​If Bournemouth beat Chelsea 3-0 and Watford beat Chelsea 4-1, Assuming momentum before collision = momentum after collision and forces applied to a rigid body all act in the same plane, calculate the number of goals Barcelona will score against Chelsea. (Take g=9.8m/s2)​


According to the collision theory wen barca n Chelsea collide the intensity of the collision will be approximately 70-30 in possesion n 3-4 number of goals will be scored with reference to Barcelona ��

Given that g= 9.8m/s^2...{ let Chelsea be denoted as C, Bournemouth be denoted as B, and Watford is denoted by W}

3B+ 0C = 3......Eqn 1

4W + (-1) = 3...Eqn 2

The cumulative goal conceded is {3+3 =6}

Let cumulative be denoted as "a"
Therefore, if Barca denoted as Br

Squad strength of barca = a+1
Messi probability to score = a+1+1

Chelsea being a team of dog turds = a+1+1+1

Note a=6

Therefore, a+3 =6+3=9

9 goals.

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