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Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 3:43pm On Nov 11, 2013 |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 3:52pm On Nov 11, 2013 |
1 Like |
Re: Nairaland Mathematics Clinic by Richiez(m): 3:58pm On Nov 11, 2013 |
Alpha Maximus: Alright I guess this quiz can't end that quickly, with hope, it should even protrude into the night , like OBJ's stomach. Since I can't wait for my battery to DEAD(sorry , na Patience fault), I'll be back with 10 medium questions to serve as an appetizer!!the first round of the quiz will be starting by 10am 2mao so start getting your questions and answers ready as a potential quiz master. you'd be briefed on what next to do very soon 1 Like |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:07pm On Nov 11, 2013 |
2 Likes |
Re: Nairaland Mathematics Clinic by Richiez(m): 4:08pm On Nov 11, 2013 |
Alpha Maximus: When exactly is this quiz meant to commence 'cause its way past 3.00 Prime Meridian already(forgive my EFFIZY ). I don't want this battery to fail me yet, already below half!! * rushes to hospital with phone in hand*No rushing bro! we are still on the stage of selecting quiz masters! the whole competition will run from Monday to Friday because different rounds will be involved. will send all selected quiz masters a briefing soon |
Re: Nairaland Mathematics Clinic by Aliciakeys(f): 4:26pm On Nov 11, 2013 |
INTERESTED... |
Re: Nairaland Mathematics Clinic by dcitizen1: 4:28pm On Nov 11, 2013 |
d citizen: "I am interested" 1 Like |
Re: Nairaland Mathematics Clinic by dcitizen1: 4:37pm On Nov 11, 2013 |
@richiez, I would like to make some recomendations with regards to the quiz competition 1. The levels of the participants should be clearly stated especially, jambite, undergraduate, postgraduate or is the competition opens to all and sundry 2. the questions should be objective based with 4 options, a, b, c and d 3. The questions sets should be adaptive for the potential participants. I mean the question to be set should be graded according to the level of difficulties especially, easy, medium and hard case questions (based on steps, reasoning and math areas) 4. If it is objective based question, negative marking should be strictly applied. That is actual mark = correct - incorrect/4. 5. Rewards should be given to the participant with decorated hall of fame to inspire young and aspiring mathematicians or otherwise. 6. Areas of the mathematics to be cover by the participants need to be made know to encourage speed, accuracy, organisation and preparation. The strcuture and organisation must be matured, sound and solid to encourage more participants in the nearest future. U never can tell how far the kinds of quiz can go. Msg from the five star general in the house. 1 Like |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:57pm On Nov 11, 2013 |
Re: Nairaland Mathematics Clinic by Nobody: 5:00pm On Nov 11, 2013 |
d citizen:'just said my mind'... |
Re: Nairaland Mathematics Clinic by Nobody: 5:08pm On Nov 11, 2013 |
I will be following for now, |
Re: Nairaland Mathematics Clinic by dcitizen1: 5:32pm On Nov 11, 2013 |
Five star general approah to 1^x+2^x+3^x=6^x (6-5)^x+(6-4)^x+(6-3)^x=6^x (6^x(1-5/6)^x)+(6^x(1-4/6)^x)+(6^x(1-3/6)^x)=6^x 6^x((1-5/6)^x)+(1-4/6)^x+(1-3/6)^x)=6^x 1-5/6x+1-4/6x+1-3/6x=1 3-12/6x=1 2x=3-1 2x=2 X=2/2=1 N.b use the principle of linear approximation((1+x)^n approximately equal to 1+nx) becos x is small enough to ignore the values of x^2, x^3, etc 3 Likes |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 7:09pm On Nov 11, 2013 |
Re: Nairaland Mathematics Clinic by Ortarico(m): 8:54pm On Nov 11, 2013 |
jackpot: hmmm, nice one from you Aunt. A similar stuff asked by a friend of mine: 'Peter climbs a mountain 500m high. Each day he climbs 200m but because he is clumsy and drops things, he goes down 100m the next day. In how many days will he get to the top of the mountain? Not needing its solution anyway. |
Re: Nairaland Mathematics Clinic by Ortarico(m): 8:57pm On Nov 11, 2013 |
Wow, it's Innovative! Can we still recommend? I recommend; 'calculusf(x). 1 Like |
Re: Nairaland Mathematics Clinic by Calculusfx: 12:04am On Nov 12, 2013 |
