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Pls Solve This Quantitative Reasoning Book 4 Exercise 2a / Pls Solve Thanks / Please Solve If You Can (2) (3) (4)
| Pls Solve If U Can. Thanks by shankeke: 5:37am On Mar 28, 2018 |
1) two men started from the same point and walked in opposite directions. each man walked for 50 minutes and turned left, walked for another 20 minutes and stopped. how far apart are they, if each man walked at the same rate of 6km/hr? |
| Re: Pls Solve If U Can. Thanks by dejt4u(m): 7:02am On Mar 28, 2018 |
shankeke:10.77km |
| Re: Pls Solve If U Can. Thanks by shankeke: 9:04am On Mar 28, 2018 |
dejt4u:Pls can u show the working.. thanks |
| Re: Pls Solve If U Can. Thanks by Sugar97(f): 9:19am On Mar 28, 2018 |
Both are a total of 140 minutes apart. That's (50 ×2) + (20×2). They have a common speed of 6km/h. The problem is to find distance (in km) when Time is 140 mins ( or 2 hrs. 20 mins) and speed is 6km/h. Distance = speed × time. Therefore, distance between them is 2 1/3 × 6, that's 7/3 × 6 = 14 km  |
| Re: Pls Solve If U Can. Thanks by Nobody: 9:21am On Mar 28, 2018 |
Sugar97: Hmnn. Guru |
| Re: Pls Solve If U Can. Thanks by Sugar97(f): 9:25am On Mar 28, 2018 |
| Re: Pls Solve If U Can. Thanks by Omuneizzy6(m): 9:31am On Mar 28, 2018 |
The answer has been given so thread closed. |
| Re: Pls Solve If U Can. Thanks by Nobody: 10:05am On Mar 28, 2018 |
Sugar97:I don't think you will like my 'confirmation' oh  |
| Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:12am On Mar 28, 2018 |
DanXplore: Lol. Well, if it's wrong, pls say it so I don't mislead someone |
| Re: Pls Solve If U Can. Thanks by Nobody: 10:13am On Mar 28, 2018 |
Sugar97: lol. detj4u is more correct |
| Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:16am On Mar 28, 2018 |
DanXplore: Lol. What does "more correct" mean? I thought it should be either correct or wrong |
| Re: Pls Solve If U Can. Thanks by Nobody: 10:18am On Mar 28, 2018 |
Sugar97: you will have two congruent right angled triangles in opposite direction but touching each other at the point of intersection of their respective hypothenus and adjacent (longest line). Their distance apart is twice the length of the hypothenus of one triangle 1 Like |
| Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:30am On Mar 28, 2018 |
DanXplore: I agree, I considered it as a possible solution. But then, the question doesn't ask for the shortest possible distance and that's why I ignored it |
| Re: Pls Solve If U Can. Thanks by Nobody: 10:33am On Mar 28, 2018 |
Sugar97: Lol. you think say u get sense abi? I agree with you 100% though |
| Re: Pls Solve If U Can. Thanks by Sugar97(f): 10:40am On Mar 28, 2018 |
DanXplore: Seriously, I considered both. I'm not trying to use sense  |
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