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Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by tolulopevoice: 5:28pm On Nov 14, 2019 |
Mathematicians please solution to question 5 |
Re: Nairaland Mathematics Clinic by Martinez39(m): 5:54pm On Nov 14, 2019 |
tolulopevoice: Use the special formula for the difference of two squares. P² - Q² = (P - Q)(P + Q) P½ - Q½ = (P¼ - Q¼)(P¼ + Q¼) Given that M½ = √(M) (P½ - Q½)(√(P) +√(Q) ) = (P½ - Q½)(P½ + Q½) = P - Q |
Re: Nairaland Mathematics Clinic by dejt4u(m): 5:55pm On Nov 14, 2019 |
tolulopevoice: (p¼ - q¼)(p¼ + q¼)(√p + √q) = (p¼ - q¼)(p¼ + q¼)(p½ + q½) = {(p¼)(p¼) + (p¼)(q¼) - (p¼)(q¼) - (q¼)(q¼)}{p½ + q½} = {(p¼)(p¼) - (q¼)(q¼)}{p½ + q½} = {p½ - q½}{p½ + q½} = (p½)(p½) + (p½)(q½) - (p½)(q½) - (q½)(q½) = (p½)(p½) - (q½)(q½) = p - q 2 Likes |
Re: Nairaland Mathematics Clinic by tolulopevoice: 10:05pm On Nov 14, 2019 |
dejt4u:thanks |
Re: Nairaland Mathematics Clinic by tolulopevoice: 10:06pm On Nov 14, 2019 |
tolulopevoice:still waiting for correct solution to this please |
Re: Nairaland Mathematics Clinic by Mrshape: 10:22pm On Nov 14, 2019 |
tolulopevoice:Tell me which of my solution is not correct? |
Re: Nairaland Mathematics Clinic by Mrshape: 10:27pm On Nov 14, 2019 |
tolulopevoice:Tell me which of my solution is not correct? Let me look at the question again |
Re: Nairaland Mathematics Clinic by tolulopevoice: 10:30pm On Nov 14, 2019 |
Mrshape:
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Re: Nairaland Mathematics Clinic by Mrshape: 10:36pm On Nov 14, 2019 |
[quote author=tolulopevoice post=84035124][/quote] Check my previous solution I have attempted it |
Re: Nairaland Mathematics Clinic by tolulopevoice: 9:22pm On Nov 15, 2019 |
Mrshape:the answer at the textbook says the volume is 5030cm³ |
Re: Nairaland Mathematics Clinic by Mrshape: 9:31pm On Nov 15, 2019 |
tolulopevoice:I know what they did, The assume that same is an hemisphere, although they told us but we can see a sphere their |
Re: Nairaland Mathematics Clinic by Mrshape: 9:33pm On Nov 15, 2019 |
tolulopevoice:7/8 πr^3=7/8×22/7×14^3=5028.84~5030cm^3 |
Re: Nairaland Mathematics Clinic by Mrshape: 9:46pm On Nov 15, 2019 |
tolulopevoice:TSA of solid =TSAhemisphere-TSA of outer cross section+ area of two quadrants +area of roof sector TSA of solid=2πr^2-1/8×2πr^2+1/2πr^2 + 7/8×πr^2 TSA of solid =3.125πr^2 =26900cm^2 |
Re: Nairaland Mathematics Clinic by tolulopevoice: 10:46pm On Nov 15, 2019 |
Mrshape:please can you help with proper and clear solutions |
Re: Nairaland Mathematics Clinic by Mrshape: 10:50pm On Nov 15, 2019 |
tolulopevoice:Your problem is that you don't respond quick I am solving this thing using mental work, so their is high chance of error, If you respond quick I will know if you check my solution again, But your response is every 12 hours. |
Re: Nairaland Mathematics Clinic by Mrshape: 10:56pm On Nov 15, 2019 |
tolulopevoice:full shape is a share Volume of a hemisphere is 2/3πr^3 Volume 2/3×22/7×14^3 Volume =5747cm^3 But the portion cut out from it is 45° out of the hemisphere So it will be 45/360 of hemisphere volume Volume cross section =1/8×2/3×22/7×14^3 V CS=718.38 volume of solid=volume of hemisphere-volume of cross section Volume of solid=5747-718.38 Volume of solid =5030cm^3 |
Re: Nairaland Mathematics Clinic by Akanoo1: 6:00pm On Nov 18, 2019 |
In how many ways can the letters of the word OBASANJO be arranged such that the vowels will not be together. Need help on this question please, I promised my cousin to assist. Thank you |
Re: Nairaland Mathematics Clinic by Mrshape: 6:39pm On Nov 18, 2019 |
Akanoo1:Lol promise and fail. Add one million dollars to it and see how we go rush am |
Re: Nairaland Mathematics Clinic by Akanoo1: 7:20pm On Nov 18, 2019 |
Mrshape:I know there's a platform like this before I said that. Kindly help. |
Re: Nairaland Mathematics Clinic by naturalwaves: 9:53pm On Nov 18, 2019 |
