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See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 6:29pm On Apr 26, 2016 |
http://familyesperience..com/2016/04/an-alternative-method-of-deriving.html we need to encourage our youths who wish to contribute to the academic world. look at how this igbo guy proved Almighty Formula in a different way. 2 Shares
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Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by Nobody: 6:35pm On Apr 26, 2016 |
. 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by amiskurie(m): 7:01pm On Apr 26, 2016 |
What are we suppose to do with ur picture,where are your derivation? 9 Likes |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 7:05pm On Apr 26, 2016 |
amiskurie: brother Nawaooo!!!! u no c the link above? check the link first b4 complaining. or are u jealous about the guys breakthrough? |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by buharisbae(f): 8:05pm On Apr 26, 2016 |
must u include anambra? yeebos and inferiority like bread n butter 5 Likes |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by prinsam30: 10:11pm On Apr 26, 2016 |
u still have to share it with us here on nairaland so we can deliberate on it |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by Nobody: 10:17pm On Apr 26, 2016 |
So ?? 2 Likes
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Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by BlackHummer(m): 11:00pm On Apr 26, 2016 |
OP, your mathematical proving is NOT different from completing the square. All those differentiation you were doing are redundant and unnecessary complications. It is simply a circumlocution for completing the square, or still, a distractor. If you compare your procedure properly with that of the conventional completing the square, the only difference is your inclusion of x(x+b/a) to both sides of the equation which is more time consuming and waste of real estate. I mean, look at equation 5. Rearrange it and compare and contrast against completing the square then you'll be able to filter out the complications that made your 'novel' procedure look as though it was different from completing the square. Btw, equation 1 and 3 might have some issues you might want to check. But I like people who like maths 8 Likes 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by ademasta(m): 12:09am On Apr 27, 2016 |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by yunglivochi(m): 2:08am On Apr 27, 2016 |
so wu dis thread eep |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 4:56am On Apr 27, 2016 |
BlackHummer: OK ,lets do this little comparison. * while you complete a square so as to have a perfect square trinomial at the LHS, which after factoring yields the binomial (X+ b/2a)^2, I differentiate a monic quadratic equation whose square - half automatically yields a binomial (X +b/2a)^2 which is then added to the both sides of the monic quadratic for expansion, so as to cancel like terms. so, while you factorize for completing the square principle, I expand in this method, and this is the major reason for their difference. Also,the application of first order derivative contributes to its difference. if you believe so,the you would believe that factoring by grouping method and box method are the same. but they are not. see, in method,once one or two steps alter,the methods are not the same again, rather similar just like the case of Gaussian and Gauss-Jordan rule for linear systems. As of the equations, 1 and 3, I have corrected them. Thanks anyway. 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 4:59am On Apr 27, 2016 |
yunglivochi: it helps mathematical - minded people because, they will be happy 1 Like |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by Oyiboman69: 8:28am On Apr 27, 2016 |
op I can't see what we are discussing or is it audio,you know I definitely don't like.... you know wara mean... |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by en0uwem: 9:20am On Apr 27, 2016 |
Pls, I need just 200 "likes" on Facebook to win a competition. And I know that you can help me to achieve that by clicking on this link: https://m.facebook.com/story.php?story_fbid=1019111638159235&id=100001812256041 1 Like |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 9:29am On Apr 27, 2016 |
Oyiboman69: Ahh! Brother, u are too quick to conclude. Open the link above before complaining. That is what others do before writing comments. "I definitely don't like......", said by you. That I don't understand. Na u know wetin u mean |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 9:31am On Apr 27, 2016 |
en0uwem: OK I shall do mine |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by lazyList: 9:57am On Apr 27, 2016 |
SlimShaddy10:Bro, what u just did was simply trying to show us how efficient completing the square method is... Don't think u can win an award with that.... I like ur instincts though. 1 Like 2 Shares |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by BlackHummer(m): 10:17am On Apr 27, 2016 |
SlimShaddy10:Bro, what u did is still completing the square. Aside this, there are tons of issues I could raise from your opening statement to the end. I just don't feel it is needful though. But if you love maths this much and you keep pushing further, you'll hit something big by God's grace 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by yunglivochi(m): 10:35am On Apr 27, 2016 |
SlimShaddy10: SlimShaddy10: 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by hausadreturn(m): 12:23pm On Apr 27, 2016 |
buharisbae:are u sure u're not the one with the inferiority complex? If not, why the worry? 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 12:48pm On Apr 27, 2016 |
BlackHummer: U still don't get it brother. See, the method of completing a square has the name because, after taking C/a to the RHS Then we form a perfect square trinomial at the LHS which when factorized gives a perfect square binomial. It is for this reason that the method got the name,'completing the square'. But this method did not do anything like trying to form any perfect square so as to get a perfect square binomial rather, the method uses derivative to get directly the perfect square binomial which is expanded. On this note, the method is different from method of completing the square. Hope you construe my meaning |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by BlackHummer(m): 1:28pm On Apr 27, 2016 |