I'm sorry.i have not been typing for quite a long time,it's just that someone whose life i cherish than mine is sick,so i don't have much time nowadays,i'm very sorry....thanx to master ortarico for remembering calculusf(x) on nairaland maths clinic...and i also greet all generals in the house starting from master richiez,double dx,and my greatest oga here who's the five star maths general(i think everybody knows him with that) master d citizen(who's the only general in the same field with me here),master 2nioshine,master jackpot...and my other generals,starting from master laplace,master alpha maximus,my brother who's also my master(ridex),master labodinho and my great pals who are my masters....benbuks and ortarico....I RESPECT YOU ALL...let's keep the thread rolling... 2 Likes |
Re: Nairaland Mathematics Clinic by Calculusfx: 12:06am On Nov 12, 2013 |
Ortarico: Wow, it's Innovative!hmmmm |
Re: Nairaland Mathematics Clinic by Calculusfx: 12:10am On Nov 12, 2013 |
d citizen:...we are thinking the same master |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 12:17am On Nov 12, 2013 |
Re: Nairaland Mathematics Clinic by dcitizen1: 12:29am On Nov 12, 2013 |
@calculus It is a good thing dat u are back. I wish ur loved one a speedy recovery. Keep the math clinic running with ur great and incisive contribution. Take heart and get urself together again |
Re: Nairaland Mathematics Clinic by Calculusfx: 12:41am On Nov 12, 2013 |
[quote author=Alpha Maximus][/quote]@olarewaju's question on the expansion of (a+b+c)(a+b-c)(a-b+c)(-a+b+c)...re-arrange to give (a+b+c)(a+b-c){c+(a-b)}{c-(a-b)}...check the ones that formes difference of two squares there...then {(a+b)^2-c^2}{c^2-(a-b)^2}...expand to give {a^2+b^2+2ab-c^2}{c^2-(a^2+b^2-2ab}...then,{a^2+b^2+2ab-c^2}{c^2-a^2-b^2+2ab}...when you multiply by -1 and you make it affect the second bracket{a^2+b^2+2ab-c^2}{-c^2+a^2+b^2-2ab}...re-arrange to give {a^2+b^2+2ab-c^2}{a^2+b^2-2ab-c^2}...{a^2+b^2-c^2+2ab}{a^2+b^2-c^2-2ab}...which is another difference of two squares...{[a^2+b^2-c^2]^2-[2ab]^2}...then expand the last to give a^4+b^4+c^4-2a^2b^2-2a^2c^2-2b^2c^2 |
Re: Nairaland Mathematics Clinic by Calculusfx: 12:44am On Nov 12, 2013 |
Hmmmm |
Re: Nairaland Mathematics Clinic by Calculusfx: 12:47am On Nov 12, 2013 |
Alpha Maximus: @Calculusf(x) , I've seen , studied and learnt from your work here on this thread and you have proven your worth and skill with numbers time and time again with unique approaches and also that your characteristic humility.Godspeed to your ill acquaintance though and I wish him/her a speedy recovery..thank you my brother,i respect you mathematical approaches to question,you are great bro.and try to be greater d citizen:...thank you very much my master,i'm very grateful. |
Re: Nairaland Mathematics Clinic by Nobody: 11:43am On Nov 12, 2013 |
Factorise x^4 +x^2b^2 +b^4 |
Re: Nairaland Mathematics Clinic by Richiez(m): 11:44am On Nov 12, 2013 |
d citizen: NOTED! |
Re: Nairaland Mathematics Clinic by Richiez(m): 11:45am On Nov 12, 2013 |
The Nairaland math quiz round1 has commenced! Click Here to participate |
Re: Nairaland Mathematics Clinic by rhydex247(m): 11:52am On Nov 12, 2013 |
@ Olarewaju questn on d expansion of (a+b+c)(a+b-c)(a-b+c)(-a+b+c). Here is anoda approach. expansn of (a+b+c)(a+b-c)=a^2+b^2-c^2+2ab. For d expansn of (a-b+c)(-a+b+c)=-a^2-b^2+c^2+2ab. nw we av (a^2+b^2-c^2+2ab)(-a^2-b^2+c^2+2ab) by expansn we av -a^4-b^4-c^4+2a^2b^2+2a^2c^2+2b^2c^2. Multiplyin thru by -1 we av a^4+b^4^c^4-2a^2b^2-2a^2c^2-2b^2c^2. All is well. |
Re: Nairaland Mathematics Clinic by rhydex247(m): 12:08pm On Nov 12, 2013 |
rhydex 247:i'm interested |
Re: Nairaland Mathematics Clinic by factorial1(m): 12:34pm On Nov 12, 2013 |
Wow! It's really great to be here...just notice this thread today...I'm now part of you...keep the ball rolling, will be contributing too, Kudos! |
Re: Nairaland Mathematics Clinic by rhydex247(m): 12:58pm On Nov 12, 2013 |
benbuks: Factorise x^4 +x^2b^2 +b^4(b^2-bx+x^2)(b^2+bx+x^2). |
Re: Nairaland Mathematics Clinic by dcitizen1: 1:00pm On Nov 12, 2013 |
@benbuck X^4+x^2b^2+b^4 (x^4+b^4)+(x^2b^2) ((x^2)^2+(b^2)^2)+(xb)^2 ((x^2+b^2)^2-2(xb)^2)+(xb)^2 (x^2+b^2)^2-(xb)^2 (x^2+b^2-xb)(x^2+b^2+xb) Or((x+b)^2-3xb)((x+b)^2-xb) 1 Like |
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