naturalwaves:

Okay. I will try if there is another way of solving it. Do you have another 6th grade maths question from China? . If you do, paste it.

masperano:


lol i will paste one this weekend.

naturalwaves:

okay. Will be looking forward to it.

masperano:


check these ones out... one is quite easy to do.

masperano:


check these ones out... one is quite easy to do.

masperano:



1. 2 students
2. 8 students
3. 30 students
4. 14 students

cheers!

Olive33:
pls show me the solving .. Thanks

naturalwaves:

I just solved the circular one. I got 1008m². I embedded a square in between the shapes and took it out from the big circle along with 4 resultant semi- circles. See solution below. Sorry about the poor image.
PS: Why don't you normally put units in your questions?

masperano:


Yea that is correct. Lol on the units...(u must be an engineer: they are usually obsessed with units), that's how it is in the question: usually dimensionless.

naturalwaves:

A computer scientist actually. I am on my way for a seminar, will solve the second one when I get back. The questions require creativity. One needs to always reconfigure them and see how the shapes can be redrawn or manipulated. I guess this is what is being tested over there and it is good for children to have that kind of skill at that age. I am not really a fan of geometry and mensuration but your questions are making me think. Thanks.

masperano:


Note in question 3 I made a mistake I swapped intersection symbol for union symbol. It is suppose to be N (E n C)+N (E n B)+N(B n C).

masperano:

check these ones out... one is quite easy to do.

Engrcharlesid:

d second one

DBright123:
Great work you guys are doing in here. Please I need assistance with this trigonometry question.

1. Prove Sec square theta -Cosec square theta =1

OR Cosec square theta -Sec square theta =1

2. Prove that Sin square theta +Cos square theta =1


I will appreciate your response great minds

DBright123:


masperano
inschool
et al

DBright123:

masperano inschool et al

DBright123:
Great work you guys are doing in here. Please I need assistance with this trigonometry question.

1. Prove Sec square theta -Cosec square theta =1

OR Cosec square theta -Sec square theta =1

2. Prove that Sin square theta +Cos square theta =1


I will appreciate your response great minds

agentofchange1:
*PUZZLE*

In a company, each worker was given a key labelled either 01 or 02 or 03 or 04 or 05 or 06 or 07 or 08 or 09. Each worker has access to only one office according to his or her key.

*QUESTION:* A newly employed worker with a key labelled 07 was sacked for missing the number of his office and you were employed and was given the same key to go to the office and if you miss the office, you are sacked, what's your office number?

_HINT_

1) A worker with a key labelled 04 has access to Office5

2) A worker with a key labelled 02 has access to Office5

3) A worker with a key labelled 06 has access to Office5

4) A worker with a key labelled 05 has access to Office1

5) A worker with a key labelled 01 has access to Office1

6) A worker with a key labelled 09 has access to Office1

_Only 2% of the earth can decipher this puzzle_

Olaoke16:

Office 1 immediately... Lol

naturalwaves:

okay. Will be looking forward to it.

agentofchange1:


How?

pauljustina:
Algebraic fractions
1.Dsquared-9/Dsquared-7d+12
2.15+2x-Xsquared/Xsquared-25
3.8-2a-Asquared/2Asquared-3a-2
4.(2m-u)squared-(m-2u)squared/5Msquared -5Usquared

inschool:

sorry am just seeing this... is your problem solved?

DBright123:


one of them have been attended to by usernamesucks remaining one, as for the review that is the way the question was given or what do you think is the right question should look like?

(usernamesucks your input is highly acknowledged and appreciated)

Icosahedron:


1. (d² - 9)/(d² - 7d + 12)

For the numerator, rewrite d² - 9 as d² - 3²

factorize d² - 3² using the difference of squares method to get (d-3)(d+3)

For the denominator, we factor d² - 7d + 12 as d² - 4d - 3d + 12.

The method involved in the factorization above is looking for the factors of +12, that when added yields -7(which is -4 and -3)

so from d² - 4d - 3d + 12, we get
d(d- 4) -3(d-4) = (d-3)/(d-4)

so adding our work, we get

(d-3)(d+3)/(d-4)(d-3)

as (d-3) cancels out, we get (d+3)/(d-4) as final answer

2. (15 + 2x - x²)/( x² - 25)

Factoring completely, it is not difficult to see that
15 + 2x -x² = 15 + 5x - 3x - x²
= 5(3 + x) -x(3+x) = (5-x)(3+x)

Similarly, x² - 25 = x² - 5² = (x +5)(x-5)

Hence we have (5-x)(3+x)/(x+5)(x-5)
note that (5-x) = -(x+5)

Hence -(x+3)/(x-5) is our final answr.


3. (8 -2a - a²)/(2a² - 3a -2)

Solution
we proceed as before, we factorize the numerator first.

8 - 2a - a² = 8 - 4a + 2a - a² = 4(2-a) +a(2-a) = (4+a)(2-a)

And

2a² - 3a - 2 = 2a² - 4a + a - 2 = 2a(a-2) +1(a-2) = (2a+1)(a-2)

Combining our work we get.

(4+a)(2-a)/(2a+1)(a-2).

notice that (2-a) = -(a-2), so (a-2) cancels out and we get.

-(a+4)(2a+1) as our final answer.

4. 2m-u)squared-(m-2u)squared/5Msquared -5Usquared

Or
(2m - u)² - (m - 2u)²/(5m² - 5u²)


factoring the numerator, using difference of two squares method, we get,
(2m-u + m - 2u)(2m-u - m-2u) = (3m - 3u)= 3(m-u)(m+u)

for the denominator, we get 5(m²-u²) = 5(m²-u²) = 5(m-u)(m+u)

It is not difficult to see that, adding all these together, (m-u)(m+u) cancels out, hence 3/5 is our final answer.


And I guess that settles it.