Welcome, Guest: Register On Nairaland / LOGIN! / Trending / Recent / NewStats: 3,199,099 members, 7,970,350 topics. Date: Wednesday, 09 October 2024 at 07:29 AM |
Nairaland Forum / Nairaland / General / Education / Math Gurus Help Solve This (461 Views)
A Question For Math Gurus / Solve This Question Math Gurus: Differential Equation / Ufot Ekong Solves 30-Year-Old Math Equation In Japan And Breaks Academic Record (2) (3) (4)
Math Gurus Help Solve This by badmus45: 4:31am On Jan 05, 2015 |
the parametric equations of a curve are x=cos@ ,y=1+sin2@.find dy/dx and d2y/dx2 at @=π/6.find also the equation of the curve as relationship between x and y. |
Re: Math Gurus Help Solve This by Nobody: 8:54am On Jan 05, 2015 |
dx/d@ = -sin@ dy/d@ = 2cos2@ d@/dx = -1/sin@ dy/dx = dy/d@ x d@/dx = -2cos2@/sin@ 1 Like |
Re: Math Gurus Help Solve This by Nobody: 9:02am On Jan 05, 2015 |
dy/dx can also be written as 2(1- 2x2)/√(1-x2) d2y/dx2 = {2.-4x.√(1-x2) + 2.(1-2x2).0.5.(1-x2)-1/2.2x}/(1-x2) = 2x(2x2-3)/(1-x2)3/2 y = 1+sin2@ =1+2cos@√(1-cos2@) =1+2x√(1-x2) |
Re: Math Gurus Help Solve This by Nobody: 10:22am On Jan 05, 2015 |
Alternatively to get d2y/dx2 d2y/dx2 = d/dx{dy/d@ x d@/dx} = d@/dx x d/d@{dy/d@ x d@/dx} =-1/sin@ x d/d@{-2cos2@/sin@} = - {2cos2@cos@ + 4sin@sin2@}/sin3x = (4cos3@ - 6cos@)/sin3x =2x(2x2 - 3)/(1-x2)3/2 |
(1) (Reply)
Universities That Considers 2nd Choices Through Direct Entry / The Complete Beginner’s Guide To CFA Examination / UK ADMISSIONS Now Open
(Go Up)
Sections: politics (1) business autos (1) jobs (1) career education (1) romance computers phones travel sports fashion health religion celebs tv-movies music-radio literature webmasters programming techmarket Links: (1) (2) (3) (4) (5) (6) (7) (8) (9) (10) Nairaland - Copyright © 2005 - 2024 Oluwaseun Osewa. All rights reserved. See How To Advertise. 7 |