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Re: Nairaland Mathematics Clinic by dejt4u(m): 4:07pm On Aug 28, 2014 |
Kovic08: Thanks man please can you cross check that number one workings very well.. Buh the rest are perfect kudos to you smurfy.. and please i don't know anything about polygons.please can you teach me. Here in one page thanks.. More questions to come..am learning ( i hope we have physics and chemistry clinic)you can start it bro by opening a thread or 2 to that effect..i will definitely subscribe to it.. Just announce it here and some other threads to pull traffic |
Re: Nairaland Mathematics Clinic by dejt4u(m): 4:14pm On Aug 28, 2014 |
benbuks: manage this(2√(3x2-4x) In(3√x+√(9x-12))/3√(4x-3x2) + constant |
Re: Nairaland Mathematics Clinic by Nobody: 4:29pm On Aug 28, 2014 |
dejt4u: workings will be cool. what thinketh thou ..? 1 Like |
Re: Nairaland Mathematics Clinic by dejt4u(m): 4:34pm On Aug 28, 2014 |
benbuks:kinda long but i go try typin it sha |
Re: Nairaland Mathematics Clinic by sundaylinus: 12:24am On Aug 29, 2014 |
this is where i always gets my maths probs sol. But this one is out of maths. please no insult, Pls any android guru may help me out, my phamtom A+, when i dail a number to make call, the screen just go blank and the call is still going. Pls help to fix it |
Re: Nairaland Mathematics Clinic by mathefaro(m): 6:23am On Aug 29, 2014 |
In addition, for every polygon, the interior angle(i) and the adjacent exterior angle(e) are supplementary. I.e i + e = 180; more so, the size of each angle of a regular polygon is given as i = [(n - 2) x 180] / n. My own little contribution. You guys are doing a wonderful job here. Weldone. smurfy: 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 12:45pm On Aug 29, 2014 |
the ratio of the ages of two brother sola and femi is 3:4 in six years time the ratio of their ages will b 5:6 .how old are they now? |
Re: Nairaland Mathematics Clinic by Nobody: 12:46pm On Aug 29, 2014 |
dejt4u: ok....expecting..... |
Re: Nairaland Mathematics Clinic by Nobody: 12:53pm On Aug 29, 2014 |
benbuks: the ratio of the ages of two brother sola and femi is 3:4 in six years time the ratio of their ages will b 5:6 .how old are they now? Here goes... Let their present ages be x and y respectively. From first sentence, x/y = 3/4 or 4x = 3y or x = 3y/4 eqn (*) From second sentence, (x+6)/(y+6) = 5/6 or 6(x+6) = 5(y+6) Simplifying... 6x + 36 = 5y + 30 6x = 5y - 6 eqn (**) Solving (*) and (**) simultaneously gives x = 9, y = 12 Sola and Femi are 9 and 12 years old respectively. 3 Likes 1 Share |
Re: Nairaland Mathematics Clinic by Nobody: 1:10pm On Aug 29, 2014 |
Find the set of values of k for which ABSVAL[(x - 4)(x + 2)] = k has four solutions. Note: ABSVAL means absolute value. |
Re: Nairaland Mathematics Clinic by dejt4u(m): 1:58pm On Aug 29, 2014 |
smurfy: Find the set of values of k for which ABSVAL[(x - 4)(x + 2)] = k has four solutions. k= -4, 4, -2, 2 |
Re: Nairaland Mathematics Clinic by Nobody: 2:31pm On Aug 29, 2014 |
dejt4u: Nope. Thanks for trying. |
Re: Nairaland Mathematics Clinic by Nobody: 3:43pm On Aug 29, 2014 |
Somebody should please mama this tricky question. Triangle ABC has AC = BC, <ACB = 96 degrees. D is a point in ABC such that <DAB = 18 degrees and <DBA = 30 degrees. What is the measure (in degrees) of <ACD? |
Re: Nairaland Mathematics Clinic by Kovic08(m): 4:20pm On Aug 29, 2014 |
smurfy:you are the best |
Re: Nairaland Mathematics Clinic by Nobody: 4:24pm On Aug 29, 2014 |
Kovic08: you are the best The best? I am the least on this thread. Just keep the hard questions coming. |
Re: Nairaland Mathematics Clinic by Kovic08(m): 4:30pm On Aug 29, 2014 |
smurfy:i just used what you taught me now to solve "thousands" of polygon problems thanks man ..more questions to come |
Re: Nairaland Mathematics Clinic by Nobody: 7:31pm On Aug 29, 2014 |
smurfy: Somebody should please mama this tricky question. <ACD =54° |
Re: Nairaland Mathematics Clinic by Nobody: 7:39pm On Aug 29, 2014 |
benbuks: Workings, please. You could snap the solution if it's on paper. I'm not saying you're correct o. |
Re: Nairaland Mathematics Clinic by Nobody: 7:56pm On Aug 29, 2014 |
smurfy: sorry . <ACD =42° solution loading .