SlimShaddy10: Na wah oh. You still want us to keep going backwards and forward again and again. This is completing the square: Xsq + bx/a = -c/a Add to both sides the square of half the coeff of x Xsq + bx/a + (b/2a)sq = -c/a + (b/2a)sq Factorise (X+b/2a)sq = -c/a + (b/2a)sq...this is completing the square....eqn(a) you are using the first derivative of the equation to complete the square! .... .... From equation 5 in your model, Xsq + bx/a + c/a +(x+b/2a)sq = (x +b/2a)sq ....this is still attempting to complete the square! You now rearranged to have: (X+b/2a)sq = (x+b/2a)sq - (xsq + bx/a + c/a) You now expanded: (X+b/2a)sq = xsq + bx/a + (b/2a)sq - xsq - bx/a - c/a You now simplified: (X+b/2a)sq = (b/2a)sq - c/a.....eqn (b) How is eqn (a) different from (b) aside from being less complicated? All you just did is to complicate the procedure for completing the square. Bros, trust me when I say this is nothing but beating about the bush. It won't hold water. 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 3:57pm On Apr 27, 2016 |
BlackHummer: given aX^2 + bX + C = 0 X^2 + ( b/a)X = -c/a Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation. so my guy, do u see where the name came from? the reason of completing this square is to have a quadratic equation at the LHS which would yield us the same factors ( X+b/2a)(X+b/2a) after factoring, noting that the product is (X+b/2a)^2 so, the process of getting to this point is to form a perfect square trinomial and nothing else brother ahh! just simple thing to understand. no need to argue. but I did not form any perfect square so as to get the same binomial (X+b/2a)^2. well, I don't wish to argue with you again. believe me or don't. I know what I did. if you doubt me,then take this to some one who is good in maths to check it's difference. |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by BlackHummer(m): 4:09pm On Apr 27, 2016 |
SlimShaddy10: Ok |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 4:20pm On Apr 27, 2016 |
hausadreturn: Ask me ooo ooooo.!!!!! |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by Obas101(m): 9:13pm On Apr 27, 2016 |
SlimShaddy10: So na even you... He you just wan showcase ursef smh |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 10:42pm On Apr 27, 2016 |
[quote author=Obas101 post=45102908] So na even you... He you just wan showcase guy make your self what u wanna be . no hard feelings |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by kennyjodeci(m): 4:57am On Apr 28, 2016 |
I just hate maths especially when they ask us to find X 1 Like 1 Share |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 10:54am On Apr 29, 2016 |
Obas101: Are you jealous? if you are, good for u. |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by Obas101(m): 3:17pm On Apr 29, 2016 |
SlimShaddy10: It's no big deal, i should be the telling good for you |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by SlimShaddy10(m): 3:35pm On Apr 29, 2016 |
Obas101: well, I am not the one who brought the method. it was my cousin. But I am good in mathematics also. So,b4 blogging this, I have read it over and over, and have even studied it together with a professor of maths who encouraged him (my cousin) to write it as a project for publication. So, my cousin is the one who did that, and is the one in the pix. no hard feelings |
Re: See The Pictures Of The Anambra Guy Who Derived Almight Formula Differently. by agentofchange1(m): 6:22pm On Apr 29, 2016 |
amiskurie: content of the link .. The solutions of a quadratic equation are given by two methods among which are : factoring method and quadratic formula. But quadratic formula (a.k.a, Almighty formula) as opposed to the factoring method, works in every quadratic equation so far as the discriminant is non negative. Many alternative Derivations of the quadratic formula have been given in different texts. In this write-up, I shall show a distinct means of deriving the Almighty formula . See the nature of the quadratic formula in equation 1.0. X = -b ± sqrt( b^2 - 4ac) / 2a...........1.0 At this point, instead of using the completing the square principle for the proof, I proof it this way. Given a general quadratic equation of the form aX^2 + bX + C = 0, where X is an unknown, while a,b,and c are known numbers such that a is not zero. Let this quadratic equation be the first equation, i.e, aX^2 + bX + C = 0................1 Form a monic quadratic equation by multiplying equation one by 1 / a. This yields the second equation i.e, X^2 + (b/a)X + C / a = 0............2 Let F(X) = X^2 + (b/a)X + c/a = 0 Differentiate to have F'(X) = 2X + (b/a) Dividing the derivative by 2 and squaring the result gives (F'(X)/2)^2 = ( X + b/2a)^2 Now add this square -half of the derivative to the both sides of equation two. Doing this we have, X^2+(b/a)X+c/a + ( F'(X)/2)^2 = (F'(X)/2)^2...............3 But (F'(X)/2)^2 =( X + b/2a)^2 We then substitute to have X^2 + (b/a)X + c/a + (X+b/2a)^2 = (X +b/2a)^2................4 Isolating the LHS binomial we have ( X + b/2a ) ^2 = ( X+b/2a )^2 - ( X^2 + b/aX + c/a)......5 Expanding the RHS binomial we have ( X + b/2a )^2 = X^2 + b/aX + b^2 / 4a^2 - ( X^2 + b/aX + c/a) .......6 We cancel out like terms to have ( X + b/2a) ^2 = b^2 / 4a^2 - c/a............7 We take the LCM at the RHS to have, ( X + b/2a )^2 = b^2 - 4ac / 4a^2.............8 Take the square root of both sides to have, X + b/2a = ±sqrt(b^2 - 4ac) / 2a.............9 Isolate X to have X = - b/2a ± sqrt( b^2 - 4ac) / 2a..............10 We take the LCM of the RHS to have X = - b ± sqrt( b^2 - 4ac ) / 2a..............11 Q.E.D By The unique nature of this method is that, it saves us the stress of trying to complete a square which would have led to factoring the perfect square. Here, we only expand so as to eliminate like terms. Note : This write - up was made by Makasi Chinedu on the 26 day of April 2016. 1 Like 1 Share |
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