is it possible to send me a soft copy of it? The one I just told u about has no soft copy. If u can I'll send my email add. Sorry to bother u Please. Just that this one I have is so gross.

lebesgue:

I do have a pdf copy, but it is very large, so I can't upload or email it. But here is a pdf link (12.9 MB). Don't click this link on your phone! Right-click on it and choose Save link as.

Note: this book is very dense and hard to read; hence I wouldn't recommend it for a beginner.

Allenkee: Please help me simplify the questions.
i raise to power 7

2) i raise to power 15
The questions are from number system.
Thanks.

Kendzyma: if its d letter representin sqrt(-1)
den (1),,,,,sinc i^2=-1
(i^2)^3 * i=-1*i=i^3
(2)i^15=(i^2)^7 * i=-1*i=i^3

Arithmetic: Question:
Solve:dy/dx+2ytanx=sinx. By 1Book , from Calculus Mental Challenge(CMC).

:::SOLUTION:::.
Integrating both sides,
$(dy/dx+2ytanx)dx=$sinxdx.
$dy/dx.dx+2y$tanxdx=$sinxdx.
$dy+2y(-lncosx)=-cosx+c
NB: y is taken as a constant in $2ytanxdx.
y-2ylncosx=-cosx+c.
y(1-2lncosx)=-cosx+c.
.'.y=(-cosx+c)/(1-2lncosx). Which is the required solution.

benbuks: 18 √x=729 ^(√x-1)
solve..

benbuks: 18 √x=729 ^(√x-1)
solve..

1Book:
Hmmmm...Ur solution is quite wrong! ...
use linear differential equation method.
what was ur integrating Factor?

1Book:
Hmmmm...Ur solution is quite wrong! ...
use linear differential equation method.
what was ur integrating Factor?

benbuks: HERE....

www.nairaland.com/1852522/calculus-mental-challenge-cms-win

benbuks: HERE....

www.nairaland.com/1852522/calculus-mental-challenge-cms-win

Arithmetic: Then explain boss.

efficiencie:

bt if a series y(n) is bounded such that:

if y(i), y(j) ∈y(n) for i,j∈n which are the upper and lower bounds of n=Z, (knowing d@ Z∈(-∞ ∞)) then
y(n)∈(y(i) y(j)) and hence Limy(n)=y(i) as n→i and
Limy(n)=y(j) as n→j

suggesting that a bounded series must have a unique or oscilating limit as in d case of sinusoidal functns.
and a boundless series has no limiting values!

I stand to be correctd tho and i'l get an alternative solutn!!!

Arithmetic: Question:
Solve:dy/dx+2ytanx=sinx. By 1Book , from Calculus Mental Challenge(CMC).

:::SOLUTION:::.
Integrating both sides,
$(dy/dx+2ytanx)dx=$sinxdx.
$dy/dx.dx+2y$tanxdx=$sinxdx.
$dy+2y(-lncosx)=-cosx+c
NB: y is taken as a constant in $2ytanxdx.
y-2ylncosx=-cosx+c.
y(1-2lncosx)=-cosx+c.
.'.y=(-cosx+c)/(1-2lncosx). Which is the required solution.