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Re: Nairaland Mathematics Clinic by Nobody: 8:15pm On Aug 29, 2014 |
benbuks: Why did you say <BDC = <ADC since BD is not equal to AD and CD is not a bisector of <ACB? |
Re: Nairaland Mathematics Clinic by Nobody: 8:19pm On Aug 29, 2014 |
Can't someone solve this? smurfy: Find the set of values of k for which ABSVAL[(x - 4)(x + 2)] = k has four solutions. |
Re: Nairaland Mathematics Clinic by Nobody: 8:28pm On Aug 29, 2014 |
smurfy: equal length => equal angle . |
Re: Nairaland Mathematics Clinic by Nobody: 8:40pm On Aug 29, 2014 |
benbuks: AC = BC => angle A = angle B, nothing else. |
Re: Nairaland Mathematics Clinic by Nobody: 9:25pm On Aug 29, 2014 |
smurfy: Can't someone solve this? 0,8,2,4 |
Re: Nairaland Mathematics Clinic by Nobody: 9:36pm On Aug 29, 2014 |
^ 69% sure .. kinda lazy to solve .. nyt nyt .... |
Re: Nairaland Mathematics Clinic by Nobody: 9:53pm On Aug 29, 2014 |
benbuks: The correct answer is 0 < k < 9. It's essential you make a sketch first. Thanks detj4u and benbuks for your efforts.
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Re: Nairaland Mathematics Clinic by Nobody: 10:50am On Aug 30, 2014 |
How many integer values of x simultaneously satisfy the following two inequalities: x + 9 > 2x - 3, x^2 </= 7x + 60? |
Re: Nairaland Mathematics Clinic by mathefaro(m): 11:10am On Aug 30, 2014 |
11, if we want to consider positive integers alone but otherwise, I'm afraid that will be infinity o. I stand to be corrected though. smurfy: How many integer values of x simultaneously satisfy the following two inequalities: |
Re: Nairaland Mathematics Clinic by Nobody: 12:24pm On Aug 30, 2014 |
mathefaro: 11, if we want to consider positive integers alone but otherwise, I'm afraid that will be infinity o. I stand to be corrected though. The question is asking for integral values only. Are you willing to trash it? |
Re: Nairaland Mathematics Clinic by ugonna1054(m): 12:59pm On Aug 30, 2014 |
Some one help me pls.....what is d integral of. 5/x^2.....and prove dat integral of secxtanx=secx.. |
Re: Nairaland Mathematics Clinic by Oxide65: 1:12pm On Aug 30, 2014 |
benbuks: manage this Sire, does this correspond with your result?
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Re: Nairaland Mathematics Clinic by Nobody: 1:23pm On Aug 30, 2014 |
ugonna1054: Some one help me pls.....what is d integral of. 5/x^2.....and prove dat integral of secxtanx=secx.. ok.. $5/x2 dx = $5x-2dx => 5 $x-2 dx = -5x-1 + k = -5/x + k known that integration is the anti. of differentiation sec x = 1/cosx using quotient rule (vu' - uv ' )/v2 put 1= u u'= 0 & cosx =v v'=-sinx say f(x) = secx we thus have f '( x) = [0 -(-sinx) ]/ cos2x => 1/cosx * sinx/cosx hence we have secx.tanx ..................( as expected ) |
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