Akanoo1: Step 1. You have to find the total number of ways the entire words can be arranged and that is 8!/(2! 2!)- This is because letters O and A are doubled. 8!/(2!2!)= 1680 ways Step 2 You have to find the number of ways the word can be arranged if the vowels must be together. E. G (OAAO) BSNJ. This implies that the vowels are 1 letter and we have 4 other letters which are BSNJ Number of arrangement in this scenerio is 5!= 120 But we also know that each of the vowels can swap positions in this arrangement. Each one can maintain 4 different positions. Thus, the the number of ways of arrangement if the vowels must be together is 120 x 4 =480 ways Finally, the number of ways of arranging the name OBASANJO if the vowels must not be together = Total number of arrangements possible - Total number of arrangements when vowels are together This implies 1680-480 Therefore, answer = 1200 ways I hope this helps? 4 Likes |
Re: Nairaland Mathematics Clinic by Mrshape: 10:03pm On Nov 18, 2019 |
naturalwaves:Nice one Naturalwave |
Re: Nairaland Mathematics Clinic by naturalwaves: 10:10pm On Nov 18, 2019 |
Re: Nairaland Mathematics Clinic by Akanoo1: 4:47am On Nov 19, 2019 |
naturalwaves:Thank you |
Re: Nairaland Mathematics Clinic by naturalwaves: 5:05am On Nov 19, 2019 |
Akanoo1:You're welcome! |
Re: Nairaland Mathematics Clinic by Aybalance: 9:22am On Nov 20, 2019 |
pls help: Two drivers Alison and Kelvin are participating in a drag race.Beginning from a standing start they each proceed with a constant acceleration .kelvin covers the last 1/4 of the distance in 3 secs whereas alison covers the last 1/3 of the distance in 4secs .Who wins and by how much time? |
Re: Nairaland Mathematics Clinic by naturalwaves: 7:51pm On Nov 21, 2019 |
Aybalance:Will try this when I get back. |
Re: Nairaland Mathematics Clinic by Martinez39(m): 10:06pm On Nov 21, 2019 |
Aybalance:Kelvin wins by approximately 0.59435 sec. |
Re: Nairaland Mathematics Clinic by Martinez39(m): 10:38pm On Nov 21, 2019 |
@Aybalance, the solution requires a very basic knowledge of calculus and motion. KELVIN'S CASE dv/dx = a (constant acceleration). By integration, v = at ———(1) (since v = 0 when t = 0) Finding the definite integral of (1) from to - 3 to to (last 3 seconds) with respect to t to get the distance of move in the last 3 seconds ie. a quarter of the total distance ¼So . Doing this and solving for So will lead to So = 12ato - 18a ——(2) to is the time at which Kelvin crosses the finish line. If we had integrated (1) and substituted to into the resulting distance function, we would have gotten So = ½ato² ———(3) Solving for a in (3) and substituting (2) leads to to² - 24to + 36 = 0 Solving this quadratic equation will yield to ≈ 22.392304 sec The other solution is less than 3 but we discard it since Kelvin's journey took more than 3 sec. ALISON'S CASE Your basically follow the same mathematical procedure in Kelvin's case. The difference is that you integrate from to - 4 to to (last 3 seconds), where to is the time at which Alison crossed the finish line. After everything, you will obtain the quadratic equation to² - 24to + 48 = 0 The solution is to ≈ 21.797959 We discard the other solution because it is less that 4 seconds and we know that Alison's journey took more than 4 seconds. Kelvin wins by approximately 0.59435 sec. 3 Likes |
Re: Nairaland Mathematics Clinic by Aybalance: 6:20pm On Nov 26, 2019 |
Thanks man....I saw the question under the topic differential equations ....but seems ur approach also works!!! 1 Like |
Re: Nairaland Mathematics Clinic by Martinez39(m): 7:10pm On Nov 26, 2019 |
Aybalance:Solving differential equations involves integration. I used integration. Did my answer accord with that given in your textbook? |
Re: Nairaland Mathematics Clinic by Brunicekid(m): 7:54pm On Nov 26, 2019 |
Billyonaire369:OK...Solution to this is on its way. |
Re: Nairaland Mathematics Clinic by Aybalance: 11:44am On Nov 28, 2019 |
Martinez39:Sure it does!!!approximately 0.594 secs |
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