Where are the mathematical doctors?, It seems like we got limited diseases to treat,wow, that's great..we hope for a healthy mathematical thread...we need more female doctors.

Alpha Maximus: Alright I'm gonna post a question and no matter how simple it appears just try to solve it! I'm not joking here. As far as it isn't x+1=2, that counts right?
Question: As they say, beggars can't be choosers. A beggar is able to make one cigarette out of every six cigarette butts he finds. After a day of perusing and ransacking public ashtrays, he finds a total of 72 cigarette butts. How many cigarettes can the beggar make and smoke from the butts he found?
P.S: even if you think this is still a joke, at least you know the solution won't take time, chacha!!

He can make 12 cigerates but it wasn't mentioned if he(the begger) smokes.

....d sum of d digits of a 2-digit number is 12, find d number if d produt of its digits must be a maximum...

...d sum of d digits of a 2-digit number is nine...find d number if it must b a maximum...

doubleDx:

It's crazy really, I'm still on it....will post mine today or tomorrow! Sorry to y'all for what happened between Alpha & I! 1luv

*feels so happy*
Alright dear.

I dey expect your solution ooo

**rolls my mat on the floor of the thread and lies down on it, and with phone in my hand, refreshing the page**

[quote author=Alpha Maximus]Alright I'm gonna post a question and no matter how simple it appears just try to solve it! I'm not joking here. As far as it isn't x+1=2, that counts right?
Question: As they say, beggars can't be choosers. A beggar is able to make one cigarette out of every six cigarette butts he finds. After a day of perusing and ransacking public ashtrays, he finds a total of 72 cigarette butts. How many cigarettes can the beggar make and smoke from the butts he found?[\quote]12 it is

Laplacian: ...d sum of d digits of a 2-digit number is nine...find d number if it must b a maximum...

The number is 10x+y

The problem is
maximize F(x,y)= 10x+y
subject to x+y=9
10>x,y > 0 integers
you may use Lagrange multiplier method.

solve and you'll get x=5 or 4, y=4 or 5. Thus, the number is 54 or 45. Sorry, I am quite busy.

Laplacian: ....d sum of d digits of a 2-digit number is 12, find d number if d produt of its digits must be a maximum...

The number too is 10x+y

the problem is
Maximize F(x,y)=xy
subject to x+y=12
0<=x,y<10.

You may use the Lagrange multiplier method to solve.

carefully solving it yields x=6, y=6.

Thus, the number is 66.

Alpha Maximus: Alright I'm gonna post a question and no matter how simple it appears just try to solve it! I'm not joking here. As far as it isn't x+1=2, that counts right?
Question: As they say, beggars can't be choosers. A beggar is able to make one cigarette out of every six cigarette butts he finds. After a day of perusing and ransacking public ashtrays, he finds a total of 72 cigarette butts. How many cigarettes can the beggar make and smoke from the butts he found?
P.S: even if you think this is still a joke, at least you know the solution won't take time, chacha!!

Make 12 and smoke 6,Am I wrong or right?

jackpot: The number too is 10x+y

the problem is
Maximize F(x,y)=xy
subject to x+y=12
0<=x,y<10.

You may use the Lagrange multiplier method to solve.

carefully solving it yields x=6, y=6.

Thus, the number is 66.

correct....ur workin plz...

jackpot:

The number is 10x+y

The problem is
maximize F(x,y)= 10x+y
subject to x+y=9
10>x,y > 0 integers
you may use Lagrange multiplier method.

solve and you'll get x=5 or 4, y=4 or 5. Thus, the number is 54 or 45. Sorry, I am quite busy.

...workin plz...

Alpha Maximus: ....*brings out intecontinental ballistic missile of WRONG and blasts lanrexlan!!!*.....the no he can make is the same no he can smoke!!! Its not 12 though!! Appreciated attempt!! Any of our self-acclaimed generals wanna try out the 'simple' question before I finally post the solution? *alantas spiritually back to amala*

....wat's ur motive 4 bringin dis questn up?...promote knowledge or demote ppl?...anybody can post a hundred such questions dat u too cannot answer?...

...@Math*Generals...any solution 2 Rhydex247's questns?....@Jackpot...ur solution is pretty...our differencies came essentially from our methods of obtainin Ux,Vx..etc...evri other thing are same...

.

Alpha Maximus: ....*brings out intecontinental ballistic missile of WRONG and blasts lanrexlan!!!*.....the no he can make is the same no he can smoke!!! Its not 12 though!! Appreciated attempt!! Any of our self-acclaimed generals wanna try out the 'simple' question before I finally post the solution? *alantas spiritually back to amala*

**dodges the missile **Nice question and thanks for the answer,waiting for more.

Alpha Maximus: I was not looking for any rank o! And you modified it AFTER I posted d solution......about that log 'mistake' , I'm not the first to solve in that way....and its not a riddle seeing as it has an analytical solution which I produced....and why would I look for consolation here, when I already have my A1 in math WAEC and prizes for academic excellence(money included)...

gud 4 u

Laplacian: ...@Math*Generals...any solution 2 Rhydex247's questns?....@Jackpot...ur solution is pretty...our differencies came essentially from our methods of obtainin Ux,Vx..etc...evri other thing are same...

pretty or sexy?

As for me, the solution is kinda sexy

i must confess, I equally learnt one or two things from the way you began your solution. It is refreshing to note that even though my first step is 100% different from yours, our first partial derivatives (and ultimately), our result essentially remains the same.

Laplacian: ...pls Maths Generals i'm so curious 2 knw d relation connectn d derivative Ux and inverse derivative Xu of a PDE...help pls!!!!!!

Given that x,y,z depends on three variables, viz,
x=x(u,v,w), y=y(u,v,w), z=z(u,v,w),
we know that the three transformed equations
u=u(x,y,z), v=v(x,y,z), w=w(x,y,z) is non-degenerate if the Jacobian of the transformation doesn't vanish.

Now, consider the equation
x=x(u,v,w).
Differentiating both sides partially w.r.t. x, we have
1=Xu Ux+ Xv Vx+ Xw Wx

so, the relationship is

Xu*Ux=1-(Xv Vx + Xw Wx)

As a corollary to the above.

Assume that x depends on one variable u, viz,
x=x(u).
Differentiating both sides w.r.t. X, we have
1= Xu* Ux
therefore, Ux=1/(Xu).

This is the same as writing du/dx= 1/ (dx/du),
which is the normal relationship between the two, in single variable calculus.

jackpot:

Given that x,y,z depends on three variables, viz,
x=x(u,v,w), y=y(u,v,w), z=z(u,v,w),
we know that the three transformed equations
u=u(x,y,z), v=v(x,y,z), w=w(x,y,z) is non-degenerate if the Jacobian of the transformation doesn't vanish.

Now, consider the equation
x=x(u,v,w).
Differentiating both sides partially w.r.t. x, we have
1=Xu Ux+ Xv Vx+ Xw Wx

so, the relationship is

Xu*Ux=1-(Xv Vx + Xw Wx)

tanks...our only 'female Fermat'

Laplacian:
tanks...our only 'female Fermat'

.dis1 na even isaac newton o...calculus full dis girl head die....

@miss jackport,i saw your solution yearsterday, i think its infinestesimally void of anomalies, my dear, with the breakthrough of this magnitude,am supremely confident .you could be another katherine okikiolu. Or Grace alele, even better.,i must confess, u r a challenge 2dis thread,just be focus and dnt allow all doz boys decieve u,(i really amire smart ladies..esp in science/mathematics) kudus to u once more....please teach us more...