ladokuntlad:
.

pls boss, i cnt see d answer very well. could u type it instead pls

Hadampson:
pls boss, i cnt see d answer very well. could u type it instead pls

Can't start typing ooo




D solution is r=2 a=5

ladokuntlad:



Can't start typing ooo




D solution is r=2 a=5

pls boss just tell me how u get d quadratic equation when solving for constant ratio.

strictlynaija:
Hello people, someone should help me with how to integrate secx

The first thing you need to do is to obtain the trigonometric identity for sec X. Now sec X=sec X *1=sec x((sec x+tan x) /(sec x +tan x)). At this point you will integrate the simplicities of sec X using the u-substitution which will give you a final result as ln(secx +tanx) +c.

What is the curl of A = y i - z²j + (y - x²)k at the point (1,2,1) ?

Teempakguy:
What is the curl of A = y i - z²j + (y - x²)k at the point (1,2,1) ?

curl A = 3i + 2j - k

Nigayoyo:


curl A = 3i + 2j - k

no working?

Teempakguy:
no working?

curl A = V x A = i [d/dy(y-x^2) + d/dz(z^2)] - j [d/dx(y-x^2)-d/dz(y)] + k [d/dx(-z^2) - d/dy(y)]

= (1+2z)i + (2x)j - k

Evaluating at (1,2,1) yields:

curl A = 3 i + 2 j - k

That was a pain in the a**

Nigayoyo:


curl A = V x A = i [d/dy(y-x^2) + d/dz(z^2)] - j [d/dx(y-x^2)-d/dz(y)] + k [d/dx(-z^2) - d/dy(y)]

= (1+2z)i + (2x)j - k

Evaluating at (1,2,1) yields:

curl A = 3 i + 2 j - k

That was a pain in the a**

haha, sorry about that. I was just trying to compare results.

Ok

Oluwatosint:
help please

I can't see anything.

Richiez:
We diagnose and solve math problems here
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Good Morning pals and also the admin of this great n amiable forum. Please, how can one define n explain logical reasoning in Mathematics? thanks.

Someone should please help me with solutions to these questions.

crouch2014:
Someone should please help me with solutions to these questions.

sorry can't solve it

crouch2014:
Someone should please help me with solutions to these questions.

sorry can't solve it

Good morning all,
Please someone should help me solve this: Express 3x-2<10+x<2+5x in the form a<x<b. Where a and b are both integers.

Please help

nnamdi1998:
Please help

So, the man has 24,000
Then he gave his wife ¼ of 24,000 which is 6,000
Then his two sons 2/3 of 24,000 which is 16,000
So total for wife and sons = 6,000+16,000 = 22,000
Amount remaining = 24,000-22,000 = 2,000
Remainder was divided equally among two daughters = 2,000/2 = 1,000
So amount each daughter received = 1,000
I stand to be corrected if wrong though.

Ifeshyne:
So, the man has 24,000 Then he gave his wife ¼ of 24,000 which is 6,000 Then his two sons 2/3 of 24,000 which is 16,000 So total for wife and sons = 6,000+16,000 = 22,000 Amount remaining = 24,000-22,000 = 2,000 Remainder was divided equally among two daughters = 2,000/2 = 1,000 So amount each daughter received = 1,000 I stand to be corrected if wrong though.

Thanks sir,you're very good

nnamdi1998:
Thanks sir,you're very good

My pleasure.
I'm female though

crouch2014:
Someone should please help me with solutions to these questions.

Q(1). Using Euler formular..

exp(i x)= cosx +i*sinx;

exp(i pi/2)=i;

exp(i(pi/2+2 *pi*k))=i; where k is any positive integer.

i^i=(exp(i(pi/2+2 *pi*k)))^i=exp((pi/2+2 *pi*k)) which is a real number and infinite since k is infinite.

crouch2014:
Someone should please help me with solutions to these questions.

Will solve Q(2) when am less busy.. that is one dimensional wave equation with boundary conditions. D-Alembert formula is a solution of the one dimensional wave equation or u can use separation variable technique.

hadassaheke:
Good morning all,
Please someone should help me solve this: Express 3x-2<10+x<2+5x in the form a<x<b. Where a and b are both integers.

Someone should say something about this please. Thanks!

crouch2014:
Someone should please help me with solutions to these questions.

I remember telling you to apply Duhamel's principle....

Anybody here wants to talk about real/functional analysis,measure theory,topology ring and field theory?....I'm too lazy for the solving kind of math....

hadassaheke:
Good morning all,
Please someone should help me solve this: Express 3x-2<10+x<2+5x in the form a<x<b. Where a and b are both integers.

3x-2<10+x<2+5x
= 3x-2-10<10-10+x<2-10+5x
=3x - 12 < x < -8 + 5x
= 6 < X < 2

Deicide:

3x-2<10+x<2+5x
= 3x-2-10<10-10+x<2-10+5x
=3x - 12 < x < -8 + 5x
= 6 < X < 2

That is problematic. I think you have gotten it the other way round. Cheers!

masperano:


That is problematic. I think you have gotten it the other way round. Cheers!

well you can also solve it separately by picking
1) 3x-2<10+x
2) 10+x<2+5x
then solve then join the inequality later...

Deicide:

well you can also solve it separately by picking
1) 3x-2<10+x
2) 10+x<2+5x
then solve then join the inequality later...

yea I know, I thought you made a slight error since x cannot be greater than 6 (i.e x>6) and at the same time x less than 2( i.e. x<2) you wrote (6 < X < 2). So it should be the other way round... that is 2< x<6. Cheers!